Unitary operator explained

In functional analysis, a unitary operator is a surjective bounded operator on a Hilbert space that preserves the inner product. Unitary operators are usually taken as operating on a Hilbert space, but the same notion serves to define the concept of isomorphism between Hilbert spaces.

Definition

Definition 1. A unitary operator is a bounded linear operator on a Hilbert space that satisfies, where is the adjoint of, and is the identity operator.

The weaker condition defines an isometry. The other condition,, defines a coisometry. Thus a unitary operator is a bounded linear operator that is both an isometry and a coisometry, or, equivalently, a surjective isometry.

An equivalent definition is the following:

Definition 2. A unitary operator is a bounded linear operator on a Hilbert space for which the following hold:

\langleUx,Uy\rangleH=\langlex,y\rangleH.

The notion of isomorphism in the category of Hilbert spaces is captured if domain and range are allowed to differ in this definition. Isometries preserve Cauchy sequences; hence the completeness property of Hilbert spaces is preserved

The following, seemingly weaker, definition is also equivalent:

Definition 3. A unitary operator is a bounded linear operator on a Hilbert space for which the following hold:

\langleUx,Uy\rangleH=\langlex,y\rangleH.

To see that definitions 1 and 3 are equivalent, notice that preserving the inner product implies is an isometry (thus, a bounded linear operator). The fact that has dense range ensures it has a bounded inverse . It is clear that .

Thus, unitary operators are just automorphisms of Hilbert spaces, i.e., they preserve the structure (the vector space structure, the inner product, and hence the topology) of the space on which they act. The group of all unitary operators from a given Hilbert space to itself is sometimes referred to as the Hilbert group of, denoted or .

Examples

Linearity

The linearity requirement in the definition of a unitary operator can be dropped without changing the meaning because it can be derived from linearity and positive-definiteness of the scalar product:

\begin{align} \|λU(x)-U(λx)\|2&=\langleλU(x)-U(λx),λU(x)-U(λx)\rangle\\[5pt] &=\|λU(x)\|2+\|U(λx)\|2-\langleU(λx),λU(x)\rangle-\langleλU(x),U(λx)\rangle\\[5pt] &=|λ|2\|U(x)\|2+\|U(λx)\|2-\overline{λ}\langleU(λx),U(x)\rangle-λ\langleU(x),U(λx)\rangle\\[5pt] &=|λ|2\|x\|2+\|λx\|2-\overline{λ}\langleλx,x\rangle-λ\langlex,λx\rangle\\[5pt] &=0 \end{align}

Analogously we obtain

\|U(x+y)-(Ux+Uy)\|=0.

Properties

References