Algebraic element explained
In mathematics, if is an extension field of, then an element of is called an algebraic element over, or just algebraic over, if there exists some non-zero polynomial with coefficients in such that . Elements of that are not algebraic over are called transcendental over .
These notions generalize the algebraic numbers and the transcendental numbers (where the field extension is, with being the field of complex numbers and being the field of rational numbers).
Examples
- The square root of 2 is algebraic over, since it is the root of the polynomial whose coefficients are rational.
- Pi is transcendental over but algebraic over the field of real numbers : it is the root of, whose coefficients (1 and −) are both real, but not of any polynomial with only rational coefficients. (The definition of the term transcendental number uses, not .)
Properties
The following conditions are equivalent for an element
of
:
is algebraic over
,
is algebraic, i.e.
every element of
is algebraic over
(here
denotes the smallest subfield of
containing
and
),
has finite degree, i.e. the
dimension of
as a
-
vector space is finite,
, where
is the set of all elements of
that can be written in the form
with a polynomial
whose coefficients lie in
.
\varepsilona:K[X] → K(a),P\mapstoP(a)
. This is a
homomorphism and its kernel is
. If
is algebraic, this ideal contains non-zero polynomials, but as
is a
euclidean domain, it contains a unique polynomial
with minimal degree and leading coefficient
, which then also generates the ideal and must be irreducible. The polynomial
is called the
minimal polynomial of
and it encodes many important properties of
. Hence the ring isomorphism
K[X]/(p) → im(\varepsilona)
obtained by the homomorphism theorem is an isomorphism of fields, where we can then observe that
. Otherwise,
is injective and hence we obtain a field isomorphism
, where
is the
field of fractions of
, i.e. the field of rational functions on
, by the universal property of the field of fractions. We can conclude that in any case, we find an isomorphism
or
. Investigating this construction yields the desired results.
This characterization can be used to show that the sum, difference, product and quotient of algebraic elements over
are again algebraic over
. For if
and
are both algebraic, then
is finite. As it contains the aforementioned combinations of
and
, adjoining one of them to
also yields a finite extension, and therefore these elements are algebraic as well. Thus set of all elements of
that are algebraic over
is a field that sits in between
and
.
Fields that do not allow any algebraic elements over them (except their own elements) are called algebraically closed. The field of complex numbers is an example. If
is algebraically closed, then the field of algebraic elements of
over
is algebraically closed, which can again be directly shown using the characterisation of simple algebraic extensions above. An example for this is the
field of algebraic numbers.
See also