Total ring of fractions explained
In abstract algebra, the total quotient ring or total ring of fractions is a construction that generalizes the notion of the field of fractions of an integral domain to commutative rings R that may have zero divisors. The construction embeds R in a larger ring, giving every non-zero-divisor of R an inverse in the larger ring. If the homomorphism from R to the new ring is to be injective, no further elements can be given an inverse.
Definition
Let
be a commutative ring and let
be the
set of elements that are not zero divisors in
; then
is a
multiplicatively closed set. Hence we may
localize the ring
at the set
to obtain the total quotient ring
.
If
is a
domain, then
and the total quotient ring is the same as the field of fractions. This justifies the notation
, which is sometimes used for the field of fractions as well, since there is no ambiguity in the case of a domain.
Since
in the construction contains no zero divisors, the natural map
is injective, so the total quotient ring is an extension of
.
Examples
, and so
. But since all these elements already have inverses,
.
- In a commutative von Neumann regular ring R, the same thing happens. Suppose a in R is not a zero divisor. Then in a von Neumann regular ring a = axa for some x in R, giving the equation a(xa − 1) = 0. Since a is not a zero divisor, xa = 1, showing a is a unit. Here again,
.
- In algebraic geometry one considers a sheaf of total quotient rings on a scheme, and this may be used to give the definition of a Cartier divisor.
The total ring of fractions of a reduced ring
Proof: Every element of Q(A) is either a unit or a zero divisor. Thus, any proper ideal I of Q(A) is contained in the set of zero divisors of Q(A); that set equals the union of the minimal prime ideals
since
Q(
A) is
reduced. By
prime avoidance,
I must be contained in some
. Hence, the ideals
are
maximal ideals of
Q(
A). Also, their
intersection is zero. Thus, by the Chinese remainder theorem applied to
Q(
A),
Q(A)\simeq\prodiQ(A)/ak{p}iQ(A)
.Let
S be the
multiplicatively closed set of non-zero-divisors of
A. By
exactness of localization,
Q(A)/ak{p}iQ(A)=A[S-1]/ak{p}iA[S-1]=(A/
]
,which is already a
field and so must be
.
Generalization
If
is a commutative ring and
is any
multiplicatively closed set in
, the
localization
can still be constructed, but the
ring homomorphism from
to
might fail to be injective. For example, if
, then
is the
trivial ring