Total ring of fractions explained

In abstract algebra, the total quotient ring or total ring of fractions is a construction that generalizes the notion of the field of fractions of an integral domain to commutative rings R that may have zero divisors. The construction embeds R in a larger ring, giving every non-zero-divisor of R an inverse in the larger ring. If the homomorphism from R to the new ring is to be injective, no further elements can be given an inverse.

Definition

Let

R

be a commutative ring and let

S

be the set of elements that are not zero divisors in

R

; then

S

is a multiplicatively closed set. Hence we may localize the ring

R

at the set

S

to obtain the total quotient ring

S-1R=Q(R)

.

If

R

is a domain, then

S=R-\{0\}

and the total quotient ring is the same as the field of fractions. This justifies the notation

Q(R)

, which is sometimes used for the field of fractions as well, since there is no ambiguity in the case of a domain.

Since

S

in the construction contains no zero divisors, the natural map

R\toQ(R)

is injective, so the total quotient ring is an extension of

R

.

Examples

R x

, and so

Q(R)=(R x )-1R

. But since all these elements already have inverses,

Q(R)=R

.

Q(R)=R

.

The total ring of fractions of a reduced ring

Proof: Every element of Q(A) is either a unit or a zero divisor. Thus, any proper ideal I of Q(A) is contained in the set of zero divisors of Q(A); that set equals the union of the minimal prime ideals

ak{p}iQ(A)

since Q(A) is reduced. By prime avoidance, I must be contained in some

ak{p}iQ(A)

. Hence, the ideals

ak{p}iQ(A)

are maximal ideals of Q(A). Also, their intersection is zero. Thus, by the Chinese remainder theorem applied to Q(A),

Q(A)\simeq\prodiQ(A)/ak{p}iQ(A)

.Let S be the multiplicatively closed set of non-zero-divisors of A. By exactness of localization,

Q(A)/ak{p}iQ(A)=A[S-1]/ak{p}iA[S-1]=(A/

-1
ak{p}
i)[S

]

,which is already a field and so must be

Q(A/ak{p}i)

.

\square

Generalization

If

R

is a commutative ring and

S

is any multiplicatively closed set in

R

, the localization

S-1R

can still be constructed, but the ring homomorphism from

R

to

S-1R

might fail to be injective. For example, if

0\inS

, then

S-1R

is the trivial ring