A thermodynamic cycle consists of linked sequences of thermodynamic processes that involve transfer of heat and work into and out of the system, while varying pressure, temperature, and other state variables within the system, and that eventually returns the system to its initial state.[1] In the process of passing through a cycle, the working fluid (system) may convert heat from a warm source into useful work, and dispose of the remaining heat to a cold sink, thereby acting as a heat engine. Conversely, the cycle may be reversed and use work to move heat from a cold source and transfer it to a warm sink thereby acting as a heat pump. If at every point in the cycle the system is in thermodynamic equilibrium, the cycle is reversible. Whether carried out reversible or irreversibly, the net entropy change of the system is zero, as entropy is a state function.
During a closed cycle, the system returns to its original thermodynamic state of temperature and pressure. Process quantities (or path quantities), such as heat and work are process dependent. For a cycle for which the system returns to its initial state the first law of thermodynamics applies:
\DeltaU=Ein-Eout=0
The above states that there is no change of the internal energy (
U
Ein
Eout
Two primary classes of thermodynamic cycles are power cycles and heat pump cycles. Power cycles are cycles which convert some heat input into a mechanical work output, while heat pump cycles transfer heat from low to high temperatures by using mechanical work as the input. Cycles composed entirely of quasistatic processes can operate as power or heat pump cycles by controlling the process direction. On a pressure–volume (PV) diagram or temperature–entropy diagram, the clockwise and counterclockwise directions indicate power and heat pump cycles, respectively.
Because the net variation in state properties during a thermodynamic cycle is zero, it forms a closed loop on a PV diagram. A PV diagram's Y axis shows pressure (P) and X axis shows volume (V). The area enclosed by the loop is the work (W) done by the process:
(1) W=\ointP dV
(2) W=Q=Qin-Qout
If the cyclic process moves clockwise around the loop, then W will be positive, and it represents a heat engine. If it moves counterclockwise, then W will be negative, and it represents a heat pump.
The following processes are often used to describe different stages of a thermodynamic cycle:
\deltaQ=0
\deltaT=0
\deltaP=0
\deltaV=0
\deltaS=0
pVn=C
dS-
dQ | |
T |
=0
The Otto Cycle is an example of a reversible thermodynamic cycle.
See main article: Heat engine. Thermodynamic power cycles are the basis for the operation of heat engines, which supply most of the world's electric power and run the vast majority of motor vehicles. Power cycles can be organized into two categories: real cycles and ideal cycles. Cycles encountered in real world devices (real cycles) are difficult to analyze because of the presence of complicating effects (friction), and the absence of sufficient time for the establishment of equilibrium conditions. For the purpose of analysis and design, idealized models (ideal cycles) are created; these ideal models allow engineers to study the effects of major parameters that dominate the cycle without having to spend significant time working out intricate details present in the real cycle model.
Power cycles can also be divided according to the type of heat engine they seek to model. The most common cycles used to model internal combustion engines are the Otto cycle, which models gasoline engines, and the Diesel cycle, which models diesel engines. Cycles that model external combustion engines include the Brayton cycle, which models gas turbines, the Rankine cycle, which models steam turbines, the Stirling cycle, which models hot air engines, and the Ericsson cycle, which also models hot air engines.
For example :--the pressure-volume mechanical work output from the ideal Stirling cycle (net work out), consisting of 4 thermodynamic processes, is:
(3) W\rm=W1\to+W2\to+W3\to+W4\to
W1\to=
V2 | |
\int | |
V1 |
PdV,negative,workdoneonsystem
W2\to=
V3 | |
\int | |
V2 |
PdV,zeroworksinceV2=V3
W3\to=
V4 | |
\int | |
V3 |
PdV,positive,workdonebysystem
W4\to=
V1 | |
\int | |
V4 |
PdV,zeroworksinceV4=V1
(4) W\rm=W1\to+W3\to
See main article: Heat pump and refrigeration cycle. Thermodynamic heat pump cycles are the models for household heat pumps and refrigerators. There is no difference between the two except the purpose of the refrigerator is to cool a very small space while the household heat pump is intended to warm or cool a house. Both work by moving heat from a cold space to a warm space. The most common refrigeration cycle is the vapor compression cycle, which models systems using refrigerants that change phase. The absorption refrigeration cycle is an alternative that absorbs the refrigerant in a liquid solution rather than evaporating it. Gas refrigeration cycles include the reversed Brayton cycle and the Hampson–Linde cycle. Multiple compression and expansion cycles allow gas refrigeration systems to liquify gases.
The difference between an idealized cycle and actual performance may be significant.[2] For example, the following images illustrate the differences in work output predicted by an ideal Stirling cycle and the actual performance of a Stirling engine:
As the net work output for a cycle is represented by the interior of the cycle, there is a significant difference between the predicted work output of the ideal cycle and the actual work output shown by a real engine. It may also be observed that the real individual processes diverge from their idealized counterparts; e.g., isochoric expansion (process 1-2) occurs with some actual volume change.
In practice, simple idealized thermodynamic cycles are usually made out of four thermodynamic processes. Any thermodynamic processes may be used. However, when idealized cycles are modeled, often processes where one state variable is kept constant, such as:
Some example thermodynamic cycles and their constituent processes are as follows:
An ideal cycle is simple to analyze and consists of:
If the working substance is a perfect gas,
U
T
a
b
\DeltaU=
b | |
\int | |
a |
CvdT
Assuming that
Cv
\DeltaU=Cv\DeltaT
Under this set of assumptions, for processes A and C we have
W=p\Deltav
Q=Cp\DeltaT
W=0
Q=\DeltaU=Cv\DeltaT
The total work done per cycle is
Wcycle=pA(v2-v1)+pC(v4-v3)=pA(v2-v1)+pC(v1-v2)=(pA-pC)(v2-v1)
\DeltaUcycle=Qcycle-Wcycle=0
Qcycle=Wcycle
Thus, the total heat flow per cycle is calculated without knowing the heat capacities and temperature changes for each step (although this information would be needed to assess the thermodynamic efficiency of the cycle).
See main article: Carnot cycle. The Carnot cycle is a cycle composed of the totally reversible processes of isentropic compression and expansion and isothermal heat addition and rejection. The thermal efficiency of a Carnot cycle depends only on the absolute temperatures of the two reservoirs in which heat transfer takes place, and for a power cycle is:
η=1- | TL |
TH |
{TL}
{TH}
COP=1+
TL | |
TH-TL |
COP=
TL | |
TH-TL |
See main article: Stirling cycle. A Stirling cycle is like an Otto cycle, except that the adiabats are replaced by isotherms. It is also the same as an Ericsson cycle with the isobaric processes substituted for constant volume processes.
Heat flows into the loop through the top isotherm and the left isochore, and some of this heat flows back out through the bottom isotherm and the right isochore, but most of the heat flow is through the pair of isotherms. This makes sense since all the work done by the cycle is done by the pair of isothermal processes, which are described by Q=W. This suggests that all the net heat comes in through the top isotherm. In fact, all of the heat which comes in through the left isochore comes out through the right isochore: since the top isotherm is all at the same warmer temperature
TH
TC
If Z is a state function then the balance of Z remains unchanged during a cyclic process:
\ointdZ=0
Entropy is a state function and is defined in an absolute sense through the Third Law of Thermodynamics as
S=
T | |
\int | |
0 |
{dQrev\overT}
\DeltaS={Qrev\overT}
\ointdS=\oint{dQrev\overT}=0