Solid of revolution explained

In geometry, a solid of revolution is a solid figure obtained by rotating a plane figure around some straight line (the axis of revolution), which may not intersect the generatrix (except at its boundary). The surface created by this revolution and which bounds the solid is the surface of revolution.

Assuming that the curve does not cross the axis, the solid's volume is equal to the length of the circle described by the figure's centroid multiplied by the figure's area (Pappus's second centroid theorem).

A representative disc is a three-dimensional volume element of a solid of revolution. The element is created by rotating a line segment (of length) around some axis (located units away), so that a cylindrical volume of units is enclosed.

Finding the volume

Two common methods for finding the volume of a solid of revolution are the disc method and the shell method of integration. To apply these methods, it is easiest to draw the graph in question; identify the area that is to be revolved about the axis of revolution; determine the volume of either a disc-shaped slice of the solid, with thickness, or a cylindrical shell of width ; and then find the limiting sum of these volumes as approaches 0, a value which may be found by evaluating a suitable integral. A more rigorous justification can be given by attempting to evaluate a triple integral in cylindrical coordinates with two different orders of integration.

Disc method

See main article: Disc integration.

The disc method is used when the slice that was drawn is perpendicular to the axis of revolution; i.e. when integrating parallel to the axis of revolution.

The volume of the solid formed by rotating the area between the curves of and and the lines and about the -axis is given byV = \pi \int_a^b \left| f(y)^2 - g(y)^2\right|\,dy\, .If (e.g. revolving an area between the curve and the -axis), this reduces to:V = \pi \int_a^b f(y)^2 \,dy\, .

The method can be visualized by considering a thin horizontal rectangle at between on top and on the bottom, and revolving it about the -axis; it forms a ring (or disc in the case that), with outer radius and inner radius . The area of a ring is, where is the outer radius (in this case), and is the inner radius (in this case). The volume of each infinitesimal disc is therefore . The limit of the Riemann sum of the volumes of the discs between and becomes integral (1).

Assuming the applicability of Fubini's theorem and the multivariate change of variables formula, the disk method may be derived in a straightforward manner by (denoting the solid as D):V = \iiint_D dV = \int_a^b \int_^ \int_0^ r\,d\theta\,dr\,dz = 2\pi \int_a^b\int_^ r\,dr\,dz = 2\pi \int_a^b \fracr^2\Vert^_ \,dz = \pi \int_a^b (f(z)^2 - g(z)^2)\,dz

Shell Method of Integration

See main article: Shell integration.

The shell method (sometimes referred to as the "cylinder method") is used when the slice that was drawn is parallel to the axis of revolution; i.e. when integrating perpendicular to the axis of revolution.

The volume of the solid formed by rotating the area between the curves of and and the lines and about the -axis is given byV = 2\pi \int_a^b x |f(x) - g(x)|\, dx\, .If (e.g. revolving an area between curve and -axis), this reduces to:V = 2\pi \int_a^b x | f(x) | \,dx\, .

The method can be visualized by considering a thin vertical rectangle at with height, and revolving it about the -axis; it forms a cylindrical shell. The lateral surface area of a cylinder is, where is the radius (in this case), and is the height (in this case). Summing up all of the surface areas along the interval gives the total volume.

This method may be derived with the same triple integral, this time with a different order of integration:V = \iiint_D dV = \int_a^b \int_^ \int_0^ r\,d\theta\,dz\,dr = 2\pi \int_a^b\int_^ r\,dz\,dr = 2\pi\int_a^b r(f(r) - g(r))\,dr.

Parametric form

When a curve is defined by its parametric form in some interval, the volumes of the solids generated by revolving the curve around the -axis or the -axis are given by[1] \beginV_x &= \int_a^b \pi y^2 \, \frac \, dt \,, \\V_y &= \int_a^b \pi x^2 \, \frac \, dt \, .\end

Under the same circumstances the areas of the surfaces of the solids generated by revolving the curve around the -axis or the -axis are given by[2] \beginA_x &= \int_a^b 2 \pi y \, \sqrt \, dt \,, \\A_y &= \int_a^b 2 \pi x \, \sqrt \, dt \, .\end

This can also be derived from multivariable integration. If a plane curve is given by

\langlex(t),y(t)\rangle

then its corresponding surface of revolution when revolved around the x-axis has Cartesian coordinates given by

r(t,\theta)=\langley(t)\cos(\theta),y(t)\sin(\theta),x(t)\rangle

with

0\leq\theta\leq2\pi

. Then the surface area is given by the surface integral A_x = \iint_S dS = \iint_ \left\|\frac \times \frac\right\|\ d\theta\ dt = \int_a^b \int_0^ \left\|\frac \times \frac\right\|\ d\theta\ dt.

Computing the partial derivatives yields\frac = \left\langle \frac \cos(\theta), \frac \sin(\theta), \frac \right\rangle,\frac = \left\langle -y \sin(\theta), y \cos(\theta), 0 \right\rangleand computing the cross product yields \frac \times \frac = \left\langle y \cos(\theta)\frac, y \sin(\theta)\frac, y \frac \right\rangle = y \left\langle \cos(\theta)\frac, \sin(\theta)\frac, \frac \right\rangle where the trigonometric identity

\sin2(\theta)+\cos2(\theta)=1

was used. With this cross product, we get\beginA_x&= \int_a^b \int_0^ \left\|\frac \times \frac\right\|\ d\theta\ dt \\[1ex]&= \int_a^b \int_0^ \left\|y \left\langle y \cos(\theta)\frac, y \sin(\theta)\frac, y \frac \right\rangle\right\|\ d\theta\ dt \\[1ex]&= \int_a^b \int_0^ y \sqrt\ d\theta\ dt \\[1ex]&= \int_a^b \int_0^ y \sqrt\ d\theta\ dt \\[1ex]&= \int_a^b 2\pi y \sqrt\ dt\endwhere the same trigonometric identity was used again. The derivation for a surface obtained by revolving around the y-axis is similar.

Polar form

For a polar curve

r=f(\theta)

where

\alpha\leq\theta\leq\beta

and

f(\theta)\geq0

, the volumes of the solids generated by revolving the curve around the x-axis or y-axis are\beginV_x &= \int_\alpha^\beta \left(\pi r^2\sin^2 \cos\, \frac-\pi r^3\sin^3\right)d\theta\,, \\V_y &= \int_\alpha^\beta \left(\pi r^2\sin \cos^2\, \frac+\pi r^3\cos^3\right)d\theta \, .\end

The areas of the surfaces of the solids generated by revolving the curve around the -axis or the -axis are given\beginA_x &= \int_\alpha^\beta 2 \pi r\sin \, \sqrt \, d\theta \,, \\A_y &= \int_\alpha^\beta 2 \pi r\cos \, \sqrt \, d\theta \,,\end

See also

References

Notes and References

  1. Book: Sharma , A. K. . Application Of Integral Calculus. Discovery Publishing House. 2005. 81-7141-967-4. 168.
  2. Book: Singh , Ravish R. . Engineering Mathematics. 6th. Tata McGraw-Hill. 1993. 0-07-014615-2. 6.90.