The six-rays model is applied in an urban or indoor environment where a radio signal transmitted will encounter some objects that produce reflected, refracted or scattered copies of the transmitted signal. These are called multipath signal components, they are attenuated, delayed and shifted from the original signal (LOS) due to a finite number of reflectors with known location and dielectric properties, LOS and multipath signal are summed at the receiver.
This model approach the propagation of electromagnetic waves by representing wavefront as simple particles. Thus reflection, refraction and scattering effects are approximated using simple geometric equation instead Maxwell's wave equations.[1]
The simplest model is two-rays which predicts signal variation resulting from a ground reflection interfering with the loss path. This model is applicable in isolated areas with some reflectors, such as rural roads or hallway.
The above two-rays approach can easily be extended to add as many rays as required. We may add rays bouncing off each side of a street in an urban corridor, leading to a six-rays model. The deduction of the six-rays model is presented below.
For the analysis of antennas with equal heights then
ht=hr=h
h
d'
Being located in the center of the street the distance between the antennas
TX
RX
wt1=wr1=wt2=wr2
w
The mathematical model of propagation of six rays is based on the model of two rays, to find the equations of each ray involved. The distance
d
R0
R0=d
For the ray reflected under
R0
R0
R0'=\sqrt{d2+(2*h)2
For
R1
w
R1=\sqrt{d2+(2*w)2
For
R1
d1
R1
d
R1'=2*\sqrt{\left(
R1 | |
2 |
\right)2+(2h)2
For
R1
R2
R2=R1
R2'=R1'
As the direct ray LOS does not vary and has not angular variation between the rays, the distance of the first two rays
R0
' | |
R | |
0 |
R1
wt1
wr1
wt2
wr2
R1=\sqrt{d2-(wt1-wr2)2+(wt1+wt2-wr2)2
For likeness of triangles in the top view for model is determined the equation
R1
d'=\sqrt{d2-(wt1-wr2)2
x= | (wr2*R1) |
wr2+wt2+wt1-wr2 |
R1'=\sqrt{(R1-x2)+(2*h2)}+\sqrt{(x)2+(2*h)2
For
R1
R2
R2=R1
R2'=R1'
For antennas of different heights with rays that rebound in the wall, it is noted that the wall is the half point, where the two transmitted rays they fall on such wall. This wall has half the height between the height of the
TX
RX
TX
RX
a
d-a
For the mathematical model of six-ray propagation for antennas of different heights located at any point in the street,
ht ≠ hr
d
R0=\sqrt{d2+(ht-h
2 | |
r) |
The second ray or reflected ray is calculated as the first ray but the heights of the antennas are added to form the right triangle.
R0'=\sqrt{d2+(ht+h
2 | |
r) |
For deducing the third ray it is calculated the angle between the direct distance
d
R0
\cos\theta= | ht-hr |
R0 |
Now deducing the height that subtraction of the wall with respect the height of the receiver called
z
z | = | |
a |
ht | |
d' |
z= | ht*~a |
d' |
By similarity of triangles it can deduce the distance where the ray hits the wall until the perpendicular of the receiver called a achieved:
a | = | |
wt2 |
d' | |
wt1+wr1 |
a= | d'*wt2 |
\left(wt1+wr1\right) |
R1=
| |||||||||||||
+\sqrt{z |
2+a2
By similarity of the triangles can be deduced the equation of the fourth ray:
R1'=
| |||||||||||||
+\sqrt{(2h |
2 | |
r+z) |
+a2
For
R1
R2
R2=R1
R2'=R1'
Consider a transmitted signal in the free space a receptor located a distance d of the transmitter. One may add rays bouncing off each side of a street in an urban corridor, leading to a six-rays model, with rays
R0
R1
R2
An important assumption must be made to simplify the model:
T
s(t)=s(t-T)
T
Free-space path loss of six rays model is defined as:
p0(t)=\sqrt{(GiG
\left( | |||||
|
\exp(j*2\pi*R0/{λ | |
)}{R |
0
p1(t)=\sqrt{(GiG
|
~\Gamma1\left(
\exp(j*2\pi*R1/{λ | |
)}{R |
1
p2(t)=\sqrt{(GiG
|
~\Gamma1\left(
\exp(j*2\pi*R2/{λ | |
)}{R |
2
Pl~(dB)=20log\left|~\sum
N | |
i=0 |
Pi~\right|
{λ}=
{c\overf}
T=
\Gamma=
Gi=
Gr=