\R3
By definition, a rotation about the origin is a transformation that preserves the origin, Euclidean distance (so it is an isometry), and orientation (i.e., handedness of space). Composing two rotations results in another rotation, every rotation has a unique inverse rotation, and the identity map satisfies the definition of a rotation. Owing to the above properties (along composite rotations' associative property), the set of all rotations is a group under composition.
Every non-trivial rotation is determined by its axis of rotation (a line through the origin) and its angle of rotation. Rotations are not commutative (for example, rotating R 90° in the x-y plane followed by S 90° in the y-z plane is not the same as S followed by R), making the 3D rotation group a nonabelian group. Moreover, the rotation group has a natural structure as a manifold for which the group operations are smoothly differentiable, so it is in fact a Lie group. It is compact and has dimension 3.
Rotations are linear transformations of
\R3
\R3
\R3
The group SO(3) is used to describe the possible rotational symmetries of an object, as well as the possible orientations of an object in space. Its representations are important in physics, where they give rise to the elementary particles of integer spin.
Besides just preserving length, rotations also preserve the angles between vectors. This follows from the fact that the standard dot product between two vectors u and v can be written purely in terms of length (see the law of cosines):
It follows that every length-preserving linear transformation in
\R3
\R3
See main article: Orthogonal matrix and Rotation matrix.
Every rotation maps an orthonormal basis of
\R3
\R3
RTR=RRT=I,
where denotes the transpose of and is the identity matrix. Matrices for which this property holds are called orthogonal matrices. The group of all orthogonal matrices is denoted, and consists of all proper and improper rotations.
In addition to preserving length, proper rotations must also preserve orientation. A matrix will preserve or reverse orientation according to whether the determinant of the matrix is positive or negative. For an orthogonal matrix, note that implies, so that . The subgroup of orthogonal matrices with determinant is called the special orthogonal group, denoted .
Thus every rotation can be represented uniquely by an orthogonal matrix with unit determinant. Moreover, since composition of rotations corresponds to matrix multiplication, the rotation group is isomorphic to the special orthogonal group .
Improper rotations correspond to orthogonal matrices with determinant, and they do not form a group because the product of two improper rotations is a proper rotation.
\R3
Furthermore, the rotation group is nonabelian. That is, the order in which rotations are composed makes a difference. For example, a quarter turn around the positive x-axis followed by a quarter turn around the positive y-axis is a different rotation than the one obtained by first rotating around y and then x.
The orthogonal group, consisting of all proper and improper rotations, is generated by reflections. Every proper rotation is the composition of two reflections, a special case of the Cartan–Dieudonné theorem.
The finite subgroups of
SO(3)
Every finite subgroup is isomorphic to either an element of one of two countably infinite families of planar isometries: the cyclic groups
Cn
D2n
\congA4
\congS4
\congA5
See main article: Axis–angle representation. Every nontrivial proper rotation in 3 dimensions fixes a unique 1-dimensional linear subspace of
\R3
For example, counterclockwise rotation about the positive z-axis by angle φ is given by
Rz(\phi)=\begin{bmatrix}\cos\phi&-\sin\phi&0\ \sin\phi&\cos\phi&0\ 0&0&1\end{bmatrix}.
Given a unit vector n in
\R3
Using these properties one can show that any rotation can be represented by a unique angle φ in the range 0 ≤ φ ≤ and a unit vector n such that
In the next section, this representation of rotations is used to identify SO(3) topologically with three-dimensional real projective space.
P3(\R).
Consider the solid ball in
\R3
\R3
P3(\R),
These identifications illustrate that SO(3) is connected but not simply connected. As to the latter, in the ball with antipodal surface points identified, consider the path running from the "north pole" straight through the interior down to the south pole. This is a closed loop, since the north pole and the south pole are identified. This loop cannot be shrunk to a point, since no matter how it is deformed, the start and end point have to remain antipodal, or else the loop will "break open". In terms of rotations, this loop represents a continuous sequence of rotations about the z-axis starting (by example) at the identity (center of the ball), through the south pole, jumping to the north pole and ending again at the identity rotation (i.e., a series of rotation through an angle φ where φ runs from 0 to 2).
Surprisingly, running through the path twice, i.e., running from the north pole down to the south pole, jumping back to the north pole (using the fact that north and south poles are identified), and then again running from the north pole down to the south pole, so that φ runs from 0 to 4, gives a closed loop which can be shrunk to a single point: first move the paths continuously to the ball's surface, still connecting north pole to south pole twice. The second path can then be mirrored over to the antipodal side without changing the path at all. Now we have an ordinary closed loop on the surface of the ball, connecting the north pole to itself along a great circle. This circle can be shrunk to the north pole without problems. The plate trick and similar tricks demonstrate this practically.
The same argument can be performed in general, and it shows that the fundamental group of SO(3) is the cyclic group of order 2 (a fundamental group with two elements). In physics applications, the non-triviality (more than one element) of the fundamental group allows for the existence of objects known as spinors, and is an important tool in the development of the spin–statistics theorem.
The universal cover of SO(3) is a Lie group called Spin(3). The group Spin(3) is isomorphic to the special unitary group SU(2); it is also diffeomorphic to the unit 3-sphere S3 and can be understood as the group of versors (quaternions with absolute value 1). The connection between quaternions and rotations, commonly exploited in computer graphics, is explained in quaternions and spatial rotations. The map from S3 onto SO(3) that identifies antipodal points of S3 is a surjective homomorphism of Lie groups, with kernel . Topologically, this map is a two-to-one covering map. (See the plate trick.)
In this section, we give two different constructions of a two-to-one and surjective homomorphism of SU(2) onto SO(3).
See main article: Quaternions and spatial rotation. The group is isomorphic to the quaternions of unit norm via a map given by[5] restricted to where , , , and
\alpha=a+bi\inC
\beta=c+di\inC
Let us now identify
\R3
i,j,k
v
\R3
q
Furthermore, the map
v\mapstoqvq-1
\R3.
(-q)v(-q)-1
qvq-1
One can work this homomorphism out explicitly: the unit quaternion,, withis mapped to the rotation matrix
This is a rotation around the vector by an angle, where and . The proper sign for is implied, once the signs of the axis components are fixed. The is apparent since both and map to the same .
The general reference for this section is . The points on the sphere
S=\left\{(x,y,z)\in\R3:x2+y2+z2=
1 | |
4 |
\right\}
can, barring the north pole, be put into one-to-one bijection with points on the plane defined by, see figure. The map is called stereographic projection.
Let the coordinates on be . The line passing through and can be parametrized as
L(t)=N+t(N-P)=\left(0,0,
1 | |
2 |
\right)+t\left(\left(0,0,
1 | |
2 |
\right)-(x,y,z)\right), t\in\R.
Demanding that the of
L(t0)
t0=
| ||||
We have
L(t0)=(\xi,η,-1/2).
\begin{cases}S:S\toM\ P=(x,y,z)\longmapstoP'=(\xi,η)=\left(
x | ||||
|
,
y | ||||
|
\right)\equiv\zeta=\xi+iη\end{cases}
where, for later convenience, the plane is identified with the complex plane
\Complex.
For the inverse, write as
L=N+s(P'-N)=\left(0,0,
1 | |
2 |
\right)+s\left(\left(\xi,η,-
1 | |
2 |
\right)-\left(0,0,
1 | |
2 |
\right)\right),
and demand to find and thus
\begin{cases}S-1:M\toS\ P'=(\xi,η)\longmapstoP=(x,y,z)=\left(
\xi | |
1+\xi2+η2 |
,
η | |
1+\xi2+η2 |
,
-1+\xi2+η2 | |
2+2\xi2+2η2 |
\right)\end{cases}
If is a rotation, then it will take points on to points on by its standard action on the embedding space
\R3.
\zeta=P'\longmapstoP\longmapsto\Pis(g)P=gP\longmapstoS(gP)\equiv\Piu(g)\zeta=\zeta'.
Thus is a transformation of
\Complex
\R3
It turns out that represented in this way by can be expressed as a matrix (where the notation is recycled to use the same name for the matrix as for the transformation of
\Complex
\begin{align} x'&=x\cos\phi-y\sin\phi,\\ y'&=x\sin\phi+y\cos\phi,\\ z'&=z. \end{align}
Hence
\zeta'=
x'+iy' | ||||
|
=
ei\phi(x+iy) | ||||
|
=ei\phi\zeta=
| ||||||||||
|
,
which, unsurprisingly, is a rotation in the complex plane. In an analogous way, if is a rotation about the through an angle, then
w'=ei\thetaw, w=
y+iz | ||||
|
,
which, after a little algebra, becomes
\zeta'=
| |||||||||
|
.
These two rotations,
g\phi,g\theta,
A general Möbius transformation is given by
\zeta'=
\alpha\zeta+\beta | |
\gamma\zeta+\delta |
, \alpha\delta-\beta\gamma\ne0.
The rotations,
g\phi,g\theta
g\phi,g\theta
\begin{pmatrix}\alpha&\beta\ \gamma&\delta\end{pmatrix}, \alpha\delta-\beta\gamma=1,
since a common factor of cancels.
For the same reason, the matrix is not uniquely defined since multiplication by has no effect on either the determinant or the Möbius transformation. The composition law of Möbius transformations follow that of the corresponding matrices. The conclusion is that each Möbius transformation corresponds to two matrices .
Using this correspondence one may write
\begin{align} \Piu(g\phi)&=\Piu\left[\begin{pmatrix} \cos\phi&-\sin\phi&0\\ \sin\phi&\cos\phi&0\\ 0&0&1 \end{pmatrix}\right]=
| ||||
\pm \begin{pmatrix} e |
&0\\ 0&
| ||||
e |
\end{pmatrix},\\ \Piu(g\theta)&=\Piu\left[\begin{pmatrix} 1&0&0\\ 0&\cos\theta&-\sin\theta\\ 0&\sin\theta&\cos\theta \end{pmatrix}\right]=\pm \begin{pmatrix} \cos
\theta | |
2 |
&i\sin
\theta | \\ i\sin | |
2 |
\theta | |
2 |
&\cos
\theta | |
2 |
\end{pmatrix}. \end{align}
These matrices are unitary and thus . In terms of Euler angles[6] one finds for a general rotation
one has[7]
For the converse, consider a general matrix
\pm\Piu(g\alpha,\beta)=\pm\begin{pmatrix}\alpha&\beta\ -\overline{\beta}&\overline{\alpha}\end{pmatrix}\in\operatorname{SU}(2).
Make the substitutions
\begin{align} \cos
\theta | |
2 |
&=|\alpha|,&\sin
\theta | |
2 |
&=|\beta|,&(0\le\theta\le\pi),\\
\phi+\psi | |
2 |
&=\arg\alpha,&
\psi-\phi | |
2 |
&=\arg\beta.& \end{align}
With the substitutions, assumes the form of the right hand side (RHS) of, which corresponds under to a matrix on the form of the RHS of with the same . In terms of the complex parameters,
g\alpha,\beta=\begin{pmatrix}
1 | |
2 |
\left(\alpha2-\beta2+\overline{\alpha2}-\overline{\beta2}\right)&
i | |
2 |
\left(-\alpha2-\beta2+\overline{\alpha2}+\overline{\beta2}\right)& -\alpha\beta-\overline{\alpha}\overline{\beta}\\
i | |
2 |
\left(\alpha2-\beta2-\overline{\alpha2}+\overline{\beta2}\right)&
1 | |
2 |
\left(\alpha2+\beta2+\overline{\alpha2}+\overline{\beta2}\right)& -i\left(+\alpha\beta-\overline{\alpha}\overline{\beta}\right)\\ \alpha\overline{\beta}+\overline{\alpha}\beta& i\left(-\alpha\overline{\beta}+\overline{\alpha}\beta\right)& \alpha\overline{\alpha}-\beta\overline{\beta} \end{pmatrix}.
To verify this, substitute for the elements of the matrix on the RHS of . After some manipulation, the matrix assumes the form of the RHS of .
It is clear from the explicit form in terms of Euler angles that the map
\begin{cases} p:\operatorname{SU}(2)\to\operatorname{SO}(3)\\ \pm\Piu(g\alpha)\mapstog\alpha\end{cases}
just described is a smooth, and surjective group homomorphism. It is hence an explicit description of the universal covering space of from the universal covering group .
Associated with every Lie group is its Lie algebra, a linear space of the same dimension as the Lie group, closed under a bilinear alternating product called the Lie bracket. The Lie algebra of is denoted by
ak{so}(3)
ak{so}(3)
The elements of
ak{so}(3)
R(\phi,\boldsymbol{n})
\boldsymbol{n},
\forall\boldsymbol{u}\in\R3: \left.
\operatorname{d | |
This can be used to show that the Lie algebra
ak{so}(3)
\R3
\boldsymbol{\omega}\in\R3
\widetilde{\boldsymbol{\omega}}
\widetilde{\boldsymbol{\omega}}(\boldsymbol{u})=\boldsymbol{\omega} x \boldsymbol{u}.
In more detail, most often a suitable basis for
ak{so}(3)
\boldsymbol{L}x=\begin{bmatrix}0&0&0\\0&0&-1\\0&1&0\end{bmatrix}, \boldsymbol{L}y=\begin{bmatrix}0&0&1\\0&0&0\\-1&0&0\end{bmatrix}, \boldsymbol{L}z=\begin{bmatrix}0&-1&0\\1&0&0\\0&0&0\end{bmatrix}.
The commutation relations of these basis elements are,
[\boldsymbol{L}x,\boldsymbol{L}y]=\boldsymbol{L}z, [\boldsymbol{L}z,\boldsymbol{L}x]=\boldsymbol{L}y, [\boldsymbol{L}y,\boldsymbol{L}z]=\boldsymbol{L}x
which agree with the relations of the three standard unit vectors of
\R3
As announced above, one can identify any matrix in this Lie algebra with an Euler vector
\boldsymbol{\omega}=(x,y,z)\in\R3,
\widehat{\boldsymbol{\omega}}=\boldsymbol{\omega} ⋅ \boldsymbol{L}=x\boldsymbol{L}x+y\boldsymbol{L}y+z\boldsymbol{L}z=\begin{bmatrix}0&-z&y\\z&0&-x\\-y&x&0\end{bmatrix}\inak{so}(3).
This identification is sometimes called the hat-map. Under this identification, the
ak{so}(3)
\R3
\left[\widehat{\boldsymbol{u}},\widehat{\boldsymbol{v}}\right]=\widehat{\boldsymbol{u} x \boldsymbol{v}}.
The matrix identified with a vector
\boldsymbol{u}
\widehat{\boldsymbol{u}}\boldsymbol{v}=\boldsymbol{u} x \boldsymbol{v},
where the left-hand side we have ordinary matrix multiplication. This implies
\boldsymbol{u}
\boldsymbol{u} x \boldsymbol{u}=\boldsymbol{0}.
See main article: Angular momentum operator.
See also: Representation theory of SU(2) and Jordan map.
In Lie algebra representations, the group SO(3) is compact and simple of rank 1, and so it has a single independent Casimir element, a quadratic invariant function of the three generators which commutes with all of them. The Killing form for the rotation group is just the Kronecker delta, and so this Casimir invariant is simply the sum of the squares of the generators,
\boldsymbol{J}x,\boldsymbol{J}y,\boldsymbol{J}z,
[\boldsymbol{J}x,\boldsymbol{J}y]=\boldsymbol{J}z, [\boldsymbol{J}z,\boldsymbol{J}x]=\boldsymbol{J}y, [\boldsymbol{J}y,\boldsymbol{J}z]=\boldsymbol{J}x.
\boldsymbol{J}2\equiv\boldsymbol{J} ⋅ \boldsymbol{J}
2 | |
=\boldsymbol{J} | |
z |
\propto\boldsymbol{I}.
For unitary irreducible representations, the eigenvalues of this invariant are real and discrete, and characterize each representation, which is finite dimensional, of dimensionality
2j+1
\boldsymbol{J}2=-j(j+1)\boldsymbol{I}2j+1,
So, the 3 × 3 generators L displayed above act on the triplet (spin 1) representation, while the 2 × 2 generators below, t, act on the doublet (spin-1/2) representation. By taking Kronecker products of with itself repeatedly, one may construct all higher irreducible representations . That is, the resulting generators for higher spin systems in three spatial dimensions, for arbitrarily large, can be calculated using these spin operators and ladder operators.
For every unitary irreducible representations there is an equivalent one, . All infinite-dimensional irreducible representations must be non-unitary, since the group is compact.
In quantum mechanics, the Casimir invariant is the "angular-momentum-squared" operator; integer values of spin characterize bosonic representations, while half-integer values fermionic representations. The antihermitian matrices used above are utilized as spin operators, after they are multiplied by, so they are now hermitian (like the Pauli matrices). Thus, in this language,
[\boldsymbol{J}x,\boldsymbol{J}y]=i\boldsymbol{J}z, [\boldsymbol{J}z,\boldsymbol{J}x]=i\boldsymbol{J}y, [\boldsymbol{J}y,\boldsymbol{J}z]=i\boldsymbol{J}x.
\boldsymbol{J}2=j(j+1)\boldsymbol{I}2j+1.
Explicit expressions for these are,
\begin{align}\left
(j) | |
(\boldsymbol{J} | |
z |
\right)ba&=(j+1-a)\deltab,a\\ \left
(j) | |
(\boldsymbol{J} | |
x |
\right)ba&=
1 | |
2 |
\left(\deltab,a+1+\deltab+1,a\right)\sqrt{(j+1)(a+b-1)-ab}\\ \left
(j) | |
(\boldsymbol{J} | |
y |
\right)ba&=
1 | |
2i |
\left(\deltab,a+1-\deltab+1,a\right)\sqrt{(j+1)(a+b-1)-ab}\\ \end{align}
1\lea,b\le2j+1
For example, the resulting spin matrices for spin 1 (
j=1
\begin{align} \boldsymbol{J}x&=
1 | |
\sqrt{2 |
Note, however, how these are in an equivalent, but different basis, the spherical basis, than the above L in the Cartesian basis.[10]
For higher spins, such as spin (
j=\tfrac{3}{2}
\begin{align} \boldsymbol{J}x&=
1 | |
2 |
\begin{pmatrix} 0&\sqrt{3}&0&0\\ \sqrt{3}&0&2&0\\ 0&2&0&\sqrt{3}\\ 0&0&\sqrt{3}&0 \end{pmatrix}\\ \boldsymbol{J}y&=
1 | |
2 |
\begin{pmatrix} 0&-i\sqrt{3}&0&0\\ i\sqrt{3}&0&-2i&0\\ 0&2i&0&-i\sqrt{3}\\ 0&0&i\sqrt{3}&0 \end{pmatrix}\\ \boldsymbol{J}z&=
1 | |
2 |
\begin{pmatrix} 3&0&0&0\\ 0&1&0&0\\ 0&0&-1&0\\ 0&0&0&-3 \end{pmatrix}. \end{align}
For spin (
j=\tfrac{5}{2}
\begin{align} \boldsymbol{J}x&=
1 | |
2 |
\begin{pmatrix} 0&\sqrt{5}&0&0&0&0\\ \sqrt{5}&0&2\sqrt{2}&0&0&0\\ 0&2\sqrt{2}&0&3&0&0\\ 0&0&3&0&2\sqrt{2}&0\\ 0&0&0&2\sqrt{2}&0&\sqrt{5}\\ 0&0&0&0&\sqrt{5}&0 \end{pmatrix}\\ \boldsymbol{J}y&=
1 | |
2 |
\begin{pmatrix} 0&-i\sqrt{5}&0&0&0&0\\ i\sqrt{5}&0&-2i\sqrt{2}&0&0&0\\ 0&2i\sqrt{2}&0&-3i&0&0\\ 0&0&3i&0&-2i\sqrt{2}&0\\ 0&0&0&2i\sqrt{2}&0&-i\sqrt{5}\\ 0&0&0&0&i\sqrt{5}&0 \end{pmatrix}\\ \boldsymbol{J}z&=
1 | |
2 |
\begin{pmatrix} 5&0&0&0&0&0\\ 0&3&0&0&0&0\\ 0&0&1&0&0&0\\ 0&0&0&-1&0&0\\ 0&0&0&0&-3&0\\ 0&0&0&0&0&-5 \end{pmatrix}. \end{align}
The Lie algebras
ak{so}(3)
ak{su}(2)
ak{su}(2)
\boldsymbol{t}1=
1 | |
2 |
\begin{bmatrix}0&-i\ -i&0\end{bmatrix}, \boldsymbol{t}2=
1 | |
2 |
\begin{bmatrix}0&-1\ 1&0\end{bmatrix}, \boldsymbol{t}3=
1 | |
2 |
\begin{bmatrix}-i&0\ 0&i\end{bmatrix}.
These are related to the Pauli matrices by
\boldsymbol{t}i\longleftrightarrow
1 | |
2i |
\sigmai.
The Pauli matrices abide by the physicists' convention for Lie algebras. In that convention, Lie algebra elements are multiplied by, the exponential map (below) is defined with an extra factor of in the exponent and the structure constants remain the same, but the definition of them acquires a factor of . Likewise, commutation relations acquire a factor of . The commutation relations for the
\boldsymbol{t}i
[\boldsymbol{t}i,\boldsymbol{t}j]=\varepsilonijk\boldsymbol{t}k,
where is the totally anti-symmetric symbol with . The isomorphism between
ak{so}(3)
ak{su}(2)
ak{so}(3)
ak{su}(2)
\boldsymbol{L}x\longleftrightarrow\boldsymbol{t}1, \boldsymbol{L}y\longleftrightarrow\boldsymbol{t}2, \boldsymbol{L}z\longleftrightarrow\boldsymbol{t}3,
and extending by linearity.
The exponential map for, is, since is a matrix Lie group, defined using the standard matrix exponential series,
\begin{cases} \exp:ak{so}(3)\to\operatorname{SO}(3)\\ A\mapstoeA=
infty | |
\sum | |
k=0 |
1 | |
k! |
Ak =I+A+\tfrac{1}{2}A2+ … . \end{cases}
For any skew-symmetric matrix, is always in . The proof uses the elementary properties of the matrix exponential
\left(eA\right)sf{T}eA=
Asf{T | |
e |
since the matrices and commute, this can be easily proven with the skew-symmetric matrix condition. This is not enough to show that is the corresponding Lie algebra for, and shall be proven separately.
The level of difficulty of proof depends on how a matrix group Lie algebra is defined. defines the Lie algebra as the set of matrices
\left\{A\in\operatorname{M}(n,\R)\left|etA\in\operatorname{SO}(3)\forallt\right.\right\},
in which case it is trivial. uses for a definition derivatives of smooth curve segments in through the identity taken at the identity, in which case it is harder.[12]
For a fixed, is a one-parameter subgroup along a geodesic in . That this gives a one-parameter subgroup follows directly from properties of the exponential map.[13]
The exponential map provides a diffeomorphism between a neighborhood of the origin in the and a neighborhood of the identity in the .[14] For a proof, see Closed subgroup theorem.
The exponential map is surjective. This follows from the fact that every, since every rotation leaves an axis fixed (Euler's rotation theorem), and is conjugate to a block diagonal matrix of the form
D=\begin{pmatrix}\cos\theta&-\sin\theta&0\ \sin\theta&\cos\theta&0\ 0&0&1\end{pmatrix}=
\thetaLz | |
e |
,
such that, and that
\thetaLz | |
Be |
B-1=
| |||||||||
e |
,
together with the fact that is closed under the adjoint action of, meaning that .
Thus, e.g., it is easy to check the popular identity
-\piLx/2 | |
e |
\thetaLz | |
e |
\piLx/2 | |
e |
=
\thetaLy | |
e |
.
As shown above, every element is associated with a vector, where is a unit magnitude vector. Since is in the null space of, if one now rotates to a new basis, through some other orthogonal matrix, with as the axis, the final column and row of the rotation matrix in the new basis will be zero.
Thus, we know in advance from the formula for the exponential that must leave fixed. It is mathematically impossible to supply a straightforward formula for such a basis as a function of, because its existence would violate the hairy ball theorem; but direct exponentiation is possible, and yields
\begin{align} \exp(\tilde{\boldsymbol{\omega}}) &=\exp(\theta(\boldsymbol{u ⋅ L})) =\exp\left(\theta\begin{bmatrix}0&-z&y\ z&0&-x\ -y&x&0\end{bmatrix}\right)\\[4pt] &=\boldsymbol{I}+2cs(\boldsymbol{u ⋅ L})+2s2(\boldsymbol{u ⋅ L})2\\[4pt] &=\begin{bmatrix} 2\left(x2-1\right)s2+1&2xys2-2zcs&2xzs2+2ycs\\ 2xys2+2zcs&2\left(y2-1\right)s2+1&2yzs2-2xcs\\ 2xzs2-2ycs&2yzs2+2xcs&2\left(z2-1\right)s2+1 \end{bmatrix}, \end{align}
where and . This is recognized as a matrix for a rotation around axis by the angle : cf. Rodrigues' rotation formula.
Given, let
A=\tfrac{1}{2}\left(R-RT\right)
logR=
\sin-1\|A\| | |
\|A\| |
A.
This is manifest by inspection of the mixed symmetry form of Rodrigues' formula,
eX=I+
\sin\theta | |
\theta |
X+2
| ||||||||
\theta2 |
X2, \theta=\|X\|,
where the first and last term on the right-hand side are symmetric.
SO(3)
SO(3)
Consequently, generating a uniformly random rotation in
\R3
where
u1,u2,u3
[0,1]
See main article: Baker–Campbell–Hausdorff formula. Suppose and in the Lie algebra are given. Their exponentials, and, are rotation matrices, which can be multiplied. Since the exponential map is a surjection, for some in the Lie algebra,, and one may tentatively write
Z=C(X,Y),
for some expression in and . When and commute, then, mimicking the behavior of complex exponentiation.
The general case is given by the more elaborate BCH formula, a series expansion of nested Lie brackets. For matrices, the Lie bracket is the same operation as the commutator, which monitors lack of commutativity in multiplication. This general expansion unfolds as follows,[15]
Z=C(X,Y)=X+Y+
1 | |
2 |
[X,Y]+\tfrac{1}{12}[X,[X,Y]]-
1 | |
12 |
[Y,[X,Y]]+ … .
The infinite expansion in the BCH formula for reduces to a compact form,
Z=\alphaX+\betaY+\gamma[X,Y],
for suitable trigonometric function coefficients .The are given by
\alpha=\phi\cot\left(
\phi | |
2 |
\right)\gamma, \beta=\theta\cot\left(
\theta | |
2 |
\right)\gamma, \gamma=
\sin-1d | |
d |
c | |
\theta\phi |
,
\begin{align} c&=
1 | |
2 |
\sin\theta\sin\phi-
| ||||
2\sin |
| ||||
\sin |
\cos(\angle(u,v)), a=c\cot\left(
\phi | |
2 |
\right), b=c\cot\left(
\theta | |
2 |
\right),\\ d&=\sqrt{a2+b2+2ab\cos(\angle(u,v))+c2\sin2(\angle(u,v))}, \end{align}
for
\theta=\|X\|, \phi=\|Y\|, \angle(u,v)=\cos-1
\langleX,Y\rangle | |
\|X\|\|Y\| |
.
The inner product is the Hilbert–Schmidt inner product and the norm is the associated norm. Under the hat-isomorphism,
\langleu,v\rangle=
1 | |
2 |
\operatorname{Tr}XTY,
which explains the factors for and . This drops out in the expression for the angle.
It is worthwhile to write this composite rotation generator as
\alphaX+\betaY+\gamma[X,Y]\underset{ak{so}(3)}{=}X+Y+
1 | |
2 |
[X,Y]+
1 | |
12 |
[X,[X,Y]]-
1 | |
12 |
[Y,[X,Y]]+ … ,
to emphasize that this is a Lie algebra identity.
The above identity holds for all faithful representations of . The kernel of a Lie algebra homomorphism is an ideal, but, being simple, has no nontrivial ideals and all nontrivial representations are hence faithful. It holds in particular in the doublet or spinor representation. The same explicit formula thus follows in a simpler way through Pauli matrices, cf. the 2×2 derivation for SU(2).
The Pauli vector version of the same BCH formula is the somewhat simpler group composition law of SU(2),
ei ⋅ \vec{\sigma}\right)}ei ⋅ \vec{\sigma}\right)}= \exp\left(
c' | |
\sinc' |
\sina'\sinb'\left(\left(i\cotb'\hat{u}+i\cota'\hat{v}\right) ⋅ \vec{\sigma}+
1 | |
2 |
\left[i\hat{u} ⋅ \vec{\sigma},i\hat{v} ⋅ \vec{\sigma}\right]\right) \right),
where
\cosc'=\cosa'\cosb'-\hat{u} ⋅ \hat{v}\sina'\sinb',
the spherical law of cosines. (Note are angles, not the above.)
This is manifestly of the same format as above,
Z=\alpha'X+\beta'Y+\gamma'[X,Y],
X=ia'\hat{u} ⋅ \sigma, Y=ib'\hat{v} ⋅ \sigma\inak{su}(2),
\begin{align} \alpha'&=
c' | |
\sinc' |
\sina' | |
a' |
\cosb'\ \beta'&=
c' | |
\sinc' |
\sinb' | |
b' |
\cosa'\ \gamma'&=
1 | |
2 |
c' | |
\sinc' |
\sina' | |
a' |
\sinb' | |
b' |
. \end{align}
For uniform normalization of the generators in the Lie algebra involved, express the Pauli matrices in terms of -matrices,, so that
a'\mapsto-
\theta | |
2 |
, b'\mapsto-
\phi | |
2 |
.
To verify then these are the same coefficients as above, compute the ratios of the coefficients,
\begin{align}
\alpha' | |
\gamma' |
&=\theta\cot
\theta | |
2 |
&=
\alpha | |
\gamma |
\\
\beta' | |
\gamma' |
&=\phi\cot
\phi | |
2 |
&=
\beta | |
\gamma |
. \end{align}
For the general case, one might use Ref.[16]
The quaternion formulation of the composition of two rotations RB and RA also yields directly the rotation axis and angle of the composite rotation RC = RBRA.
Let the quaternion associated with a spatial rotation R is constructed from its rotation axis S and the rotation angle φ this axis. The associated quaternion is given by,
S=\cos
\phi | |
2 |
+\sin
\phi | |
2 |
S.
Then the composition of the rotation RR with RA is the rotation RC = RBRA with rotation axis and angle defined by the product of the quaternions
A=\cos
\alpha | |
2 |
+\sin
\alpha | |
2 |
A and B=\cos
\beta | |
2 |
+\sin
\beta | |
2 |
B,
that is
C=\cos
\gamma | |
2 |
+\sin
\gamma | |
2 |
C= \left(\cos
\beta | |
2 |
+\sin
\beta | B\right)\left(\cos | |
2 |
\alpha | |
2 |
+\sin
\alpha | |
2 |
A\right).
Expand this product to obtain
\cos | \gamma |
2 |
+\sin
\gamma | |
2 |
C= \left(\cos
\beta | \cos | |
2 |
\alpha | |
2 |
- \sin
\beta | \sin | |
2 |
\alpha | |
2 |
B ⋅ A \right)+\left(\sin
\beta | \cos | |
2 |
\alpha | |
2 |
B+ \sin
\alpha | \cos | |
2 |
\beta | |
2 |
A+ \sin
\beta | \sin | |
2 |
\alpha | |
2 |
B x A \right).
Divide both sides of this equation by the identity, which is the law of cosines on a sphere,
\cos | \gamma |
2 |
=\cos
\beta | \cos | |
2 |
\alpha | |
2 |
-\sin
\beta | \sin | |
2 |
\alpha | |
2 |
B ⋅ A,
and compute
\tan | \gamma |
2 |
C=
| ||||||||||||||
|
.
This is Rodrigues' formula for the axis of a composite rotation defined in terms of the axes of the two rotations. He derived this formula in 1840 (see page 408).[17]
The three rotation axes A, B, and C form a spherical triangle and the dihedral angles between the planes formed by the sides of this triangle are defined by the rotation angles.
See main article: Rotation formalisms in three dimensions.
See also: Charts on SO(3).
We have seen that there are a variety of ways to represent rotations:
See main article: Spherical harmonics.
The group of three-dimensional Euclidean rotations has an infinite-dimensional representation on the Hilbert space
L2\left(S2\right)=\operatorname{span}\left\{
\ell | |
Y | |
m, |
\ell\in\N+,-\ell\leqm\leq\ell\right\},
where
\ell | |
Y | |
m |
If is an arbitrary square integrable function defined on the unit sphere, then it can be expressed as
where the expansion coefficients are given by
The Lorentz group action restricts to that of and is expressed as
This action is unitary, meaning that
The can be obtained from the of above using Clebsch–Gordan decomposition, but they are more easily directly expressed as an exponential of an odd-dimensional -representation (the 3-dimensional one is exactly).[19] [20] In this case the space decomposes neatly into an infinite direct sum of irreducible odd finite-dimensional representations according to[21]
This is characteristic of infinite-dimensional unitary representations of . If is an infinite-dimensional unitary representation on a separable[22] Hilbert space, then it decomposes as a direct sum of finite-dimensional unitary representations. Such a representation is thus never irreducible. All irreducible finite-dimensional representations can be made unitary by an appropriate choice of inner product,
\langlef,g\rangleU\equiv\int\operatorname{SO(3)}\langle\Pi(R)f,\Pi(R)g\rangledg=
1 | |
8\pi2 |
2\pi | |
\int | |
0 |
\pi | |
\int | |
0 |
2\pi | |
\int | |
0 |
\langle\Pi(R)f,\Pi(R)g\rangle\sin\thetad\phid\thetad\psi, f,g\inV,
where the integral is the unique invariant integral over normalized to, here expressed using the Euler angles parametrization. The inner product inside the integral is any inner product on .
The rotation group generalizes quite naturally to n-dimensional Euclidean space,
\Rn
In special relativity, one works in a 4-dimensional vector space, known as Minkowski space rather than 3-dimensional Euclidean space. Unlike Euclidean space, Minkowski space has an inner product with an indefinite signature. However, one can still define generalized rotations which preserve this inner product. Such generalized rotations are known as Lorentz transformations and the group of all such transformations is called the Lorentz group.
The rotation group SO(3) can be described as a subgroup of E+(3), the Euclidean group of direct isometries of Euclidean
\R3.
In general, the rotation group of an object is the symmetry group within the group of direct isometries; in other words, the intersection of the full symmetry group and the group of direct isometries. For chiral objects it is the same as the full symmetry group.
\Rn
g\theta
g\theta
g\psi
g\theta
g\psi
g\theta=g\phig\theta
-1 | |
g | |
\phi |
.
g\psi=g\phig\theta
-1 | |
g | |
\phi |
g\phig\psi\left[g\phig\theta
-1 | |
g | |
\phi |
g\phi\right]-1.
g\psig\thetag\phi=g\phig\theta
-1 | |
g | |
\phi |
g\phig\psi\left[g\phig\theta
-1 | |
g | |
\phi |
g\phi\right]-1*g\phig\theta
-1 | |
g | |
\phi |
*g\phi=g\phig\thetag\psi.
ak{so}(3)
\boldsymbol{U}\boldsymbol{J}\alpha
\dagger=i\boldsymbol{L} | |
\boldsymbol{U} | |
\alpha |
\boldsymbol{U}=\left(\begin{array}{ccc} -
i | |
\sqrt{2 |
\|X\|+\|Y\|<log2
\|Z\|<log2.