Regulated function explained
In mathematics, a regulated function, or ruled function, is a certain kind of well-behaved function of a single real variable. Regulated functions arise as a class of integrable functions, and have several equivalent characterisations. Regulated functions were introduced by Nicolas Bourbaki in 1949, in their book "Livre IV: Fonctions d'une variable réelle".
Definition
Let X be a Banach space with norm || - ||X. A function f : [0, ''T''] → X is said to be a regulated function if one (and hence both) of the following two equivalent conditions holds true:
It requires a little work to show that these two conditions are equivalent. However, it is relatively easy to see that the second condition may be re-stated in the following equivalent ways:
- for every δ > 0, there is some step function φδ : [0, ''T''] → X such that
\|f-\varphi\delta\|infty=\supt\|f(t)-\varphi\delta(t)\|X<\delta;
- f lies in the closure of the space Step([0, ''T'']; X) of all step functions from [0, ''T''] into X (taking closure with respect to the supremum norm in the space B([0, ''T'']; X) of all bounded functions from [0, ''T''] into X).
Properties of regulated functions
Let Reg([0, ''T'']; X) denote the set of all regulated functions f : [0, ''T''] → X.
- Sums and scalar multiples of regulated functions are again regulated functions. In other words, Reg([0, ''T'']; X) is a vector space over the same field K as the space X; typically, K will be the real or complex numbers. If X is equipped with an operation of multiplication, then products of regulated functions are again regulated functions. In other words, if X is a K-algebra, then so is Reg([0, ''T'']; X).
- The supremum norm is a norm on Reg([0, ''T'']; X), and Reg([0, ''T'']; X) is a topological vector space with respect to the topology induced by the supremum norm.
- As noted above, Reg([0, ''T'']; X) is the closure in B([0, ''T'']; X) of Step([0, ''T'']; X) with respect to the supremum norm.
- If X is a Banach space, then Reg([0, ''T'']; X) is also a Banach space with respect to the supremum norm.
- Reg([0, ''T'']; R) forms an infinite-dimensional real Banach algebra: finite linear combinations and products of regulated functions are again regulated functions.
- Since a continuous function defined on a compact space (such as [0, ''T'']) is automatically uniformly continuous, every continuous function f : [0, ''T''] → X is also regulated. In fact, with respect to the supremum norm, the space C0([0, ''T'']; X) of continuous functions is a closed linear subspace of Reg([0, ''T'']; X).
- If X is a Banach space, then the space BV([0, ''T'']; X) of functions of bounded variation forms a dense linear subspace of Reg([0, ''T'']; X):
Reg([0,T];X)=\overline{BV([0,T];X)}w.r.t.\| ⋅ \|infty.
- If X is a Banach space, then a function f : [0, ''T''] → X is regulated if and only if it is of bounded φ-variation for some φ:
Reg([0,T];X)=cup\varphiBV\varphi([0,T];X).
, the set of points at which the right and left limits differ by more than
is finite. In particular, the discontinuity set has
measure zero, from which it follows that a regulated function has a well-defined
Riemann integral.
- Remark: By the Baire Category theorem the set of points of discontinuity of such function
is either meager or else has nonempty interior. This is not always equivalent with countability.
[1] - The integral, as defined on step functions in the obvious way, extends naturally to Reg([0, ''T'']; X) by defining the integral of a regulated function to be the limit of the integrals of any sequence of step functions converging uniformly to it. This extension is well-defined and satisfies all of the usual properties of an integral. In particular, the regulated integral
- is a bounded linear function from Reg([0, ''T'']; X) to X; hence, in the case X = R, the integral is an element of the space that is dual to Reg([0, ''T'']; R);
- agrees with the Riemann integral.
External links
Notes and References
- https://math.stackexchange.com/q/84870 Stackexchange discussion