Purely inseparable extension explained

In algebra, a purely inseparable extension of fields is an extension k ⊆ K of fields of characteristic p > 0 such that every element of K is a root of an equation of the form xq = a, with q a power of p and a in k. Purely inseparable extensions are sometimes called radicial extensions, which should not be confused with the similar-sounding but more general notion of radical extensions.

Purely inseparable extensions

E\supseteqF

is a purely inseparable extension if and only if for every

\alpha\inE\setminusF

, the minimal polynomial of

\alpha

over F is not a separable polynomial.[1] If F is any field, the trivial extension

F\supseteqF

is purely inseparable; for the field F to possess a non-trivial purely inseparable extension, it must be imperfect as outlined in the above section.

Several equivalent and more concrete definitions for the notion of a purely inseparable extension are known. If

E\supseteqF

is an algebraic extension with (non-zero) prime characteristic p, then the following are equivalent:[2]
  1. E is purely inseparable over F.
  2. For each element

\alpha\inE

, there exists

n\geq0

such that
pn
\alpha

\inF

.
  1. Each element of E has minimal polynomial over F of the form
pn
X

-a

for some integer

n\geq0

and some element

a\inF

.

It follows from the above equivalent characterizations that if

E=F[\alpha]

(for F a field of prime characteristic) such that
pn
\alpha

\inF

for some integer

n\geq0

, then E is purely inseparable over F.[3] (To see this, note that the set of all x such that
pn
x

\inF

for some

n\geq0

forms a field; since this field contains both

\alpha

and F, it must be E, and by condition 2 above,

E\supseteqF

must be purely inseparable.)

If F is an imperfect field of prime characteristic p, choose

a\inF

such that a is not a pth power in F, and let f(X) = Xp - a. Then f has no root in F, and so if E is a splitting field for f over F, it is possible to choose

\alpha

with

f(\alpha)=0

. In particular,

\alphap=a

and by the property stated in the paragraph directly above, it follows that

F[\alpha]\supseteqF

is a non-trivial purely inseparable extension (in fact,

E=F[\alpha]

, and so

E\supseteqF

is automatically a purely inseparable extension).[4]

Purely inseparable extensions do occur naturally; for example, they occur in algebraic geometry over fields of prime characteristic. If K is a field of characteristic p, and if V is an algebraic variety over K of dimension greater than zero, the function field K(V) is a purely inseparable extension over the subfield K(V)p of pth powers (this follows from condition 2 above). Such extensions occur in the context of multiplication by p on an elliptic curve over a finite field of characteristic p.

Properties

E\supseteqF

is a purely inseparable extension, then if

F\subseteqK\subseteqE

, K is purely inseparable over F and E is purely inseparable over K. Furthermore, if [''E'' : ''F''] is finite, then it is a power of p, the characteristic of F.[5]

F\subseteqK\subseteqE

is such that

F\subseteqK

and

K\subseteqE

are purely inseparable extensions, then E is purely inseparable over F.[6]

E\supseteqF

is an inseparable extension if and only if there is some

\alpha\inE\setminusF

such that the minimal polynomial of

\alpha

over F is not a separable polynomial (i.e., an algebraic extension is inseparable if and only if it is not separable; note, however, that an inseparable extension is not the same thing as a purely inseparable extension). If

E\supseteqF

is a finite degree non-trivial inseparable extension, then [''E'' : ''F''] is necessarily divisible by the characteristic of F.[7]

E\supseteqF

is a finite degree normal extension, and if

K=Fix(Gal(E/F))

, then K is purely inseparable over F and E is separable over K.[8]

Galois correspondence for purely inseparable extensions

introduced a variation of Galois theory for purely inseparable extensions of exponent 1, where the Galois groups of field automorphisms in Galois theory are replaced by restricted Lie algebras of derivations. The simplest case is for finite index purely inseparable extensions KL of exponent at most 1 (meaning that the pth power of every element of L is in K). In this case the Lie algebra of K-derivations of L is a restricted Lie algebra that is also a vector space of dimension n over L, where [''L'':''K''] = pn, and the intermediate fields in L containing K correspond to the restricted Lie subalgebras of this Lie algebra that are vector spaces over L. Although the Lie algebra of derivations is a vector space over L, it is not in general a Lie algebra over L, but is a Lie algebra over K of dimension n[''L'':''K''] = npn.

A purely inseparable extension is called a modular extension if it is a tensor product of simple extensions, so in particular every extension of exponent 1 is modular, but there are non-modular extensions of exponent 2 . and gave an extension of the Galois correspondence to modular purely inseparable extensions, where derivations are replaced by higher derivations.

See also

Notes and References

  1. Isaacs, p. 298
  2. Isaacs, Theorem 19.10, p. 298
  3. Isaacs, Corollary 19.11, p. 298
  4. Isaacs, p. 299
  5. Isaacs, Corollary 19.12, p. 299
  6. Isaacs, Corollary 19.13, p. 300
  7. Isaacs, Corollary 19.16, p. 301
  8. Isaacs, Theorem 19.18, p. 301