In mathematics, given two measurable spaces and measures on them, one can obtain a product measurable space and a product measure on that space. Conceptually, this is similar to defining the Cartesian product of sets and the product topology of two topological spaces, except that there can be many natural choices for the product measure.
Let
(X1,\Sigma1)
(X2,\Sigma2)
\Sigma1
\Sigma2
X1
X2
\mu1
\mu2
\Sigma1 ⊗ \Sigma2
X1 x X2
B1 x B2
B1\in\Sigma1
B2\in\Sigma2.
A product measure
\mu1 x \mu2
\mu1 ⊗ \mu2
(X1 x X2,\Sigma1 ⊗ \Sigma2)
(\mu1 x \mu2)(B1 x B2)=\mu1(B1)\mu2(B2)
for all
B1\in\Sigma1, B2\in\Sigma2
(In multiplying measures, some of which are infinite, we define the product to be zero if any factor is zero.)
In fact, when the spaces are
\sigma
(\mu1 x \mu2)(E)=
\int | |
X2 |
y)d\mu | |
\mu | |
2(y) |
=
\int | |
X1 |
\mu2(Ex)d\mu1(x),
where
Ex=\{y\inX2|(x,y)\inE\}
Ey=\{x\inX1|(x,y)\inE\}
The existence of this measure is guaranteed by the Hahn–Kolmogorov theorem. The uniqueness of product measure is guaranteed only in the case that both
(X1,\Sigma1,\mu1)
(X2,\Sigma2,\mu2)
The Borel measures on the Euclidean space Rn can be obtained as the product of n copies of Borel measures on the real line R.
Even if the two factors of the product space are complete measure spaces, the product space may not be. Consequently, the completion procedure is needed to extend the Borel measure into the Lebesgue measure, or to extend the product of two Lebesgue measures to give the Lebesgue measure on the product space.
The opposite construction to the formation of the product of two measures is disintegration, which in some sense "splits" a given measure into a family of measures that can be integrated to give the original measure.
. Michel Loève. Probability Theory vol. I . 4th . Springer . 1977 . 0-387-90210-4 . 8.2. Product measures and iterated integrals . 135 - 137 . loe1978.
. Paul Halmos . Measure theory . Springer . 1974 . 0-387-90088-8 . 35. Product measures . 143 - 145 . loe1978 . registration .