Nowhere dense set explained
In mathematics, a subset of a topological space is called nowhere dense or rare if its closure has empty interior. In a very loose sense, it is a set whose elements are not tightly clustered (as defined by the topology on the space) anywhere. For example, the integers are nowhere dense among the reals, whereas the interval (0, 1) is not nowhere dense.
A countable union of nowhere dense sets is called a meagre set. Meagre sets play an important role in the formulation of the Baire category theorem, which is used in the proof of several fundamental results of functional analysis.
Definition
Density nowhere can be characterized in different (but equivalent) ways. The simplest definition is the one from density:
A subset
of a topological space
is said to be dense in another set
if the intersection
is a dense subset of
is or in
if
is not dense in any nonempty open subset
of
Expanding out the negation of density, it is equivalent that each nonempty open set
contains a nonempty open subset disjoint from
It suffices to check either condition on a
base for the topology on
In particular, density nowhere in
is often described as being dense in no open interval.
[1] [2] Definition by closure
The second definition above is equivalent to requiring that the closure,
cannot contain any nonempty open set.
[3] This is the same as saying that the
interior of the
closure of
is empty; that is,
\operatorname{int}X\left(\operatorname{cl}XS\right)=\varnothing.
[4]
Alternatively, the complement of the closure
X\setminus\left(\operatorname{cl}XS\right)
must be a dense subset of
in other words, the exterior of
is dense in
Properties
The notion of nowhere dense set is always relative to a given surrounding space. Suppose
where
has the
subspace topology induced from
The set
may be nowhere dense in
but not nowhere dense in
Notably, a set is always dense in its own subspace topology. So if
is nonempty, it will not be nowhere dense as a subset of itself. However the following results hold:
is nowhere dense in
then
is nowhere dense in
is open in
, then
is nowhere dense in
if and only if
is nowhere dense in
is dense in
, then
is nowhere dense in
if and only if
is nowhere dense in
A set is nowhere dense if and only if its closure is.
Every subset of a nowhere dense set is nowhere dense, and a finite union of nowhere dense sets is nowhere dense. Thus the nowhere dense sets form an ideal of sets, a suitable notion of negligible set. In general they do not form a -ideal, as meager sets, which are the countable unions of nowhere dense sets, need not be nowhere dense. For example, the set
is not nowhere dense in
The boundary of every open set and of every closed set is closed and nowhere dense. A closed set is nowhere dense if and only if it is equal to its boundary, if and only if it is equal to the boundary of some open set (for example the open set can be taken as the complement of the set). An arbitrary set
is nowhere dense if and only if it is a subset of the boundary of some open set (for example the open set can be taken as the exterior of
).
Examples
and its closure
are nowhere dense in
since the closure has empty interior.
- The Cantor set is an uncountable nowhere dense set in
viewed as the horizontal axis in the Euclidean plane is nowhere dense in
is nowhere dense in
but the rationals
are not (they are dense everywhere).
is
nowhere dense in
: it is dense in the open interval
and in particular the interior of its closure is
Nowhere dense sets with positive measure
A nowhere dense set is not necessarily negligible in every sense. For example, if
is the
unit interval
not only is it possible to have a dense set of
Lebesgue measure zero (such as the set of rationals), but it is also possible to have a nowhere dense set with positive measure. One such example is the
Smith–Volterra–Cantor set.
For another example (a variant of the Cantor set), remove from
all
dyadic fractions, i.e. fractions of the form
in
lowest terms for positive integers
and the intervals around them:
\left(a/2n-1/22n+1,a/2n+1/22n+1\right).
Since for each
this removes intervals adding up to at most
the nowhere dense set remaining after all such intervals have been removed has measure of at least
(in fact just over
because of overlaps
[5]) and so in a sense represents the majority of the ambient space
This set is nowhere dense, as it is closed and has an empty interior: any interval
is not contained in the set since the dyadic fractions in
have been removed.
Generalizing this method, one can construct in the unit interval nowhere dense sets of any measure less than
although the measure cannot be exactly 1 (because otherwise the complement of its closure would be a nonempty open set with measure zero, which is impossible).
[6] For another simpler example, if
is any dense open subset of
having finite
Lebesgue measure then
is necessarily a closed subset of
having infinite Lebesgue measure that is also nowhere dense in
(because its topological interior is empty). Such a dense open subset
of finite Lebesgue measure is commonly constructed when proving that the Lebesgue measure of the rational numbers
is
This may be done by choosing any
bijection
(it actually suffices for
to merely be a
surjection) and for every
letting
(here, the
Minkowski sum notation
f(n)+\left(-r/2n,r/2n\right):=\left(f(n)-r/2n,f(n)+r/2n\right)
was used to simplify the description of the intervals). The open subset
is dense in
because this is true of its subset
and its Lebesgue measure is no greater than
Taking the union of closed, rather than open, intervals produces the
F-subsetthat satisfies
Sr/2\subseteqUr\subseteqSr\subseteqU2r.
Because
is a subset of the nowhere dense set
it is also nowhere dense in
Because
is a
Baire space, the set
is a dense subset of
(which means that like its subset
cannot possibly be nowhere dense in
) with
Lebesgue measure that is also a
nonmeager subset of
(that is,
is of the
second category in
), which makes
a
comeager subset of
whose interior in
is also empty; however,
is nowhere dense in
if and only if its in
has empty interior. The subset
in this example can be replaced by any countable dense subset of
and furthermore, even the set
can be replaced by
for any integer
Bibliography
- Book: Fremlin, D. H.. Measure Theory. Lulu.com. 2002. 978-0-9566071-1-9.
External links
Notes and References
- Book: Oxtoby, John C.. Measure and Category. Springer-Verlag. 1980. 0-387-90508-1. 2nd. New York. 1–2. A set is nowhere dense if it is dense in no interval.
- although note that Oxtoby later gives the interior-of-closure definition on page 40.
- Book: Natanson, Israel P.. Teoria functsiy veshchestvennoy peremennoy. Frederick Ungar. 1955. I (Chapters 1-9). New York. 88. 2027/mdp.49015000681685. English. Boron. Leo F.. Theory of functions of a real variable. 54-7420.
- Book: Steen. Lynn Arthur. Counterexamples in Topology. Seebach Jr.. J. Arthur. Dover. 1995. 978-0-486-68735-3. Dover republication of Springer-Verlag 1978. New York. 7. A subset
of
is said to be nowhere dense in
if no nonempty open set of
is contained in
.
- Book: Gamelin, Theodore W.. Introduction to Topology. Dover. 1999. 0-486-40680-6. 2nd. Mineola. 36–37. ProQuest ebook Central.
- Web site: Some nowhere dense sets with positive measure and a strictly monotonic continuous function with a dense set of points with zero derivative.
- Book: Folland, G. B.. Real analysis: modern techniques and their applications. John Wiley & Sons. 1984. 0-471-80958-6. New York. 41. 2027/mdp.49015000929258.