Irreducible ideal explained
In mathematics, a proper ideal of a commutative ring is said to be irreducible if it cannot be written as the intersection of two strictly larger ideals.[1]
Examples
and
be ideals of a commutative ring
, with neither one contained in the other. Then there exist
and
, where neither is in
but the product is. This proves that a reducible ideal is not prime. A concrete example of this are the ideals
and
contained in
. The intersection is
, and
is not a prime ideal.
Properties
An element of an integral domain is prime if and only if the ideal generated by it is a non-zero prime ideal. This is not true for irreducible ideals; an irreducible ideal may be generated by an element that is not an irreducible element, as is the case in
for the ideal
since it is not the intersection of two strictly greater ideals.
In algebraic geometry, if an ideal
of a ring
is irreducible, then
is an
irreducible subset in the
Zariski topology on the
spectrum
. The
converse does not hold; for example the ideal
in
defines the irreducible
variety consisting of just the origin, but it is not an irreducible ideal as
(x2,xy,y2)=(x2,y)\cap(x,y2)
.
See also
Notes and References
- .
- .
- Book: Dummit. David S.. Foote. Richard M.. Abstract Algebra. 2004. John Wiley & Sons, Inc.. Hoboken, NJ. 0-471-43334-9. 683–685. Third.
- . Theorem 1, p. 3.