In commutative algebra, the norm of an ideal is a generalization of a norm of an element in the field extension. It is particularly important in number theory since it measures the size of an ideal of a complicated number ring in terms of an ideal in a less complicated ring. When the less complicated number ring is taken to be the ring of integers, Z, then the norm of a nonzero ideal I of a number ring R is simply the size of the finite quotient ring R/I.
Let A be a Dedekind domain with field of fractions K and integral closure of B in a finite separable extension L of K. (this implies that B is also a Dedekind domain.) Let
l{I}A
l{I}B
NB/A\colonl{I}B\tol{I}A
NB/A(akq)=ak{p}[B/akq
akq
akp=akq\capA
akq
Alternatively, for any
akb\inl{I}B
NB/A(ak{b})
\{NL/K(x)|x\inak{b}\}
For
aka\inl{I}A
NB/A(akaB)=akan
n=[L:K]
The ideal norm of a principal ideal is thus compatible with the field norm of an element:
NB/A(xB)=NL/K(x)A.
Let
L/K
l{O}K\subsetl{O}L
Then the preceding applies with
A=l{O}K,B=l{O}L
akb\inl{I}l{OL}
Nl{OL/l{O}K}(akb)=K\cap\prod\sigma(L/K)}\sigma(akb),
l{I}l{OK}
The notation
Nl{OL/l{O}K}
NL/K
NL/K
In the case
K=Q
Nl{OL/Z
Z
\{\pm1\}
Z
L
K=Q
Let
L
l{O}L
aka
l{O}L
The absolute norm of
aka
N(aka):=\left[l{O}L:aka\right]=\left|l{O}L/aka\right|.
If
aka=(a)
N(aka)=\left|NL/Q(a)\right|
The norm is completely multiplicative: if
aka
akb
l{O}L
N(aka ⋅ akb)=N(aka)N(akb)
Thus the absolute norm extends uniquely to a group homomorphism
N\colonl{I}l{OL}\toQ
x , | |
>0 |
l{O}L
aka
there always exists a nonzero
a\inaka
\left|NL/Q(a)\right|\leq\left(
2 | |
\pi |
\right)s\sqrt{\left|\DeltaL\right|}N(aka),
\DeltaL
L
s
C