Hyperconnected space explained

In the mathematical field of topology, a hyperconnected space[1] or irreducible space is a topological space X that cannot be written as the union of two proper closed subsets (whether disjoint or non-disjoint). The name irreducible space is preferred in algebraic geometry.

For a topological space X the following conditions are equivalent:

A space which satisfies any one of these conditions is called hyperconnected or irreducible. Due to the condition about neighborhoods of distinct points being in a sense the opposite of the Hausdorff property, some authors call such spaces anti-Hausdorff.[2]

The empty set is vacuously a hyperconnected or irreducible space under the definition above (because it contains no nonempty open sets). However some authors,[3] especially those interested in applications to algebraic geometry, add an explicit condition that an irreducible space must be nonempty.

An irreducible set is a subset of a topological space for which the subspace topology is irreducible.

Examples

Two examples of hyperconnected spaces from point set topology are the cofinite topology on any infinite set and the right order topology on

R

.

In algebraic geometry, taking the spectrum of a ring whose reduced ring is an integral domain is an irreducible topological space—applying the lattice theorem to the nilradical, which is within every prime, to show the spectrum of the quotient map is a homeomorphism, this reduces to the irreducibility of the spectrum of an integral domain. For example, the schemes

Spec\left(

Z[x,y,z]
x4+y3+z2

\right)

,

Proj\left(

C[x,y,z]
(y2z-x(x-z)(x-2z))

\right)

are irreducible since in both cases the polynomials defining the ideal are irreducible polynomials (meaning they have no non-trivial factorization). A non-example is given by the normal crossing divisor

Spec\left(

C[x,y,z]
(xyz)

\right)

since the underlying space is the union of the affine planes
2
A
x,y
,
2
A
x,z
, and
2
A
y,z
. Another non-example is given by the scheme

Proj\left(

C[x,y,z,w]
(xy,f4)

\right)

where

f4

is an irreducible degree 4 homogeneous polynomial. This is the union of the two genus 3 curves (by the genus–degree formula)

Proj\left(

C[y,z,w]
(f4(0,y,z,w))

\right),Proj\left(

C[x,z,w]
(f4(x,0,z,w))

\right)

Hyperconnectedness vs. connectedness

Every hyperconnected space is both connected and locally connected (though not necessarily path-connected or locally path-connected).

Note that in the definition of hyper-connectedness, the closed sets don't have to be disjoint. This is in contrast to the definition of connectedness, in which the open sets are disjoint.

For example, the space of real numbers with the standard topology is connected but not hyperconnected. This is because it cannot be written as a union of two disjoint open sets, but it can be written as a union of two (non-disjoint) closed sets.

Properties

Proof: Let

U\subsetX

be an open subset. Any two disjoint open subsets of

U

would themselves be disjoint open subsets of

X

. So at least one of them must be empty.

Proof: Suppose

S

is a dense subset of

X

and

S=S1\cupS2

with

S1

,

S2

closed in

S

. Then

X=\overlineS=\overline{S1}\cup\overline{S2}

. Since

X

is hyperconnected, one of the two closures is the whole space

X

, say

\overline{S1}=X

. This implies that

S1

is dense in

S

, and since it is closed in

S

, it must be equal to

S

.

Counterexample:

\Bbbk2

with

\Bbbk

an algebraically closed field (thus infinite) is hyperconnected[6] in the Zariski topology, while

V=Z(XY)=Z(X)\cupZ(Y)\subset\Bbbk2

is closed and not hyperconnected.

Proof: Suppose

S\subseteqX

where

S

is irreducible and write

\operatorname{Cl}X(S)=F\cupG

for two closed subsets

F,G\subseteq\operatorname{Cl}X(S)

(and thus in

X

).

F':=F\capS,G':=G\capS

are closed in

S

and

S=F'\cupG'

which implies

S\subseteqF

or

S\subseteqG

, but then

\operatorname{Cl}X(S)=F

or

\operatorname{Cl}X(S)=G

by definition of closure.

X

which can be written as

X=U1\cupU2

with

U1,U2\subsetX

open and irreducible such that

U1\capU2\ne\emptyset

is irreducible.[8]

Proof: Firstly, we notice that if

V

is a non-empty open set in

X

then it intersects both

U1

and

U2

; indeed, suppose

V1:=U1\capV\ne\emptyset

, then

V1

is dense in

U1

, thus

\exists

x\in\operatorname{Cl}
U1

(V1)\capU2=U1\capU2\ne\emptyset

and

x\inU2

is a point of closure of

V1

which implies

V1\capU2\ne\emptyset

and a fortiori

V2:=V\capU2\ne\emptyset

. Now

V=V\cap(U1\cupU2)=V1\cupV2

and taking the closure

\operatorname{Cl}X

(V)\supseteq{\operatorname{Cl}}
U1

(V1)\cup{\operatorname{Cl}}

U2

(V2)=U1\cupU2=X,

therefore

V

is a non-empty open and dense subset of

X

. Since this is true for every non-empty open subset,

X

is irreducible.

Irreducible components

An irreducible component[9] in a topological space is a maximal irreducible subset (i.e. an irreducible set that is not contained in any larger irreducible set). The irreducible components are always closed.

Every irreducible subset of a space X is contained in a (not necessarily unique) irreducible component of X.[10] In particular, every point of X is contained in some irreducible component of X. Unlike the connected components of a space, the irreducible components need not be disjoint (i.e. they need not form a partition). In general, the irreducible components will overlap.

The irreducible components of a Hausdorff space are just the singleton sets.

Since every irreducible space is connected, the irreducible components will always lie in the connected components.

Every Noetherian topological space has finitely many irreducible components.[11]

See also

References

Notes and References

  1. Steen & Seebach, p. 29
  2. An anti-Hausdorff Fréchet space in which convergent sequences have unique limits. 10.1016/0166-8641(93)90147-6. 1993. Van Douwen. Eric K.. Topology and Its Applications. 51. 2. 147–158. free.
  3. Web site: Section 5.8 (004U): Irreducible components—The Stacks project.
  4. Book: Bourbaki, Nicolas. Commutative Algebra: Chapters 1-7. Springer. 1989. 978-3-540-64239-8. 95.
  5. Book: Bourbaki, Nicolas. Commutative Algebra: Chapters 1-7. Springer. 1989. 978-3-540-64239-8. 95.
  6. Book: Perrin, Daniel. Algebraic Geometry. An introduction. Springer. 2008. 978-1-84800-055-1. 14.
  7. Web site: Lemma 5.8.3 (004W)—The Stacks project.
  8. Book: Bourbaki, Nicolas. Commutative Algebra: Chapters 1-7. Springer. 1989. 978-3-540-64239-8. 95.
  9. Web site: Definition 5.8.1 (004V)—The Stacks project.
  10. Web site: Lemma 5.8.3 (004W)—The Stacks project.
  11. Web site: Section 5.9 (0050): Noetherian topological spaces—The Stacks project.