Analyticity of holomorphic functions explained
of a complex variable
:
if it is
differentiable at every point within some
open disk centered at
, and
if in some open disk centered at
it can be expanded as a
convergent power series (this implies that the
radius of convergence is positive).
One of the most important theorems of complex analysis is that holomorphic functions are analytic and vice versa. Among the corollaries of this theorem are
with an
accumulation point inside the
intersection of their
domains also agree everywhere in every connected open
subset of their domains that contains the set
, and
- the fact that, since power series are infinitely differentiable, so are holomorphic functions (this is in contrast to the case of real differentiable functions), and
- the fact that the radius of convergence is always the distance from the center
to the nearest non-removable
singularity; if there are no singularities (i.e., if
is an
entire function), then the radius of convergence is infinite. Strictly speaking, this is not a corollary of the theorem but rather a by-product of the proof.
- no bump function on the complex plane can be entire. In particular, on any connected open subset of the complex plane, there can be no bump function defined on that set which is holomorphic on the set. This has important ramifications for the study of complex manifolds, as it precludes the use of partitions of unity. In contrast the partition of unity is a tool which can be used on any real manifold.
Proof
The argument, first given by Cauchy, hinges on Cauchy's integral formula and the power series expansion of the expression
Let
be an open disk centered at
and suppose
is differentiable everywhere within an open neighborhood containing the closure of
. Let
be the positively oriented (i.e., counterclockwise) circle which is the boundary of
and let
be a point in
. Starting with Cauchy's integral formula, we have
\begin{align}f(z)&{}={1\over2\pii}\intC{f(w)\overw-z}dw\\[10pt]
&{}={1\over2\pii}\intC{f(w)\over(w-a)-(z-a)}dw\\[10pt]
&{}={1\over2\pii}\intC{1\overw-a} ⋅ {1\over1-{z-a\overw-a}}f(w)dw\\[10pt]
&{}={1\over2\pii}\intC{1\over
| infty\left({z-a |
w-a} ⋅ {\sum | |
| n=0 |
\overw-a}\right)n}f(w)dw
| infty{1 |
\\[10pt]
&{}=\sum | |
| n=0 |
\over2\pii}\intC{(z-a)n\over(w-a)n+1
} f(w)\,\mathrmw.\end
Interchange of the integral and infinite sum is justified by observing that
is bounded on
by some positive number
, while for all
in
for some positive
as well. We therefore have
\left|{(z-a)n\over(w-a)n+1}f(w)\right|\leMrn,
on
, and as the
Weierstrass M-test shows the series
converges uniformly over
, the sum and the integral may be interchanged.
As the factor
does not depend on the variable of integration
, it may be factored out to yield
(z-a)n{1\over2\pii}\intC{f(w)\over(w-a)n+1
} \,\mathrmw,
which has the desired form of a power series in
:
with coefficients
cn={1\over2\pii}\intC{f(w)\over(w-a)n+1
} \,\mathrmw.
Remarks
- Since power series can be differentiated term-wise, applying the above argument in the reverse direction and the power series expression for gives This is a Cauchy integral formula for derivatives. Therefore the power series obtained above is the Taylor series of
.
is any point that is closer to the center
than is any singularity of
. Therefore, the radius of convergence of the Taylor series cannot be smaller than the distance from
to the nearest singularity (nor can it be larger, since power series have no singularities in the interiors of their circles of convergence).
- A special case of the identity theorem follows from the preceding remark. If two holomorphic functions agree on a (possibly quite small) open neighborhood
of
, then they coincide on the open disk
, where
is the distance from
to the nearest singularity