In mathematics, in the area of order theory, a free lattice is the free object corresponding to a lattice. As free objects, they have the universal property.
Because the concept of a lattice can be axiomatised in terms of two operations
\wedge
\vee
F
X
F(X)
η\colonX\longrightarrowF(X)
x\inX
η(x)\inF(X)
f\colonX\longrightarrowL
X
L
\tilde{f}\colonF(X)\longrightarrowL
f=\tilde{f}\circη
F
It is frequently possible to prove things about the free lattice directly using the universal property, but such arguments tend to be rather abstract, so a concrete construction provides a valuable alternative presentation.
In the case of semilattices, an explicit construction of the free semilattice
F\vee(X)
F\vee(X)
X
\vee
η\colonX\longrightarrowF\vee(X)
X
η(x)=\{x\}
x\inX
L
f\colonX\longrightarrowL
\tilde{f}\colonF\vee(X)\longrightarrowL
vee
L
This form of
\tilde{f}
S\inF\vee(X)
η(x)
x\inX
\tilde{f}l(η(x)r)=f(x)
\tilde{f}
\tilde{f}(S1\cupS2)=\tilde{f}(S1)\vee\tilde{f}(S2)
S1,S2\inF\vee(X)
\tilde{f}
X
F\vee(X)
X
It is similarly possible to define a free functor
F\wedge
F\wedge(F\vee(X))
F(X)
F\wedge
F\vee(X)
\vee
F\wedge(F\vee(X))
F\vee(X)
F\wedge
a
a\veeb
a\wedge(a\veeb)=a
F(X)
|
|
The word problem for free lattices has some interesting aspects. Consider the case of bounded lattices, i.e. algebraic structures with the two binary operations ∨ and ∧ and the two constants (nullary operations) 0 and 1. The set of all well-formed expressions that can be formulated using these operations on elements from a given set of generators X will be called W(X). This set of words contains many expressions that turn out to denote equal values in every lattice. For example, if a is some element of X, then a ∨ 1 = 1 and a ∧ 1 =a. The word problem for free bounded lattices is the problem of determining which of these elements of W(X) denote the same element in the free bounded lattice FX, and hence in every bounded lattice.
The word problem may be resolved as follows. A relation ≤~ on W(X) may be defined inductively by setting w ≤~ v if and only if one of the following holds:
This defines a preorder ≤~ on W(X), so an equivalence relation can be defined by w ~ v when w ≤~ v and v ≤~ w. One may then show that the partially ordered quotient space W(X)/~ is the free bounded lattice FX.[1] [2] The equivalence classes of W(X)/~ are the sets of all words w and v with w ≤~ v and v ≤~ w. Two well-formed words v and w in W(X) denote the same value in every bounded lattice if and only if w ≤~ v and v ≤~ w; the latter conditions can be effectively decided using the above inductive definition. The table shows an example computation to show that the words x∧z and x∧z∧(x∨y) denote the same value in every bounded lattice. The case of lattices that are not bounded is treated similarly, omitting rules 2. and 3. in the above construction.
The solution of the word problem on free lattices has several interesting corollaries. One is that the free lattice of a three-element set of generators is infinite. In fact, one can even show that every free lattice on three generators contains a sublattice which is free for a set of four generators. By induction, this eventually yields a sublattice free on countably many generators.[3] This property is reminiscent of SQ-universality in groups.
The proof that the free lattice in three generators is infinite proceeds by inductively defining
pn+1 = x ∨ (y ∧ (z ∨ (x ∧ (y ∨ (z ∧ pn)))))
where x, y, and z are the three generators, and p0 = x. One then shows, using the inductive relations of the word problem, that pn+1 is strictly greater[4] than pn, and therefore all infinitely many words pn evaluate to different values in the free lattice FX.
Another corollary is that the complete free lattice (on three or more generators) "does not exist", in the sense that it is a proper class. The proof of this follows from the word problem as well. To define a complete lattice in terms of relations, it does not suffice to use the finitary relations of meet and join; one must also have infinitary relations defining the meet and join of infinite subsets. For example, the infinitary relation corresponding to "join" may be defined as
\operatorname{sup}N:(f:N\toFX)
Here, f is a map from the elements of a cardinal N to FX; the operator
\operatorname{sup}N
The axioms of the pre-ordering of the word problem may be adjoined by the two infinitary operators corresponding to meet and join. After doing so, one then extends the definition of
pn
p\alpha
p\alpha=\operatorname{sup}\{p\beta\mid\beta<\alpha\}
when
\alpha
p\alpha+1
p\alpha