Formally étale morphism explained
In commutative algebra and algebraic geometry, a morphism is called formally étale if it has a lifting property that is analogous to being a local diffeomorphism.
Formally étale homomorphisms of rings
Let A be a topological ring, and let B be a topological A-algebra. Then B is formally étale if for all discrete A-algebras C, all nilpotent ideals J of C, and all continuous A-homomorphisms, there exists a unique continuous A-algebra map such that, where is the canonical projection.[1]
Formally étale is equivalent to formally smooth plus formally unramified.[2]
Formally étale morphisms of schemes
Since the structure sheaf of a scheme naturally carries only the discrete topology, the notion of formally étale for schemes is analogous to formally étale for the discrete topology for rings. That is, a morphism of schemes is formally étale if for every affine Y-scheme Z, every nilpotent sheaf of ideals J on Z with be the closed immersion determined by J, and every Y-morphism, there exists a unique Y-morphism such that .[3]
It is equivalent to let Z be any Y-scheme and let J be a locally nilpotent sheaf of ideals on Z.[4]
Properties
- Open immersions are formally étale.[5]
- The property of being formally étale is preserved under composites, base change, and fibered products.[6]
- If and are morphisms of schemes, g is formally unramified, and gf is formally étale, then f is formally étale. In particular, if g is formally étale, then f is formally étale if and only if gf is.[7]
- The property of being formally étale is local on the source and target.[8]
- The property of being formally étale can be checked on stalks. One can show that a morphism of rings is formally étale if and only if for every prime Q of B, the induced map is formally étale.[9] Consequently, f is formally étale if and only if for every prime Q of B, the map is formally étale, where .
Examples
See also
Notes and References
- [#Reference-EGAIV1|EGA 0<sub>IV</sub>]
- [#Reference-EGAIV1|EGA 0<sub>IV</sub>]
- [#Reference-EGAIV4|EGA IV<sub>4</sub>]
- [#Reference-EGAIV4|EGA IV<sub>4</sub>]
- [#Reference-EGAIV4|EGA IV<sub>4</sub>]
- [#Reference-EGAIV4|EGA IV<sub>4</sub>]
- [#Reference-EGAIV4|EGA IV<sub>4</sub>]
- [#Reference-EGAIV4|EGA IV<sub>4</sub>]
- https://mathoverflow.net/q/16132 mathoverflow.net question