Formally étale morphism explained

In commutative algebra and algebraic geometry, a morphism is called formally étale if it has a lifting property that is analogous to being a local diffeomorphism.

Formally étale homomorphisms of rings

Let A be a topological ring, and let B be a topological A-algebra. Then B is formally étale if for all discrete A-algebras C, all nilpotent ideals J of C, and all continuous A-homomorphisms, there exists a unique continuous A-algebra map such that, where is the canonical projection.[1]

Formally étale is equivalent to formally smooth plus formally unramified.[2]

Formally étale morphisms of schemes

Since the structure sheaf of a scheme naturally carries only the discrete topology, the notion of formally étale for schemes is analogous to formally étale for the discrete topology for rings. That is, a morphism of schemes is formally étale if for every affine Y-scheme Z, every nilpotent sheaf of ideals J on Z with be the closed immersion determined by J, and every Y-morphism, there exists a unique Y-morphism such that .[3]

It is equivalent to let Z be any Y-scheme and let J be a locally nilpotent sheaf of ideals on Z.[4]

Properties

Examples

See also

Notes and References

  1. [#Reference-EGAIV1|EGA 0<sub>IV</sub>]
  2. [#Reference-EGAIV1|EGA 0<sub>IV</sub>]
  3. [#Reference-EGAIV4|EGA IV<sub>4</sub>]
  4. [#Reference-EGAIV4|EGA IV<sub>4</sub>]
  5. [#Reference-EGAIV4|EGA IV<sub>4</sub>]
  6. [#Reference-EGAIV4|EGA IV<sub>4</sub>]
  7. [#Reference-EGAIV4|EGA IV<sub>4</sub>]
  8. [#Reference-EGAIV4|EGA IV<sub>4</sub>]
  9. https://mathoverflow.net/q/16132 mathoverflow.net question