Flipped SO(10) is a grand unified theory which is to standard SO(10) as flipped SU(5) is to SU(5).
In conventional SO(10) models, the fermions lie in three spinorial 16 representations, one for each generation, which decomposes under ['''SU'''(5) × '''U'''(1)<sub>χ</sub>]/Z5 as
16 → 101 ⊕ \bar{5}-3 ⊕ 15
This can either be the Georgi–Glashow SU(5) or flipped SU(5).
In flipped SO(10) models, however, the gauge group is not just SO(10) but SO(10)F × U(1)B or ['''SO'''(10)<sub>F</sub> × '''U'''(1)<sub>B</sub>]/Z4. The fermion fields are now three copies of
161 ⊕ 10-2 ⊕ 14
These contain the Standard Model fermions as well as additional vector fermions with GUT scale masses. If we suppose ['''SU'''(5) × '''U'''(1)<sub>A</sub>]/Z5 is a subgroup of SO(10)F, then we have the intermediate scale symmetry breaking ['''SO'''(10)<sub>F</sub> × '''U'''(1)<sub>B</sub>]/Z4 → ['''SU'''(5) × '''U'''(1)<sub>χ</sub>]/Z5 where
\chi=-{A\over4}+{5B\over4}
In that case,
\begin{align} 161& → 101 ⊕ \bar{5}2 ⊕ 10\\ 10-2& → 5-2 ⊕ \bar{5}-3\\ 14& → 15 \end{align}
note that the Standard Model fermion fields (including the right handed neutrinos) come from all three ['''SO'''(10)<sub>F</sub> × '''U'''(1)<sub>B</sub>]/Z4 representations. In particular, they happen to be the 101 of 161, the
\bar{5}-3
The other remaining fermions are vectorlike. To see this, note that with a 161H and a
\overline{16}-1H
\bar{5}2
<\overline{16}-1H>161\phi
OR we can add the nonrenormalizable term
<\overline{16}-1H><\overline{16}-1H>161161
Either way, the 10 component of the fermion 161 gets taken care of so that it is no longer chiral.
It has been left unspecified so far whether ['''SU'''(5) × '''U'''(1)<sub>χ</sub>]/Z5 is the Georgi–Glashow SU(5) or the flipped SU(5). This is because both alternatives lead to reasonable GUT models.
One reason for studying flipped SO(10) is because it can be derived from an E6 GUT model.