In mathematics, particularly in algebra, a field extension (denoted
L/K
K\subseteqL
Field extensions are fundamental in algebraic number theory, and in the study of polynomial roots through Galois theory, and are widely used in algebraic geometry.
A subfield
K
L
K\subseteqL
L
1
K
As, the latter definition implies
K
L
0
The characteristic of a subfield is the same as the characteristic of the larger field.
If K is a subfield of L, then L is an extension field or simply extension of K, and this pair of fields is a field extension. Such a field extension is denoted
L/K
If L is an extension of F, which is in turn an extension of K, then F is said to be an intermediate field (or intermediate extension or subextension) of
L/K
Given a field extension
L/K
[L:K]
The degree of an extension is 1 if and only if the two fields are equal. In this case, the extension is a . Extensions of degree 2 and 3 are called quadratic extensions and cubic extensions, respectively. A finite extension is an extension that has a finite degree.
Given two extensions
L/K
M/L
M/K
L/K
M/L
[M:K]=[M:L] ⋅ [L:K].
Given a field extension
L/K
S=\{x1,\ldots,xn\}
K(x1,\ldots,xn)
K(\{x1,\ldots,xn\}),
An extension field of the form is often said to result from the of S to K.
In characteristic 0, every finite extension is a simple extension. This is the primitive element theorem, which does not hold true for fields of non-zero characteristic.
If a simple extension is not finite, the field K(s) is isomorphic to the field of rational fractions in s over K.
The notation L / K is purely formal and does not imply the formation of a quotient ring or quotient group or any other kind of division. Instead the slash expresses the word "over". In some literature the notation L:K is used.
It is often desirable to talk about field extensions in situations where the small field is not actually contained in the larger one, but is naturally embedded. For this purpose, one abstractly defines a field extension as an injective ring homomorphism between two fields.Every non-zero ring homomorphism between fields is injective because fields do not possess nontrivial proper ideals, so field extensions are precisely the morphisms in the category of fields.
Henceforth, we will suppress the injective homomorphism and assume that we are dealing with actual subfields.
The field of complex numbers
\Complex
\R
\R
\Q
\Complex/\Q
[\Complex:\R]=2
\{1,i\}
\Complex/\R
\Complex=\R(i).
[\R:\Q]=akc
The field
\Q(\sqrt{2})=\left\{a+b\sqrt{2}\mida,b\in\Q\right\},
is an extension field of
\Q,
\left\{1,\sqrt{2}\right\}
The field
\begin{align} \Q\left(\sqrt{2},\sqrt{3}\right)&=\Q\left(\sqrt{2}\right)\left(\sqrt{3}\right)\\ &=\left\{a+b\sqrt{3}\mida,b\in\Q\left(\sqrt{2}\right)\right\}\\ &=\left\{a+b\sqrt{2}+c\sqrt{3}+d\sqrt{6}\mida,b,c,d\in\Q\right\}, \end{align}
is an extension field of both
\Q(\sqrt{2})
\Q,
\begin{align} \Q(\sqrt{2},\sqrt{3})&=\Q(\sqrt{2}+\sqrt{3})\\ &=\left\{a+b(\sqrt{2}+\sqrt{3})+c(\sqrt{2}+\sqrt{3})2+d(\sqrt{2}+\sqrt{3})3\mida,b,c,d\in\Q\right\}. \end{align}
Finite extensions of
\Q
\Qp
It is common to construct an extension field of a given field K as a quotient ring of the polynomial ring K[''X''] in order to "create" a root for a given polynomial f(X). Suppose for instance that K does not contain any element x with x2 = −1. Then the polynomial
X2+1
L=K[X]/(X2+1)
By iterating the above construction, one can construct a splitting field of any polynomial from K[''X'']. This is an extension field L of K in which the given polynomial splits into a product of linear factors.
GF(pn)=
F | |
pn |
\operatorname{GF}(p)=Fp=\Z/p\Z
Given a field K, we can consider the field K(X) of all rational functions in the variable X with coefficients in K; the elements of K(X) are fractions of two polynomials over K, and indeed K(X) is the field of fractions of the polynomial ring K[''X'']. This field of rational functions is an extension field of K. This extension is infinite.
Given a Riemann surface M, the set of all meromorphic functions defined on M is a field, denoted by
\Complex(M).
\Complex
See main article: Algebraic extension and Algebraic element. An element x of a field extension
L/K
\sqrt2
x2-2.
An element s of L is algebraic over K if and only if the simple extension is a finite extension. In this case the degree of the extension equals the degree of the minimal polynomial, and a basis of the K-vector space K(s) consists of
1,s,s2,\ldots,sd-1,
The set of the elements of L that are algebraic over K form a subextension, which is called the algebraic closure of K in L. This results from the preceding characterization: if s and t are algebraic, the extensions and are finite. Thus is also finite, as well as the sub extensions, and (if). It follows that, st and 1/s are all algebraic.
An algebraic extension
L/K
\Q(\sqrt2,\sqrt3)
\Q
\sqrt2
\sqrt3
\Q.
A simple extension is algebraic if and only if it is finite. This implies that an extension is algebraic if and only if it is the union of its finite subextensions, and that every finite extension is algebraic.
Every field K has an algebraic closure, which is up to an isomorphism the largest extension field of K which is algebraic over K, and also the smallest extension field such that every polynomial with coefficients in K has a root in it. For example,
\Complex
\R
\Q
\Q
\Q
See main article: Transcendental extension. Given a field extension
L/K
L/K
L/K
If L/K is purely transcendental and S is a transcendence basis of the extension, it doesn't necessarily follow that L = K(S). On the opposite, even when one knows a transcendence basis, it may be difficult to decide whether the extension is purely separable, and if it is so, it may be difficult to find a transcendence basis S such that L = K(S).
For example, consider the extension
\Q(x,y)/\Q,
x
\Q,
y
y2-x3=0.
\Q(X)[Y]/\langleY2-X3\rangle,
x
y
X
Y.
\{x\}
\Q
\Q(x,y)/\Q(x)
\{x\}
\Q(x,y)/\Q(x)
\{y\}
t=y/x,
x=t2
y=t3,
t
Purely transcendental extensions of an algebraically closed field occur as function fields of rational varieties. The problem of finding a rational parametrization of a rational variety is equivalent with the problem of finding a transcendence basis that generates the whole extension.
An algebraic extension
L/K
L/K
An algebraic extension
L/K
A consequence of the primitive element theorem states that every finite separable extension has a primitive element (i.e. is simple).
Given any field extension
L/K
Aut(L/K)
For a given field extension
L/K
Field extensions can be generalized to ring extensions which consist of a ring and one of its subrings. A closer non-commutative analog are central simple algebras (CSAs) – ring extensions over a field, which are simple algebra (no non-trivial 2-sided ideals, just as for a field) and where the center of the ring is exactly the field. For example, the only finite field extension of the real numbers is the complex numbers, while the quaternions are a central simple algebra over the reals, and all CSAs over the reals are Brauer equivalent to the reals or the quaternions. CSAs can be further generalized to Azumaya algebras, where the base field is replaced by a commutative local ring.
Given a field extension, one can "extend scalars" on associated algebraic objects. For example, given a real vector space, one can produce a complex vector space via complexification. In addition to vector spaces, one can perform extension of scalars for associative algebras defined over the field, such as polynomials or group algebras and the associated group representations. Extension of scalars of polynomials is often used implicitly, by just considering the coefficients as being elements of a larger field, but may also be considered more formally. Extension of scalars has numerous applications, as discussed in extension of scalars: applications.