Equivalence of metrics explained
In mathematics, two metrics on the same underlying set are said to be equivalent if the resulting metric spaces share certain properties. Equivalence is a weaker notion than isometry; equivalent metrics do not have to be literally the same. Instead, it is one of several ways of generalizing equivalence of norms to general metric spaces.
Throughout the article,
will denote a non-
empty set and
and
will denote two metrics on
.
Topological equivalence
The two metrics
and
are said to be
topologically equivalent if they generate the same
topology on
. The adverb
topologically is often dropped.
[1] There are multiple ways of expressing this condition:
is
-
open if and only if it is
-open;
and any radius
, there exist radii
such that
is
continuous with continuous
inverse; that is, it is a
homeomorphism.
The following are sufficient but not necessary conditions for topological equivalence:
such that
.
[2]
, there exist positive constants
and
such that, for every point
,
Strong equivalence
Two metrics
and
on are
strongly or
bilipschitz equivalent or
uniformly equivalent if and only if there exist positive constants
and
such that, for every
,
\alphad1(x,y)\leqd2(x,y)\leq\betad1(x,y).
In contrast to the sufficient condition for topological equivalence listed above, strong equivalence requires that there is a single set of constants that holds for every pair of points in
, rather than potentially different constants associated with each point of
.
Strong equivalence of two metrics implies topological equivalence, but not vice versa. For example, the metrics
and
d2(x,y)=|\tan(x)-\tan(y)|
on the interval
are topologically equivalent, but not strongly equivalent. In fact, this interval is bounded under one of these metrics but not the other. On the other hand, strong equivalences always take bounded sets to bounded sets.
Relation with equivalence of norms
When is a vector space and the two metrics
and
are those induced by
norms
and
, respectively, then strong equivalence is equivalent to the condition that, for all
,
For linear operators between normed vector spaces,
Lipschitz continuity is equivalent to
continuity—an operator satisfying either of these conditions is called
bounded. Therefore, in this case,
and
are topologically equivalent if and only if they are strongly equivalent; the norms
and
are simply said to be equivalent.
In finite dimensional vector spaces, all metrics induced by a norm, including the euclidean metric, the taxicab metric, and the Chebyshev distance, are equivalent.
Properties preserved by equivalence
, for
a normed space and
a subset of a normed space, is preserved if either the domain or range is renormed by a strongly equivalent norm.
[4] - A metric that is strongly equivalent to a complete metric is also complete; the same is not true of equivalent metrics because homeomorphisms do not preserve completeness. For example, since
and
are homeomorphic, the homeomorphism induces a metric on
which is complete because
is, and generates the same topology as the usual one, yet
with the usual metric is not complete, because the sequence
is Cauchy but not convergent. (It is not Cauchy in the induced metric.)
References
- Book: Richard L. Bishop . Richard L. Bishop . Samuel I. Goldberg . Tensor analysis on manifolds . 1980 . Dover Publications . registration .
- Book: Carothers . N. L. . Real analysis . 2000 . Cambridge University Press . 0-521-49756-6.
- Book: Henri Cartan . Henri Cartan . Differential Calculus . 1971 . Kershaw Publishing Company LTD. . 0-395-12033-0 .
- Book: Efe Ok . Real analysis with economics applications . 2007 . Princeton University Press . 0-691-11768-3 .
Notes and References
- Bishop and Goldberg, p. 10.
- Ok, p. 137, footnote 12.
- Ok, p. 209.
- Cartan, p. 27.