Equivalence of metrics explained

In mathematics, two metrics on the same underlying set are said to be equivalent if the resulting metric spaces share certain properties. Equivalence is a weaker notion than isometry; equivalent metrics do not have to be literally the same. Instead, it is one of several ways of generalizing equivalence of norms to general metric spaces.

Throughout the article,

X

will denote a non-empty set and

d1

and

d2

will denote two metrics on

X

.

Topological equivalence

The two metrics

d1

and

d2

are said to be topologically equivalent if they generate the same topology on

X

. The adverb topologically is often dropped.[1] There are multiple ways of expressing this condition:

A\subseteqX

is

d1

-open if and only if it is

d2

-open;

x\inX

and any radius

r>0

, there exist radii

r',r''>0

such that B_ (x; d_1) \subseteq B_r (x; d_2) \text B_ (x; d_2) \subseteq B_r (x; d_1).

I:(X,d1)\to(X,d2)

is continuous with continuous inverse; that is, it is a homeomorphism.

The following are sufficient but not necessary conditions for topological equivalence:

f:\R\to\R+

such that

d2=f\circd1

.[2]

x\inX

, there exist positive constants

\alpha

and

\beta

such that, for every point

y\inX

, \alpha d_1 (x, y) \leq d_2 (x, y) \leq \beta d_1 (x, y).

Strong equivalence

Two metrics

d1

and

d2

on are strongly or bilipschitz equivalent or uniformly equivalent if and only if there exist positive constants

\alpha

and

\beta

such that, for every

x,y\inX

,

\alphad1(x,y)\leqd2(x,y)\leq\betad1(x,y).

In contrast to the sufficient condition for topological equivalence listed above, strong equivalence requires that there is a single set of constants that holds for every pair of points in

X

, rather than potentially different constants associated with each point of

X

.

Strong equivalence of two metrics implies topological equivalence, but not vice versa. For example, the metrics

d1(x,y)=|x-y|

and

d2(x,y)=|\tan(x)-\tan(y)|

on the interval
\left(-\pi,
2
\pi
2

\right)

are topologically equivalent, but not strongly equivalent. In fact, this interval is bounded under one of these metrics but not the other. On the other hand, strong equivalences always take bounded sets to bounded sets.

Relation with equivalence of norms

When is a vector space and the two metrics

d1

and

d2

are those induced by norms

\|\|A

and

\|\|B

, respectively, then strong equivalence is equivalent to the condition that, for all

x\inX

,\alpha\|x\|_A \leq \|x\|_B \leq \beta\|x\|_AFor linear operators between normed vector spaces, Lipschitz continuity is equivalent to continuity—an operator satisfying either of these conditions is called bounded. Therefore, in this case,

d1

and

d2

are topologically equivalent if and only if they are strongly equivalent; the norms

\|\|A

and

\|\|B

are simply said to be equivalent.

In finite dimensional vector spaces, all metrics induced by a norm, including the euclidean metric, the taxicab metric, and the Chebyshev distance, are equivalent.

Properties preserved by equivalence

f:U\toV

, for

V

a normed space and

U

a subset of a normed space, is preserved if either the domain or range is renormed by a strongly equivalent norm.[4]

(0,1)

and

R

are homeomorphic, the homeomorphism induces a metric on

(0,1)

which is complete because

R

is, and generates the same topology as the usual one, yet

(0,1)

with the usual metric is not complete, because the sequence

(2-n)n\inN

is Cauchy but not convergent. (It is not Cauchy in the induced metric.)

References

Notes and References

  1. Bishop and Goldberg, p. 10.
  2. Ok, p. 137, footnote 12.
  3. Ok, p. 209.
  4. Cartan, p. 27.