Spherical cap explained
In geometry, a spherical cap or spherical dome is a portion of a sphere or of a ball cut off by a plane. It is also a spherical segment of one base, i.e., bounded by a single plane. If the plane passes through the center of the sphere (forming a great circle), so that the height of the cap is equal to the radius of the sphere, the spherical cap is called a hemisphere.
Volume and surface area
The volume of the spherical cap and the area of the curved surface may be calculated using combinations of
of the sphere
of the base of the cap
of the cap
between the rays from the center of the sphere to the apex of the cap (the pole) and the edge of the
disk forming the base of the cap.
These variables are inter-related through the formulas
,
,
,and
.
| Using
and
| Using
and
| Using
and
|
---|
Volume |
[1] |
| V=
r3(2+\cos\theta)(1-\cos\theta)2
|
---|
Area |
|
|
|
---|
Constraints |
|
| 0\leq\theta\leq\pi, 0\leqr
| |
---|
If
denotes the
latitude in
geographic coordinates, then
\theta+\phi=\pi/2=90\circ
, and
.
Deriving the surface area intuitively from the spherical sector volume
Note that aside from the calculus based argument below, the area of the spherical cap may be derived from the volume
of the spherical sector, by an intuitive argument,
[2] as
The intuitive argument is based upon summing the total sector volume from that of infinitesimal
triangular pyramids. Utilizing the pyramid (or cone) volume formula of
, where
is the infinitesimal
area of each pyramidal base (located on the surface of the sphere) and
is the height of each pyramid from its base to its apex (at the center of the sphere). Since each
, in the limit, is constant and equivalent to the radius
of the sphere, the sum of the infinitesimal pyramidal bases would equal the area of the spherical sector, and:
Vsec=\sum{V}=\sum
bh'=\sum
br=
\sumb=
A
Deriving the volume and surface area using calculus
The volume and area formulas may be derived by examining the rotation of the function
f(x)=\sqrt{r2-(x-r)2}=\sqrt{2rx-x2}
for
, using the formulas the
surface of the rotation for the area and the
solid of the revolution for the volume.The area is
The derivative of
is
} and hence
The formula for the area is therefore
} \,dx = 2\pi \int_0^h r\,dx = 2\pi r \left[x\right]_0^h = 2 \pi r h The volume is
V=\pi
f(x)2dx
=\pi
(2rx-x2)dx
=\pi
=
(3r-h)
Applications
Volumes of union and intersection of two intersecting spheres
The volume of the union of two intersecting spheresof radii
and
is
[3]
where
is the sum of the volumes of the two isolated spheres, and
the sum of the volumes of the two spherical caps forming their intersection. If
is thedistance between the two sphere centers, elimination of the variables
and
leadsto
[4] [5] V(2)=
(r1+r
\left(
2)-3(r1-r
\right).
Volume of a spherical cap with a curved base
The volume of a spherical cap with a curved base can be calculated by considering two spheres with radii
and
, separated by some distance
, and for which their surfaces intersect at
. That is, the curvature of the base comes from sphere 2. The volume is thus the difference between sphere 2's cap (with height
) and sphere 1's cap (with height
),
\begin{align}
V&=
(3r1-h)-
[3r2-((r2-r1)-(d-h))],\\
V&=
(3r1-h)-
+1\right].
\end{align}
This formula is valid only for configurations that satisfy
and
. If sphere 2 is very large such that
, hence
and
, which is the case for a spherical cap with a base that has a negligible curvature, the above equation is equal to the volume of a spherical cap with a flat base, as expected.
Areas of intersecting spheres
Consider two intersecting spheres of radii
and
, with their centers separated by distance
. They intersect if
From the law of cosines, the polar angle of the spherical cap on the sphere of radius
is
Using this, the surface area of the spherical cap on the sphere of radius
is
Surface area bounded by parallel disks
The curved surface area of the spherical segment bounded by two parallel disks is the difference of surface areas of their respective spherical caps. For a sphere of radius
, and caps with heights
and
, the area is
or, using geographic coordinates with latitudes
and
,
[6] A=2\pir2|\sin\phi1-\sin\phi2|,
For example, assuming the Earth is a sphere of radius 6371 km, the surface area of the arctic (north of the Arctic Circle, at latitude 66.56° as of August 2016[7]) is = 21.04e6km2, or = 4.125% of the total surface area of the Earth.
This formula can also be used to demonstrate that half the surface area of the Earth lies between latitudes 30° South and 30° North in a spherical zone which encompasses all of the Tropics.
Generalizations
Sections of other solids
The spheroidal dome is obtained by sectioning off a portion of a spheroid so that the resulting dome is circularly symmetric (having an axis of rotation), and likewise the ellipsoidal dome is derived from the ellipsoid.
Hyperspherical cap
Generally, the
-dimensional volume of a hyperspherical cap of height
and radius
in
-dimensional Euclidean space is given by:
[8] where
(the
gamma function) is given by
.
The formula for
can be expressed in terms of the volume of the unit
n-ball and the
hypergeometric function
or the
regularized incomplete beta function
as
and the area formula
can be expressed in terms of the area of the unit n-ball
as
where
.
A. Chudnov[9] derived the following formulas: where
For odd
:
Asymptotics
If
and
, then
where
is the integral of the standard normal distribution.
[10] A more quantitative bound is
A/An=n\Theta(1) ⋅ [(2-h/r)h/r]n/2
.For large caps (that is when
as
), the bound simplifies to
.
[11] See also
Further reading
- Timothy J. . Richmond . Solvent accessible surface area and excluded volume in proteins: Analytical equation for overlapping spheres and implications for the hydrophobic effect . Journal of Molecular Biology. 1984 . 10.1016/0022-2836(84)90231-6 . 6548264 . 178 . 1 . 63–89 .
- Rolf . Lustig . Geometry of four hard fused spheres in an arbitrary spatial configuration . Molecular Physics. 1986 . 59 . 2 . 195–207 . 1986MolPh..59..195L . 10.1080/00268978600102011.
- K. D. . Gibson . Harold A. . Scheraga . Volume of the intersection of three spheres of unequal size: a simplified formula . 1987 . The Journal of Physical Chemistry. 91 . 15 . 4121–4122 . 10.1021/j100299a035.
- K. D. . Gibson . Harold A. . Scheraga . Exact calculation of the volume and surface area of fused hard-sphere molecules with unequal atomic radii . 1987 . Molecular Physics. 62 . 5 . 1247–1265 . 1987MolPh..62.1247G . 10.1080/00268978700102951.
- Michel . Petitjean . On the analytical calculation of van der Waals surfaces and volumes: some numerical aspects . Journal of Computational Chemistry. 1994 . 15 . 5 . 507–523 . 10.1002/jcc.540150504.
- J. A. . Grant . B. T. . Pickup . A Gaussian description of molecular shape . The Journal of Physical Chemistry. 1995 . 99 . 11 . 10.1021/j100011a016 . 3503–3510.
- Jan . Busa . Jozef . Dzurina . Edik . Hayryan . Shura . Hayryan . ARVO: A fortran package for computing the solvent accessible surface area and the excluded volume of overlapping spheres via analytic equations . Computer Physics Communications. 2005CoPhC.165...59B . 2005 . 165 . 1 . 59–96 . 10.1016/j.cpc.2004.08.002.
External links
Notes and References
- .
- Web site: Shekhtman . Zor . Unizor - Geometry3D - Spherical Sectors . https://ghostarchive.org/varchive/youtube/20211222/ts3J5onzvQg . 2021-12-22 . live. YouTube . Zor Shekhtman . 31 Dec 2018.
- Michael L.. Connolly. 1985. 10.1021/ja00291a006. Computation of molecular volume. Journal of the American Chemical Society. 1118–1124. 107. 5.
- 10.1016/0097-8485(82)80006-5. 1982. A method to compute the volume of a molecule. Computers & Chemistry. R.. Pavani. G.. Ranghino. 6. 3. 133–135.
- A.. Bondi. 10.1021/j100785a001. 1964. Van der Waals volumes and radii. The Journal of Physical Chemistry. 68. 3. 441–451.
- Book: Successful Software Development. Scott E. Donaldson, Stanley G. Siegel. 29 August 2016. 9780130868268. 2001.
- Web site: Obliquity of the Ecliptic (Eps Mean) . Neoprogrammics.com . 2014-05-13.
- Concise Formulas for the Area and Volume of a Hyperspherical Cap. S.. Li. Asian Journal of Mathematics and Statistics. 2011. 66-70.
- On minimax signal generation and reception algorithms (engl. transl.) . Alexander M.. Chudnov. Problems of Information Transmission. 1986. 22. 4. 49–54.
- Game-theoretical problems of synthesis of signal generation and reception algorithms (engl. transl.). Alexander M. Chudnov. Problems of Information Transmission . 1991 . 27. 3. 57–65.
- Becker . Anja . Ducas . Léo . Gama . Nicolas . Laarhoven . Thijs . 10 January 2016 . New directions in nearest neighbor searching with applications to lattice sieving . Twenty-seventh Annual ACM-SIAM Symposium on Discrete Algorithms (SODA '16), Arlington, Virginia . Krauthgamer . Robert . Society for Industrial and Applied Mathematics . Philadelphia . 10–24 . 978-1-61197-433-1 .