In the theory of computation, a branch of theoretical computer science, a deterministic finite automaton (DFA)—also known as deterministic finite acceptor (DFA), deterministic finite-state machine (DFSM), or deterministic finite-state automaton (DFSA)—is a finite-state machine that accepts or rejects a given string of symbols, by running through a state sequence uniquely determined by the string.[1] Deterministic refers to the uniqueness of the computation run. In search of the simplest models to capture finite-state machines, Warren McCulloch and Walter Pitts were among the first researchers to introduce a concept similar to finite automata in 1943.[2] [3]
The figure illustrates a deterministic finite automaton using a state diagram. In this example automaton, there are three states: S0, S1, and S2 (denoted graphically by circles). The automaton takes a finite sequence of 0s and 1s as input. For each state, there is a transition arrow leading out to a next state for both 0 and 1. Upon reading a symbol, a DFA jumps deterministically from one state to another by following the transition arrow. For example, if the automaton is currently in state S0 and the current input symbol is 1, then it deterministically jumps to state S1. A DFA has a start state (denoted graphically by an arrow coming in from nowhere) where computations begin, and a set of accept states (denoted graphically by a double circle) which help define when a computation is successful.
A DFA is defined as an abstract mathematical concept, but is often implemented in hardware and software for solving various specific problems such as lexical analysis and pattern matching. For example, a DFA can model software that decides whether or not online user input such as email addresses are syntactically valid.
DFAs have been generalized to nondeterministic finite automata (NFA) which may have several arrows of the same label starting from a state. Using the powerset construction method, every NFA can be translated to a DFA that recognizes the same language. DFAs, and NFAs as well, recognize exactly the set of regular languages.[1]
A deterministic finite automaton is a 5-tuple,, consisting of
q0\inQ
F\subseteqQ
Let be a string over the alphabet . The automaton accepts the string if a sequence of states,, exists in with the following conditions:
rn\inF
In words, the first condition says that the machine starts in the start state . The second condition says that given each character of string, the machine will transition from state to state according to the transition function . The last condition says that the machine accepts if the last input of causes the machine to halt in one of the accepting states. Otherwise, it is said that the automaton rejects the string. The set of strings that accepts is the language recognized by and this language is denoted by .
A deterministic finite automaton without accept states and without a starting state is known as a transition system or semiautomaton.
For more comprehensive introduction of the formal definition see automata theory.
The following example is of a DFA, with a binary alphabet, which requires that the input contains an even number of 0s.
where
S1 | S2 | S1 | |
S2 | S1 | S2 |
The state represents that there has been an even number of 0s in the input so far, while signifies an odd number. A 1 in the input does not change the state of the automaton. When the input ends, the state will show whether the input contained an even number of 0s or not. If the input did contain an even number of 0s, will finish in state, an accepting state, so the input string will be accepted.
The language recognized by is the regular language given by the regular expression (1*) (0 (1*) 0 (1*))*
, where *
is the Kleene star, e.g., 1*
denotes any number (possibly zero) of consecutive ones.
According to the above definition, deterministic finite automata are always complete: they define from each state a transition for each input symbol.
While this is the most common definition, some authors use the term deterministic finite automaton for a slightly different notion: an automaton that defines at most one transition for each state and each input symbol; the transition function is allowed to be partial.[4] When no transition is defined, such an automaton halts.
A local automaton is a DFA, not necessarily complete, for which all edges with the same label lead to a single vertex. Local automata accept the class of local languages, those for which membership of a word in the language is determined by a "sliding window" of length two on the word.[5] [6]
A Myhill graph over an alphabet A is a directed graph with vertex set A and subsets of vertices labelled "start" and "finish". The language accepted by a Myhill graph is the set of directed paths from a start vertex to a finish vertex: the graph thus acts as an automaton.[5] The class of languages accepted by Myhill graphs is the class of local languages.[7]
When the start state and accept states are ignored, a DFA of states and an alphabet of size can be seen as a digraph of vertices in which all vertices have out-arcs labeled (a -out digraph). It is known that when is a fixed integer, with high probability, the largest strongly connected component (SCC) in such a -out digraph chosen uniformly at random is of linear size and it can be reached by all vertices.[8] It has also been proven that if is allowed to increase as increases, then the whole digraph has a phase transition for strong connectivity similar to Erdős–Rényi model for connectivity.[9]
In a random DFA, the maximum number of vertices reachable from one vertex is very close to the number of vertices in the largest SCC with high probability.[10] This is also true for the largest induced sub-digraph of minimum in-degree one, which can be seen as a directed version of -core.
If DFAs recognize the languages that are obtained by applying an operation on the DFA recognizable languages then DFAs are said to be closed under the operation. The DFAs are closed under the following operations.
For each operation, an optimal construction with respect to the number of states has been determined in state complexity research.Since DFAs are equivalent to nondeterministic finite automata (NFA), these closures may also be proved using closure properties of NFA.
A run of a given DFA can be seen as a sequence of compositions of a very general formulation of the transition function with itself. Here we construct that function.
For a given input symbol
a\in\Sigma
\deltaa:Q → Q
\deltaa(q)=\delta(q,a)
q\inQ
\deltaa
\deltaa
\deltab
a,b\in\Sigma
\widehat\deltaab=\deltaa\circ\deltab
\circ
Clearly, this process may be recursively continued, giving the following recursive definition of
\widehat\delta:Q x \Sigma\star → Q
\widehat\delta(q,\epsilon)=q
\epsilon
\widehat\delta(q,wa)=\deltaa(\widehat\delta(q,w))
w\in\Sigma*,a\in\Sigma
q\inQ
\widehat\delta
w\in\Sigma*
\widehat\delta
Repeated function composition forms a monoid. For the transition functions, this monoid is known as the transition monoid, or sometimes the transformation semigroup. The construction can also be reversed: given a
\widehat\delta
\delta
DFAs are one of the most practical models of computation, since there is a trivial linear time, constant-space, online algorithm to simulate a DFA on a stream of input. Also, there are efficient algorithms to find a DFA recognizing:
Because DFAs can be reduced to a canonical form (minimal DFAs), there are also efficient algorithms to determine:
DFAs are equivalent in computing power to nondeterministic finite automata (NFAs). This is because, firstly any DFA is also an NFA, so an NFA can do what a DFA can do. Also, given an NFA, using the powerset construction one can build a DFA that recognizes the same language as the NFA, although the DFA could have exponentially larger number of states than the NFA.[11] [12] However, even though NFAs are computationally equivalent to DFAs, the above-mentioned problems are not necessarily solved efficiently also for NFAs. The non-universality problem for NFAs is PSPACE complete since there are small NFAs with shortest rejecting word in exponential size. A DFA is universal if and only if all states are final states, but this does not hold for NFAs. The Equality, Inclusion and Minimization Problems are also PSPACE complete since they require forming the complement of an NFA which results in an exponential blow up of size.[13]
On the other hand, finite-state automata are of strictly limited power in the languages they can recognize; many simple languages, including any problem that requires more than constant space to solve, cannot be recognized by a DFA. The classic example of a simply described language that no DFA can recognize is bracket or Dyck language, i.e., the language that consists of properly paired brackets such as word "". Intuitively, no DFA can recognize the Dyck language because DFAs are not capable of counting: a DFA-like automaton needs to have a state to represent any possible number of "currently open" parentheses, meaning it would need an unbounded number of states. Another simpler example is the language consisting of strings of the form anbn for some finite but arbitrary number of as, followed by an equal number of bs.[14]
See main article: Induction of regular languages. Given a set of positive words
S+\subset\Sigma*
S-\subset\Sigma*
S+
S-
\Sigma
S+\cupS-
Later, K. Lang proposed an extension of the TB-algorithm that does not use any assumptions about
S+
S-
S+
S-
S+
S-
S+
S-
Yet another step forward is due to application of SAT solvers by Marjin J. H. Heule and S. Verwer: the minimal DFA identification problem is reduced to deciding the satisfiability of a Boolean formula.[22] The main idea is to build an augmented prefix-tree acceptor (a trie containing all input words with corresponding labels) based on the input sets and reduce the problem of finding a DFA with
C
C
S+
S-
C!
Read-only right-moving Turing machines are a particular type of Turing machine that only moves right; theseare almost exactly equivalent to DFAs.[25] The definition based on a singly infinite tape is a 7-tuple
M=\langleQ,\Gamma,b,\Sigma,\delta,q0,F\rangle,
Q
\Gamma
b\in\Gamma
\Sigma
\Gamma
\delta:Q x \Gamma\toQ x \Gamma x \{R\}
q0\inQ
F\subseteqQ
The machine always accepts a regular language. There must exist at least one element of the set (a HALT state) for the language to be nonempty.
Current state A | Current state B | Current state C | ||||||||
tape symbol | Write symbol | Move tape | Next state | Write symbol | Move tape | Next state | Write symbol | Move tape | Next state | |
---|---|---|---|---|---|---|---|---|---|---|
0 | 1 | R | B | 1 | R | A | 1 | R | B | |
1 | 1 | R | C | 1 | R | B | 1 | N | HALT |
Q=\{A,B,C,HALT\};
\Gamma=\{0,1\};
b=0
\Sigma=\varnothing
\delta=
q0=A
F=
\{HALT\}