Q\colonK[x]\longrightarrowK[x]
x
K
To say that
Q
g(x)=f(x+a)
{(Qg)(x)=(Qf)(x+a)}.
In other words, if
f
g
Qf
Qg
a
To say that an operator reduces degree by one means that if
f
n
Qf
n-1
n=0
Qf
Sometimes a delta operator is defined to be a shift-equivariant linear transformation on polynomials in
x
x
K
(\Deltaf)(x)=f(x+1)-f(x)
is a delta operator.
infty | |
\sum | |
k=1 |
ckDk
(where Dn(ƒ) = ƒ(n) is the nth derivative) with
c1 ≠ 0
infty | |
\Delta=e | |
k=1 |
Dk | |
k! |
.
{(\deltaf)(x)={{f(x+\Deltat)-f(x)}\over{\Deltat}}},
the Euler approximation of the usual derivative with a discrete sample time
\Deltat
Every delta operator
Q
p0(x)=1;
pn(0)=0;
(Qpn)(x)=npn-1(x)foralln\inN.
Such a sequence of basic polynomials is always of binomial type, and it can be shown that no other sequences of binomial type exist. If the first two conditions above are dropped, then the third condition says this polynomial sequence is a Sheffer sequence—a more general concept.