In differential geometry, a caustic is the envelope of rays either reflected or refracted by a manifold. It is related to the concept of caustics in geometric optics. The ray's source may be a point (called the radiant) or parallel rays from a point at infinity, in which case a direction vector of the rays must be specified.
More generally, especially as applied to symplectic geometry and singularity theory, a caustic is the critical value set of a Lagrangian mapping where is a Lagrangian immersion of a Lagrangian submanifold L into a symplectic manifold M, and is a Lagrangian fibration of the symplectic manifold M. The caustic is a subset of the Lagrangian fibration's base space B.[1]
Concentration of light, especially sunlight, can burn. The word caustic, in fact, comes from the Greek καυστός, burnt, via the Latin causticus, burning.
A common situation where caustics are visible is when light shines on a drinking glass. The glass casts a shadow, but also produces a curved region of bright light. In ideal circumstances (including perfectly parallel rays, as if from a point source at infinity), a nephroid-shaped patch of light can be produced.[2] [3] Rippling caustics are commonly formed when light shines through waves on a body of water.
Another familiar caustic is the rainbow.[4] [5] Scattering of light by raindrops causes different wavelengths of light to be refracted into arcs of differing radius, producing the bow.
A catacaustic is the reflective case.
With a radiant, it is the evolute of the orthotomic of the radiant.
The planar, parallel-source-rays case: suppose the direction vector is
(a,b)
(u(t),v(t))
(-v'(t),u'(t))
2proj | ||||
|
(x-u)(bu'2-2au'v'-bv'2)=(y-v)(av'2-2bu'v'-au'2).
F(x,y,t)=(x-u)(bu'2-2au'v'-bv'2)-(y-v)(av'2-2bu'v'-au'2)
=x(bu'2-2au'v'-bv'2) -y(av'2-2bu'v'-au'2) +b(uv'2-uu'2-2vu'v') +a(-vu'2+vv'2+2uu'v')
Ft(x,y,t)=2x(bu'u''-a(u'v''+u''v')-bv'v'') -2y(av'v''-b(u''v'+u'v'')-au'u'')
+b(u'v'2+2uv'v''-u'3-2uu'u''-2u'v'2-2u''vv'-2u'vv'') +a(-v'u'2-2vu'u''+v'3+2vv'v''+2v'u'2+2v''uu'+2v'uu'')
F=Ft=0
(x,y)
Let the direction vector be (0,1) and the mirror be
(t,t2).
u'=1
u''=0
v'=2t
v''=2
a=0
b=1
F(x,y,t)=(x-t)(1-4t2)+4t(y-t2)=x(1-4t2)+4ty-t
Ft(x,y,t)=-8tx+4y-1
F=Ft=0
(0,1/4)