In applied mechanics, bending (also known as flexure) characterizes the behavior of a slender structural element subjected to an external load applied perpendicularly to a longitudinal axis of the element.
The structural element is assumed to be such that at least one of its dimensions is a small fraction, typically 1/10 or less, of the other two.[1] When the length is considerably longer than the width and the thickness, the element is called a beam. For example, a closet rod sagging under the weight of clothes on clothes hangers is an example of a beam experiencing bending. On the other hand, a shell is a structure of any geometric form where the length and the width are of the same order of magnitude but the thickness of the structure (known as the 'wall') is considerably smaller. A large diameter, but thin-walled, short tube supported at its ends and loaded laterally is an example of a shell experiencing bending.
In the absence of a qualifier, the term bending is ambiguous because bending can occur locally in all objects. Therefore, to make the usage of the term more precise, engineers refer to a specific object such as; the bending of rods, the bending of beams,[1] the bending of plates,[2] the bending of shells[3] and so on.
A beam deforms and stresses develop inside it when a transverse load is applied on it. In the quasi-static case, the amount of bending deflection and the stresses that develop are assumed not to change over time. In a horizontal beam supported at the ends and loaded downwards in the middle, the material at the over-side of the beam is compressed while the material at the underside is stretched. There are two forms of internal stresses caused by lateral loads:
These last two forces form a couple or moment as they are equal in magnitude and opposite in direction. This bending moment resists the sagging deformation characteristic of a beam experiencing bending. The stress distribution in a beam can be predicted quite accurately when some simplifying assumptions are used.
See main article: Euler–Bernoulli beam equation.
In the Euler–Bernoulli theory of slender beams, a major assumption is that 'plane sections remain plane'. In other words, any deformation due to shear across the section is not accounted for (no shear deformation). Also, this linear distribution is only applicable if the maximum stress is less than the yield stress of the material. For stresses that exceed yield, refer to article plastic bending. At yield, the maximum stress experienced in the section (at the furthest points from the neutral axis of the beam) is defined as the flexural strength.
Consider beams where the following are true:
In this case, the equation describing beam deflection (
w
\cfrac{d2w(x)}{d
| ||||
x |
where the second derivative of its deflected shape with respect to
x
E
I
M
If, in addition, the beam is homogeneous along its length as well, and not tapered (i.e. constant cross section), and deflects under an applied transverse load
q(x)
EI~\cfrac{d4w(x)}{dx4}=q(x)
After a solution for the displacement of the beam has been obtained, the bending moment (
M
Q
M(x)=-EI~\cfrac{d2w}{dx2}~;~~Q(x)=\cfrac{dM}{dx}.
Simple beam bending is often analyzed with the Euler–Bernoulli beam equation. The conditions for using simple bending theory are:[4]
Compressive and tensile forces develop in the direction of the beam axis under bending loads. These forces induce stresses on the beam. The maximum compressive stress is found at the uppermost edge of the beam while the maximum tensile stress is located at the lower edge of the beam. Since the stresses between these two opposing maxima vary linearly, there therefore exists a point on the linear path between them where there is no bending stress. The locus of these points is the neutral axis. Because of this area with no stress and the adjacent areas with low stress, using uniform cross section beams in bending is not a particularly efficient means of supporting a load as it does not use the full capacity of the beam until it is on the brink of collapse. Wide-flange beams (-beams) and truss girders effectively address this inefficiency as they minimize the amount of material in this under-stressed region.
The classic formula for determining the bending stress in a beam under simple bending is:[5]
\sigmax=
Mzy | |
Iz |
=
Mz | |
Wz |
{\sigmax}
Mz
y
Iz
Wz
Wz=Iz/y
See main article: Plastic bending. The equation
\sigma=\tfrac{My}{Ix}
The equation above is only valid if the cross-section is symmetrical. For homogeneous beams with asymmetrical sections, the maximum bending stress in the beam is given by
\sigmax(y,z)=-
Mz~Iy+My~Iyz | ||||||||||||
|
y+
My~Iz+Mz~Iyz | ||||||||||||
|
z
where
y,z
My
Mz
Iy
Iz
Iyz
My,Mz,Iy,Iz,Iyz
For large deformations of the body, the stress in the cross-section is calculated using an extended version of this formula. First the following assumptions must be made:
Large bending considerations should be implemented when the bending radius
\rho
\rho<10h.
With those assumptions the stress in large bending is calculated as:
\sigma=
F | |
A |
+
M | |
\rhoA |
+{
M | '}}y{ | |
{Ix |
\rho | |
\rho+y |
where
F
A
M
\rho
{{Ix}'}
y
y
\sigma
When bending radius
\rho
y\ll\rho
\sigma={F\overA}\pm
My | |
I |
See main article: Timoshenko beam theory. In 1921, Timoshenko improved upon the Euler–Bernoulli theory of beams by adding the effect of shear into the beam equation. The kinematic assumptions of the Timoshenko theory are:
However, normals to the axis are not required to remain perpendicular to the axis after deformation.
The equation for the quasistatic bending of a linear elastic, isotropic, homogeneous beam of constant cross-section beam under these assumptions is
EI~\cfrac{d4w}{dx4}=q(x)-\cfrac{EI}{kAG}~\cfrac{d2q}{dx2}
I
A
G
k
q(x)
\nu
k=\cfrac{5+5\nu}{6+5\nu}
The rotation (
\varphi(x)
\cfrac{d\varphi}{dx}=-\cfrac{d2w}{dx2}-\cfrac{q(x)}{kAG}
M
Q
M(x)=-EI~\cfrac{d\varphi}{dx}~;~~Q(x)=kAG\left(\cfrac{dw}{dx}-\varphi\right)=-EI~\cfrac{d2\varphi}{dx2}=\cfrac{dM}{dx}
According to Euler–Bernoulli, Timoshenko or other bending theories, the beams on elastic foundations can be explained. In some applications such as rail tracks, foundation of buildings and machines, ships on water, roots of plants etc., the beam subjected to loads is supported on continuous elastic foundations (i.e. the continuous reactions due to external loading is distributed along the length of the beam)[7] [8] [9] [10]
The dynamic bending of beams,[11] also known as flexural vibrations of beams, was first investigated by Daniel Bernoulli in the late 18th century. Bernoulli's equation of motion of a vibrating beam tended to overestimate the natural frequencies of beams and was improved marginally by Rayleigh in 1877 by the addition of a mid-plane rotation. In 1921 Stephen Timoshenko improved the theory further by incorporating the effect of shear on the dynamic response of bending beams. This allowed the theory to be used for problems involving high frequencies of vibration where the dynamic Euler–Bernoulli theory is inadequate. The Euler-Bernoulli and Timoshenko theories for the dynamic bending of beams continue to be used widely by engineers.
See main article: Euler–Bernoulli beam equation. The Euler–Bernoulli equation for the dynamic bending of slender, isotropic, homogeneous beams of constant cross-section under an applied transverse load
q(x,t)
EI~\cfrac{\partial4w}{\partialx4}+m~\cfrac{\partial2w}{\partialt2}=q(x,t)
E
I
w(x,t)
m
For the situation where there is no transverse load on the beam, the bending equation takes the form
EI~\cfrac{\partial4w}{\partialx4}+m~\cfrac{\partial2w}{\partialt2}=0
w(x,t)=Re[\hat{w}(x)~e-i\omega] \implies \cfrac{\partial2w}{\partialt2}=-\omega2~w(x,t)
EI~\cfrac{d4\hat{w}}{dx4}-m\omega2\hat{w}=0
\hat{w}=A1\cosh(\betax)+A2\sinh(\betax)+A3\cos(\betax)+A4\sin(\betax)
A1,A2,A3,A4
\beta:=\left(\cfrac{m}{EI}~\omega2\right)1/4
See main article: Timoshenko beam theory. In 1877, Rayleigh proposed an improvement to the dynamic Euler–Bernoulli beam theory by including the effect of rotational inertia of the cross-section of the beam. Timoshenko improved upon that theory in 1922 by adding the effect of shear into the beam equation. Shear deformations of the normal to the mid-surface of the beam are allowed in the Timoshenko–Rayleigh theory.
The equation for the bending of a linear elastic, isotropic, homogeneous beam of constant cross-section under these assumptions is[12] [13]
\begin{align} &EI~
\partial4w | |
\partialx4 |
+m~
\partial2w | |
\partialt2 |
-\left(J+
EIm | \right) | |
kAG |
\partial4w | |
\partialx2~\partialt2 |
+
Jm | ~ | |
kAG |
\partial4w | |
\partialt4 |
\\[6pt] ={}&q(x,t)+
J | ~ | |
kAG |
\partial2q | |
\partialt2 |
-
EI | ~ | |
kAG |
\partial2q | |
\partialx2 |
\end{align}
where
J=\tfrac{mI}{A}
m=\rhoA
\rho
A
G
k
\nu
\begin{align} k&=
5+5\nu | |
6+5\nu |
rectangularcross-section\\[6pt] &=
6+12\nu+6\nu2 | |
7+12\nu+4\nu2 |
circularcross-section \end{align}
For free, harmonic vibrations the Timoshenko–Rayleigh equations take the form
EI~\cfrac{d4\hat{w}}{dx4}+m\omega2\left(\cfrac{J}{m}+\cfrac{EI}{kAG}\right)\cfrac{d2\hat{w}}{dx2}+m\omega2\left(\cfrac{\omega2J}{kAG}-1\right)~\hat{w}=0
w
ekx
\alpha~k4+\beta~k2+\gamma=0~;~~\alpha:=EI~,~~\beta:=m\omega2\left(\cfrac{J}{m}+\cfrac{EI}{kAG}\right)~,~~\gamma:=m\omega2\left(\cfrac{\omega2J}{kAG}-1\right)
k1=+\sqrt{z+}~,~~k2=-\sqrt{z+}~,~~k3=+\sqrt{z-}~,~~k4=-\sqrt{z-}
z+:=\cfrac{-\beta+\sqrt{\beta2-4\alpha\gamma}}{2\alpha}~,~~ z-:=\cfrac{-\beta-\sqrt{\beta2-4\alpha\gamma}}{2\alpha}
\hat{w}=
k1x | |
A | |
1~e |
+
-k1x | |
A | |
2~e |
+
k3x | |
A | |
3~e |
+
-k3x | |
A | |
4~e |
See main article: Plate theory.
The defining feature of beams is that one of the dimensions is much larger than the other two. A structure is called a plate when it is flat and one of its dimensions is much smaller than the other two. There are several theories that attempt to describe the deformation and stress in a plate under applied loads two of which have been used widely. These are
The assumptions of Kirchhoff–Love theory are
These assumptions imply that
\begin{align} u\alpha(x)&=-
x | ||||
|
=-
0 | |
x | |
,\alpha |
~;~~\alpha=1,2\\ u3(x)&=
0(x | |
w | |
1, |
x2) \end{align}
u
w0
The strain-displacement relations are
\begin{align} \varepsilon\alpha\beta&= -
0 | |
x | |
,\alpha\beta |
\\ \varepsilon\alpha&=0\\ \varepsilon33&=0 \end{align}
The equilibrium equations are
M\alpha\beta,\alpha\beta+q(x)=0~;~~M\alpha\beta:=
h | |
\int | |
-h |
x3~\sigma\alpha\beta~dx3
q(x)
In terms of displacements, the equilibrium equations for an isotropic, linear elastic plate in the absence of external load can be written as
0 | |
w | |
,1111 |
+
0 | |
2~w | |
,1212 |
+
0 | |
w | |
,2222 |
=0
\nabla2\nabla2w=0
The special assumption of this theory is that normals to the mid-surface remain straight and inextensible but not necessarily normal to the mid-surface after deformation. The displacements of the plate are given by
\begin{align} u\alpha(x)&=-x3~\varphi\alpha~;~~\alpha=1,2\\ u3(x)&=
0(x | |
w | |
1, |
x2) \end{align}
\varphi\alpha
The strain-displacement relations that result from these assumptions are
\begin{align} \varepsilon\alpha\beta&= -x3~\varphi\alpha,\beta\\ \varepsilon\alpha&=
0 | |
\cfrac{1}{2}~\kappa\left(w | |
,\alpha |
-\varphi\alpha\right)\\ \varepsilon33&=0 \end{align}
\kappa
The equilibrium equations are
\begin{align} &M\alpha\beta,\beta-Q\alpha=0\\ &Q\alpha,\alpha+q=0 \end{align}
Q\alpha:=
h | |
\kappa~\int | |
-h |
\sigma\alpha~dx3
See main article: Plate theory.
The dynamic theory of plates determines the propagation of waves in the plates, and the study of standing waves and vibration modes. The equations that govern the dynamic bending of Kirchhoff plates are
M\alpha\beta,\alpha\beta-q(x,t)=
0 | |
J | |
1~\ddot{w} |
-
0 | |
J | |
,\alpha\alpha |
\rho=\rho(x)
J1:=
h | |
\int | |
-h |
\rho~dx3~;~~ J3:=
h | |
\int | |
-h |
2~\rho~dx | |
x | |
3 |
\ddot{w}0=
\partial2w0 | |
\partialt2 |
~;~~
0 | |
\ddot{w} | |
,\alpha\beta |
=
\partial2\ddot{w | |
0}{\partial |
x\alpha\partialx\beta}
The figures below show some vibrational modes of a circular plate.