In the mathematical discipline of complex analysis, the analytic capacity of a compact subset K of the complex plane is a number that denotes "how big" a bounded analytic function on C \ K can become. Roughly speaking, γ(K) measures the size of the unit ball of the space of bounded analytic functions outside K.
It was first introduced by Lars Ahlfors in the 1940s while studying the removability of singularities of bounded analytic functions.
Let K ⊂ C be compact. Then its analytic capacity is defined to be
\gamma(K)=\sup\{|f'(infty)|; f\inl{H}infty(C\setminusK), \|f\|infty\leq1, f(infty)=0\}
Here,
l{H}infty(U)
f'(infty):=\limz\toinftyz\left(f(z)-f(infty)\right)
f(infty):=\limz\toinftyf(z)
Note that
f'(infty)=g'(0)
g(z)=f(1/z)
f'(infty) ≠ \limz\toinftyf'(z)
Equivalently, the analytic capacity may be defined as
\gamma(K)=\sup\left|
| 1{2\pi} | |
| \int |
Cf(z)dz\right|
f(infty)=0.
If A ⊂ C is an arbitrary set, then we define
\gamma(A)=\sup\{\gamma(K):K\subsetA,Kcompact\}.
The compact set K is called removable if, whenever Ω is an open set containing K, every function which is bounded and holomorphic on the set Ω \ K has an analytic extension to all of Ω. By Riemann's theorem for removable singularities, every singleton is removable. This motivated Painlevé to pose a more general question in 1880: "Which subsets of C are removable?"
It is easy to see that K is removable if and only if γ(K) = 0. However, analytic capacity is a purely complex-analytic concept, and much more work needs to be done in order to obtain a more geometric characterization.
For each compact K ⊂ C, there exists a unique extremal function, i.e.
f\inl{H}infty(C\setminusK)
\|f\|\leq1
Let dimH denote Hausdorff dimension and H1 denote 1-dimensional Hausdorff measure. Then H1(K) = 0 implies γ(K) = 0 while dimH(K) > 1 guarantees γ(K) > 0. However, the case when dimH(K) = 1 and H1(K) ∈ (0, ∞] is more difficult.
Given the partial correspondence between the 1-dimensional Hausdorff measure of a compact subset of C and its analytic capacity, it might be conjectured that γ(K) = 0 implies H1(K) = 0. However, this conjecture is false. A counterexample was first given by A. G. Vitushkin, and a much simpler one by John B. Garnett in his 1970 paper. This latter example is the linear four corners Cantor set, constructed as follows:
Let K0 := [0, 1] × [0, 1] be the unit square. Then, K1 is the union of 4 squares of side length 1/4 and these squares are located in the corners of K0. In general, Kn is the union of 4n squares (denoted by
| j | |
| Q | |
| n |
| j | |
| Q | |
| n |
| k | |
| Q | |
| n-1 |
H1(K)=\sqrt{2}
Let K ⊂ C be a compact set. Vitushkin's conjecture states that
\gamma(K)=0 \iff
| \pi | |
| \int | |
| 0 |
| 1(\operatorname{proj} | |
| lH | |
| \theta(K)) |
d\theta=0
where
\operatorname{proj}\theta(x,y):=x\cos\theta+y\sin\theta
Guy David published a proof in 1998 of Vitushkin's conjecture for the case dimHK = 1 and H1(K) < ∞. In 2002, Xavier Tolsa proved that analytic capacity is countably semiadditive. That is, there exists an absolute constant C > 0 such that if K ⊂ C is a compact set and
K=
| infty | |
| cup | |
| i=1 |
Ki
\gamma(K)\leqC
| infty\gamma(K | |
| \sum | |
| i) |
David's and Tolsa's theorems together imply that Vitushkin's conjecture is true when K is H1-sigma-finite.
In the non H1-sigma-finite case, Pertti Mattila proved in 1986[1] that the conjecture is false, but his proof did not specify which implication of the conjecture fails. Subsequent work by Jones and Muray[2] produced an example of a set with zero Favard length and positive analytic capacity, explicitly disproving one of the directions of the conjecture. As of 2023 it is not known whether the other implication holds but some progress has been made towards a positive answer by Chang and Tolsa.[3]