Wirtinger's inequality for functions explained

For other inequalities named after Wirtinger, see Wirtinger's inequality.

In the mathematical field of analysis, the Wirtinger inequality is an important inequality for functions of a single variable, named after Wilhelm Wirtinger. It was used by Adolf Hurwitz in 1901 to give a new proof of the isoperimetric inequality for curves in the plane. A variety of closely related results are today known as Wirtinger's inequality, all of which can be viewed as certain forms of the Poincaré inequality.

Theorem

There are several inequivalent versions of the Wirtinger inequality:

L
\int
0
2dx\leqL2
4\pi2
y(x)
L
\int
0

y'(x)2dx,

and equality holds if and only if for some numbers and .

L
\int
0
2dx\leqL2
\pi2
y(x)
L
\int
0

y'(x)2dx,

and equality holds if and only if for some number .

L
\int
0

y(x)2dx\leq

L2
\pi2
L
\int
0

y'(x)2dx.

and equality holds if and only if for some number .Despite their differences, these are closely related to one another, as can be seen from the account given below in terms of spectral geometry. They can also all be regarded as special cases of various forms of the Poincaré inequality, with the optimal Poincaré constant identified explicitly. The middle version is also a special case of the Friedrichs inequality, again with the optimal constant identified.

Proofs

The three versions of the Wirtinger inequality can all be proved by various means. This is illustrated in the following by a different kind of proof for each of the three Wirtinger inequalities given above. In each case, by a linear change of variables in the integrals involved, there is no loss of generality in only proving the theorem for one particular choice of .

Fourier series

Consider the first Wirtinger inequality given above. Take to be . Since Dirichlet's conditions are met, we can write

y(x)=1
2

a0+\sumn\ge

\left(a
n\sinnx
\sqrt{\pi
}+b_n\frac\right),and the fact that the average value of is zero means that . By Parseval's identity,
2\pi
\int
0
2)
y(x)
n

and

2\pi
\int
0

y'(x)2dx=

infty
\sum
n=1
2)
n
n

and since the summands are all nonnegative, the Wirtinger inequality is proved. Furthermore it is seen that equality holds if and only if for all, which is to say that . This is equivalent to the stated condition by use of the trigonometric addition formulas.

Integration by parts

Consider the second Wirtinger inequality given above. Take to be . Any differentiable function satisfies the identity

y(x)2+(y'(x)-y(x)\cotx)2=y'(x)

2-d
dx

(y(x)2\cotx).

Integration using the fundamental theorem of calculus and the boundary conditions then shows
\pi
\int
0
\pi(y'(x)-y(x)\cot
y(x)
0
\pi
x)
0

y'(x)2dx.

This proves the Wirtinger inequality, since the second integral is clearly nonnegative. Furthermore, equality in the Wirtinger inequality is seen to be equivalent to, the general solution of which (as computed by separation of variables) is for an arbitrary number .

There is a subtlety in the above application of the fundamental theorem of calculus, since it is not the case that extends continuously to and for every function . This is resolved as follows. It follows from the Hölder inequality and that

x
|y(x)|=\left|\int
0
x
y'(x)dx\right|\leq\int
0
x
|y'(x)|dx\leq\sqrt{x}\left(\int
0

y'(x)2dx\right)1/2,

which shows that as long as
\pi
\int
0

y'(x)2dx

is finite, the limit of as converges to zero is zero. Since for small positive values of, it follows from the squeeze theorem that converges to zero as converges to zero. In exactly the same way, it can be proved that converges to zero as converges to .

Functional analysis

Consider the third Wirtinger inequality given above. Take to be . Given a continuous function on of average value zero, let denote the function on which is of average value zero, and with and . From basic analysis of ordinary differential equations with constant coefficients, the eigenvalues of are for nonzero integers, the largest of which is then . Because is a bounded and self-adjoint operator, it follows that

1
\int
0

Tf(x)2dx\leq\pi-2

1
\intf(x)Tf(x)dx=
0
1
\pi2
1
\int
0

(Tf)'(x)2dx

for all of average value zero, where the equality is due to integration by parts. Finally, for any continuously differentiable function on of average value zero, let be a sequence of compactly supported continuously differentiable functions on which converge in to . Then define

yn(x)=\int

x
0

gn(z)dz-\int

1
0
w
\int
0

gn(z)dzdw.

Then each has average value zero with, which in turn implies that has average value zero. So application of the above inequality to is legitimate and shows that
1
\int
0
2dx\leq1
\pi2
y
n(x)
1
\int
0
2dx.
y
n'(x)
It is possible to replace by, and thereby prove the Wirtinger inequality, as soon as it is verified that converges in to . This is verified in a standard way, by writing

y(x)-yn(x)=\int

x
0

(yn'(z)-gn(z))dz-\int

w
0

(yn'(z)-gn(z))dzdw

and applying the Hölder or Jensen inequalities.

This proves the Wirtinger inequality. In the case that is a function for which equality in the Wirtinger inequality holds, then a standard argument in the calculus of variations says that must be a weak solution of the Euler–Lagrange equation with, and the regularity theory of such equations, followed by the usual analysis of ordinary differential equations with constant coefficients, shows that for some number .

To make this argument fully formal and precise, it is necessary to be more careful about the function spaces in question.

Spectral geometry

In the language of spectral geometry, the three versions of the Wirtinger inequality above can be rephrased as theorems about the first eigenvalue and corresponding eigenfunctions of the Laplace–Beltrami operator on various one-dimensional Riemannian manifolds:

These can also be extended to statements about higher-dimensional spaces. For example, the Riemannian circle may be viewed as the one-dimensional version of either a sphere, real projective space, or torus (of arbitrary dimension). The Wirtinger inequality, in the first version given here, can then be seen as the case of any of the following:

The second and third versions of the Wirtinger inequality can be extended to statements about first Dirichlet and Neumann eigenvalues of the Laplace−Beltrami operator on metric balls in Euclidean space:

Application to the isoperimetric inequality

In the first form given above, the Wirtinger inequality can be used to prove the isoperimetric inequality for curves in the plane, as found by Adolf Hurwitz in 1901. Let be a differentiable embedding of the circle in the plane. Parametrizing the circle by so that has constant speed, the length of the curve is given by

2\pi
\int
0

\sqrt{x'(t)2+y'(t)2}dt

and the area enclosed by the curve is given (due to Stokes theorem) by
2\pi
-\int
0

y(t)x'(t)dt.

Since the integrand of the integral defining is assumed constant, there is
L2
2\pi
2\pi
-2A=\int
0

(x'(t)2+y'(t)2+2y(t)x'(t))dt

which can be rewritten as
2\pi
\int
0
2\pi
(x'(t)+y(t))
0

(y'(t)2-y(t)2)dt.

The first integral is clearly nonnegative. Without changing the area or length of the curve, can be replaced by for some number, so as to make have average value zero. Then the Wirtinger inequality can be applied to see that the second integral is also nonnegative, and therefore
L2
4\pi

\geqA,

which is the isoperimetric inequality. Furthermore, equality in the isoperimetric inequality implies both equality in the Wirtinger inequality and also the equality, which amounts to and then for arbitrary numbers and . These equations mean that the image of is a round circle in the plane.

References