Weibel instability explained

The Weibel instability is a plasma instability present in homogeneous or nearly homogeneous electromagnetic plasmas which possess an anisotropy in momentum (velocity) space. This anisotropy is most generally understood as two temperatures in different directions. Burton Fried showed that this instability can be understood more simply as the superposition of many counter-streaming beams. In this sense, it is like the two-stream instability except that the perturbations are electromagnetic and result in filamentation as opposed to electrostatic perturbations which would result in charge bunching. In the linear limit the instability causes exponential growth of electromagnetic fields in the plasma which help restore momentum space isotropy. In very extreme cases, the Weibel instability is related to one- or two-dimensional stream instabilities.

Consider an electron-ion plasma in which the ions are fixed and the electrons are hotter in the y-direction than in x or z-direction.

To see how magnetic field perturbation would grow, suppose a field B = B cos kx spontaneously arises from noise. The Lorentz force then bends the electron trajectories with the result that upward-moving-ev x B electrons congregate at B and downward-moving ones at A. The resulting current

j=-enve

sheets generate magnetic field that enhances the original field and thus perturbation grows.

Weibel instability is also common in astrophysical plasmas, such as collisionless shock formation in supernova remnants and

\gamma

-ray bursts.

A Simple Example of Weibel Instability

As a simple example of Weibel instability, consider an electron beam with density

nb0

and initial velocity

v0z

propagating in a plasma of density

np0=nb0

with velocity

-v0z

. The analysis below will show how an electromagnetic perturbation in the form of a plane wave gives rise to a Weibel instability in this simple anisotropic plasma system. We assume a non-relativistic plasma for simplicity.

We assume there is no background electric or magnetic field i.e.

B0

=

E0

=0

. The perturbation will be taken as an electromagnetic wave propagating along

\hat{x

} i.e.

k=k\hat{x

}. Assume the electric field has the form
E1

=Aei(kx-\omegaz

With the assumed spatial and time dependence, we may use

\partial
\partialt

-i\omega

and

\nablaik\hat{x

} . From Faraday's Law, we may obtain the perturbation magnetic field

\nabla x

E1

=-

\partial
B1
\partialt

ik x

E1

=i\omega

B1

B1

=\hat{y

} \frac E_1

Consider the electron beam. We assume small perturbations, and so linearize the velocity

vb

=

vb0

+

vb1
and density

nb=nb0+nb1

. The goal is to find the perturbation electron beam current density
Jb1

=-enb

vb

=-enb0

vb1

-enb1

vb0

where second-order terms have been neglected. To do that, we start with the fluid momentum equation for the electron beam

m(
\partial
vb
\partialt

+

(vb

\nabla)

vb)

=-eE-e

vb

x B

which can be simplified by noting that

\partial
vb0
\partialt

=\nabla

vb0

=0

and neglecting second-order terms. With the plane wave assumption for the derivatives, the momentum equation becomes

-i\omegam

vb1

=-e

E1

-e

vb0

x

B1

We can decompose the above equations in components, paying attention to the cross product at the far right, and obtain the non-zero components of the beam velocity perturbation:

vb1z=

eE1
mi\omega

vb1x=

eE1
mi\omega
kvb0
\omega

To find the perturbation density

nb1

, we use the fluid continuity equation for the electron beam
\partialnb
\partialt

+\nabla(nb

vb)

=0

which can again be simplified by noting that

\partialnb0
\partialt

=\nablanb0=0

and neglecting second-order terms. The result is

nb1=nb0

k
\omega

vb1x

Using these results, we may use the equation for the beam perturbation current density given above to find

Jb1x=-nb0e2E1

kvb0
im\omega2

Jb1z=-nb0e2E1

1
im\omega

(1+

2
k
2
v
b0
\omega2

)

Analogous expressions can be written for the perturbation current density of the left-moving plasma. By noting that the x-component of the perturbation current density is proportional to

v0

, we see that with our assumptions for the beam and plasma unperturbed densities and velocities the x-component of the net current density will vanish, whereas the z-components, which are proportional to
2
v
0
, will add. The net current density perturbation is therefore
J1

=-2nb0e2E1

1
im\omega

(1+

2
k
2
v
b0
\omega2

)\hat{z

}

The dispersion relation can now be found from Maxwell's Equations:

\nabla x

E1

=i\omega

B1

\nabla x

B1

=\mu0

J1

-i\omega\epsilon0\mu0

E1

\nabla x \nabla x

E1

=-\nabla2

E1

+\nabla(\nabla

E1)

=k2

E1

+ik(ik

E1)

=k2

E1

=i\omega\nabla x

B1

=

i\omega
c2\epsilon0
J1

+

\omega2
c2
E1

where

c=

1
\sqrt{\epsilon0\mu0
} is the speed of light in free space. By defining the effective plasma frequency
2
\omega
p

=

2nb0e2
\epsilon0m

, the equation above results in

k2-

\omega2
c2

=-

2
\omega
p
(1+
c2
2
k
0
\omega2

)\omega4-\omega2

2
(\omega
p

+k2c2)-

2
\omega
p

k2

2
v
0

=0

This bi-quadratic equation may be easily solved to give the dispersion relation

\omega2=

1
2
2
(\omega
p

+k2c2\pm

2+k
\sqrt{(\omega
p

2c2)2+4

2
\omega
p

k2

2}
v
0

)

In the search for instabilities, we look for

Im(\omega)0

(

k

is assumed real). Therefore, we must take the dispersion relation/mode corresponding to the minus sign in the equation above.

To gain further insight on the instability, it is useful to harness our non-relativistic assumption

v0<<c

to simplify the square root term, by noting that
2+k
\sqrt{(\omega
p

2c2)2+4

2
\omega
p

k2

2}
v
0

=

2
(\omega
p

+k2c2)(1+

4
2k
\omega
p
2
0
2+k
(\omega2c2)2
p

)1/2

2
(\omega
p

+k2c2)(1+

2
2k
\omega
p
2
0
2+k
(\omega2c2)2
p

)

The resulting dispersion relation is then much simpler

\omega2=

2
-\omegak2
2
v
0
p
2
\omega+k2c2
p

<0

\omega

is purely imaginary. Writing

\omega=i\gamma

\gamma=

\omegapkv0
2+k
(\omega2c2)1/2
p

=\omegap

v0
c
1
(1+
2
\omega
p
)1/2
k2c2

we see that

Im(\omega)>0

, indeed corresponding to an instability.

The electromagnetic fields then have the form

E1

=A\hat{z

} e^ e^
B1

=\hat{y

} \frac E_1 = \mathbf \frac A e^ e^

Therefore, the electric and magnetic fields are

90o

out of phase, and by noting that
|B1|
|E1|

=

k
\gamma

\propto

c
v0

>>1

so we see this is a primarily magnetic perturbation although there is a non-zero electric perturbation. The magnetic field growth results in the characteristic filamentation structure of Weibel instability. Saturation will happen when the growth rate

\gamma

is on the order of the electron cyclotron frequency

\gamma\sim\omegap

v0
c

\sim\omegacB\sim

m
e

\omegap

v0
c

References

See also