Weak convergence (Hilbert space) explained
In mathematics, weak convergence in a Hilbert space is convergence of a sequence of points in the weak topology.
Definition
A sequence of points
in a Hilbert space
H is said to
converge weakly to a point
x in
H if
\limn\toinfty\langlexn,y\rangle=\langlex,y\rangle
for all y in H. Here,
is understood to be the
inner product on the Hilbert space. The notation
is sometimes used to denote this kind of convergence.
Properties
- If a sequence converges strongly (that is, if it converges in norm), then it converges weakly as well.
in a Hilbert space
H contains a weakly convergent subsequence. Note that closed and bounded sets are not in general weakly compact in Hilbert spaces (consider the set consisting of an
orthonormal basis in an infinite-dimensional Hilbert space which is closed and bounded but not weakly compact since it doesn't contain 0). However, bounded and weakly closed sets are weakly compact so as a consequence every convex bounded closed set is weakly compact.
- As a consequence of the principle of uniform boundedness, every weakly convergent sequence is bounded.
- The norm is (sequentially) weakly lower-semicontinuous: if
converges weakly to
x, then
\Vertx\Vert\le\liminfn\toinfty\Vertxn\Vert,
and this inequality is strict whenever the convergence is not strong. For example, infinite orthonormal sequences converge weakly to zero, as demonstrated below.
weakly and
\lVertxn\rVert\to\lVertx\rVert
, then
strongly:
\langlex-xn,x-xn\rangle=\langlex,x\rangle+\langlexn,xn\rangle-\langlexn,x\rangle-\langlex,xn\rangle → 0.
- If the Hilbert space is finite-dimensional, i.e. a Euclidean space, then weak and strong convergence are equivalent.
Example
The Hilbert space
is the space of the
square-integrable functions on the interval
equipped with the inner product defined by
\langlef,g\rangle=
f(x) ⋅ g(x)dx,
(see
Lp space). The sequence of functions
defined by
converges weakly to the zero function in
, as the integral
tends to zero for any square-integrable function
on
when
goes to infinity, which is by
Riemann–Lebesgue lemma, i.e.
\langlefn,g\rangle\to\langle0,g\rangle=0.
Although
has an increasing number of 0's in
as
goes to infinity, it is of course not equal to the zero function for any
. Note that
does not converge to 0 in the
or
norms. This dissimilarity is one of the reasons why this type of convergence is considered to be "weak."
Weak convergence of orthonormal sequences
Consider a sequence
which was constructed to be orthonormal, that is,
\langleen,em\rangle=\deltamn
where
equals one if
m =
n and zero otherwise. We claim that if the sequence is infinite, then it converges weakly to zero. A simple proof is as follows. For
x ∈
H, we have
\sumn|\langleen,x\rangle|2\leq\|x\|2
(
Bessel's inequality)
where equality holds when is a Hilbert space basis. Therefore
|\langleen,x\rangle|2 → 0
(since the series above converges, its corresponding sequence must go to zero)
i.e.
Banach–Saks theorem
The Banach–Saks theorem states that every bounded sequence
contains a subsequence
and a point
x such that
converges strongly to x as N goes to infinity.
Generalizations
See also: Weak topology and Weak topology (polar topology).
The definition of weak convergence can be extended to Banach spaces. A sequence of points
in a Banach space
B is said to
converge weakly to a point
x in
B if
for any bounded linear
functional
defined on
, that is, for any
in the
dual space
. If
is an
Lp space on
and
, then any such
has the form
for some
, where
is the
measure on
and
are
conjugate indices.
In the case where
is a Hilbert space, then, by the
Riesz representation theorem,
for some
in
, so one obtains the Hilbert space definition of weak convergence.
See also