A two-dimensional elastic membrane under tension can support transverse vibrations. The properties of an idealized drumhead can be modeled by the vibrations of a circular membrane of uniform thickness, attached to a rigid frame. Due to the phenomenon of resonance, at certain vibration frequencies, its resonant frequencies, the membrane can store vibrational energy, the surface moving in a characteristic pattern of standing waves. This is called a normal mode. A membrane has an infinite number of these normal modes, starting with a lowest frequency one called the fundamental mode.
There exist infinitely many ways in which a membrane can vibrate, each depending on the shape of the membrane at some initial time, and the transverse velocity of each point on the membrane at that time. The vibrations of the membrane are given by the solutions of the two-dimensional wave equation with Dirichlet boundary conditions which represent the constraint of the frame. It can be shown that any arbitrarily complex vibration of the membrane can be decomposed into a possibly infinite series of the membrane's normal modes. This is analogous to the decomposition of a time signal into a Fourier series.
The study of vibrations on drums led mathematicians to pose a famous mathematical problem on whether the shape of a drum can be heard, with an answer (it cannot) being given in 1992 in the two-dimensional setting.
Analyzing the vibrating drum head problem explains percussion instruments such as drums and timpani. However, there is also a biological application in the working of the eardrum. From an educational point of view the modes of a two-dimensional object are a convenient way to visually demonstrate the meaning of modes, nodes, antinodes and even quantum numbers. These concepts are important to the understanding of the structure of the atom.
\Omega
a
t,
(x,y)
\Omega
u(x,y,t),
\partial\Omega
\Omega,
a
The mathematical equation that governs the vibration of the drum head is the wave equation with zero boundary conditions,
\partial2u | |
\partialt2 |
=c2\left(
\partial2u | + | |
\partialx2 |
\partial2u | |
\partialy2 |
\right)for(x,y)\in\Omega
u=0on\partial\Omega.
Due to the circular geometry of
\Omega
(r,\theta).
\partial2u | |
\partialt2 |
=c2\left(
\partial2u | + | |
\partialr2 |
1 | |
r |
\partialu | + | |
\partialr |
1 | |
r2 |
\partial2u | |
\partial\theta2 |
\right)for0\ler<a,0\le\theta\le2\pi
u=0forr=a.
Here,
c
c=\sqrt{
| |||||||
\rhoh |
where
* | |
N | |
rr |
r=a
h
\rho
r
F=
r | |
rN | |
rr |
r | |
=rN | |
\theta\theta |
where
r | |
N | |
\theta\theta |
=
r | |
N | |
rr |
We will first study the possible modes of vibration of a circular drum head that are axisymmetric. Then, the function
u
\theta,
\partial2u | |
\partialt2 |
=c2\left(
\partial2u | + | |
\partialr2 |
1 | |
r |
\partialu | |
\partialr |
\right).
We will look for solutions in separated variables,
u(r,t)=R(r)T(t).
c2R(r)T(t)
T''(t) | |
c2T(t) |
=
1 | |
R(r) |
\left(R''(r)+
1 | |
r |
R'(r)\right).
The left-hand side of this equality does not depend on
r,
t,
K.
T(t)
R(r)
T''(t)=Kc2T(t)
rR''(r)+R'(r)-KrR(r)=0.
The equation for
T(t)
K>0,
K=0
K<0
K<0,
K=-λ2
T(t)
T(t)=A\coscλt+B\sincλt.
Turning to the equation for
R(r),
K=-λ2,
R(r)=c1J0(λr)+c2Y0(λr).
The Bessel function
Y0
r\to0,
c2
c1=1,
A
B
T(t).
R(r)=J0(λr).
The requirement that height
u
R(a)=J0(λa)=0.
The Bessel function
J0
0<\alpha01<\alpha02< …
We get that
λa=\alpha0n,
n=1,2,...,
R(r)=
J | ||||
|
r\right).
Therefore, the axisymmetric solutions
u
u0n(r,t)=\left(A\coscλ0nt+B\sincλ0nt\right)J0\left(λ0nr\right)forn=1,2,...,
where
λ0n=\alpha0n/a.
The general case, when
u
\theta,
u(r,\theta,t)=R(r)\Theta(\theta)T(t).
Substituting this into the wave equation and separating the variables, gives
T''(t) | |
c2T(t) |
=
R''(r) | + | |
R(r) |
R'(r) | |
rR(r) |
+
\Theta''(\theta) | |
r2\Theta(\theta) |
=K
where
K
T(t)
K=-λ2
λ>0
T(t)=A\coscλt+B\sincλt.
From the equation
R''(r) | + | |
R(r) |
R'(r) | |
rR(r) |
+
\Theta''(\theta) | |
r2\Theta(\theta) |
=-λ2
we obtain, by multiplying both sides by
r2
λ2r
| |||||
+ |
rR'(r) | |
R(r) |
=L
and
- | \Theta''(\theta) |
\Theta(\theta) |
=L,
for some constant
L.
\Theta(\theta)
2\pi,
\theta
\Theta(\theta)=C\cosm\theta+D\sinm\theta,
where
m=0,1,...
C
D
L=m2.
Going back to the equation for
R(r),
Jm
Ym.
R(r)=Jm(λmnr),
m=0,1,...,
n=1,2,...,
where
λmn=\alphamn/a,
\alphamn
n
Jm.
We showed that all solutions in separated variables of the vibrating drum head problem are of the form
umn(r,\theta,t)=\left(A\coscλmnt+B\sincλmnt\right)Jm\left(λmnr\right)(C\cosm\theta+D\sinm\theta)
for
m=0,1,...,n=1,2,...
A number of modes are shown below together with their quantum numbers. The analogous wave functions of the hydrogen atom are also indicated as well as the associated angular frequencies
\omegamn=λmnc=\dfrac{\alphamn
\alphamn
Jm
\forall\theta\in[0,2\pi],\forallt, umn(r=a,\theta,t)=0
Jm(λmna)=Jm(\alphamn)=0
More values of
\alphamn
scipy
library:[1]