Vanadium(III) bromide, also known as vanadium tribromide, describes the inorganic compounds with the formula VBr3 and its hydrates. The anhydrous material is a green-black solid. In terms of its structure, the compound is polymeric with octahedral vanadium(III) surrounded by six bromide ligands.
VBr3 has been prepared by treatment of vanadium tetrachloride with hydrogen bromide:
2 VCl4 + 8 HBr → 2 VBr3 + 8 HCl + Br2The reaction proceeds via the unstable vanadium(IV) bromide (VBr4), which releases Br2 near room temperature.[1]
It is also possible to prepare vanadium(III) bromide by reacting bromine with vanadium or ferrovanadine:[2]
2 V + 3 Br2 → 2 VBr3
2 VFe + 6 Br2 → 2 VBr3 + FeBr3
Vanadium(III) bromide is present in the form of black, leafy, very hygroscopic crystals with a sometimes greenish sheen. It is soluble in water with green color. Its crystal structure is isotypic to that of vanadium(III) chloride with space group Rc (space group no. 167), a = 6.400 Å, c = 18.53 Å. When heated to temperatures of around 500 °C, a violet gas phase is formed, from which, under suitable conditions, red vanadium(IV) bromide can be separated by rapid cooling, which decomposes at −23 °C.
Like vanadium(III) chloride, vanadium(III) bromide forms red-brown soluble complexes with dimethoxyethane and THF, such as mer-VBr3(THF)3.[3]
Aqueous solutions prepared from VBr3 contain the cation trans-[VBr<sub>2</sub>(H<sub>2</sub>O)<sub>4</sub>]+. Evaporation of these solutions give the salt trans-[VBr<sub>2</sub>(H<sub>2</sub>O)<sub>4</sub>]Br.(H2O)2.[4]