In probability theory and statistics, the Van Houtum distribution is a discrete probability distribution named after prof. Geert-Jan van Houtum.[1] It can be characterized by saying that all values of a finite set of possible values are equally probable, except for the smallest and largest element of this set. Since the Van Houtum distribution is a generalization of the discrete uniform distribution, i.e. it is uniform except possibly at its boundaries, it is sometimes also referred to as quasi-uniform.
It is regularly the case that the only available information concerning some discrete random variable are its first two moments. The Van Houtum distribution can be used to fit a distribution with finite support on these moments.
A simple example of the Van Houtum distribution arises when throwing a loaded dice which has been tampered with to land on a 6 twice as often as on a 1. The possible values of the sample space are 1, 2, 3, 4, 5 and 6. Each time the die is thrown, the probability of throwing a 2, 3, 4 or 5 is 1/6; the probability of a 1 is 1/9 and the probability of throwing a 6 is 2/9.
A random variable U has a Van Houtum (a, b, pa, pb) distribution if its probability mass function is
\Pr(U=u)=\begin{cases}pa&ifu=a;\\[8pt] pb&ifu=b\\[8pt] \dfrac{1-pa-pb}{b-a-1}&ifa<u<b\\[8pt] 0&otherwise\end{cases}
Suppose a random variable
X
\mu
c2
U
U
X
a
b
pa
pb
\begin{align} a&=\left\lceil\mu-
1 | |
2 |
\left\lceil\sqrt{1+12c2\mu2}\right\rceil\right\rceil\\[8pt] b&=\left\lfloor\mu+
1 | |
2 |
\left\lceil\sqrt{1+12c2\mu2}\right\rceil\right\rfloor\\[8pt] pb&=
(c2+1)\mu2-A-(a2-A)(2\mu-a-b)/(a-b) | |
a2+b2-2A |
\\[8pt] pa&=
2\mu-a-b | |
a-b |
+pb\\[12pt] whereA&=
2a2+a+2ab-b+2b2 | |
6 |
. \end{align}
There does not exist a Van Houtum distribution for every combination of
\mu
c2
\mu
\lfloor\mu\rfloor
\lceil\mu\rceil
c2\mu2\geq(\mu-\lfloor\mu\rfloor)(1+\mu-\lceil\mu\rceil)2+(\mu-\lfloor\mu\rfloor)2(1+\mu-\lceil\mu\rceil).