See main article: 1828 United States presidential election.
Election Name: | 1828 United States presidential election in Alabama |
Country: | Alabama |
Type: | presidential |
Ongoing: | no |
Previous Election: | 1824 United States presidential election in Alabama |
Previous Year: | 1824 |
Next Election: | 1832 United States presidential election in Alabama |
Next Year: | 1832 |
Election Date: | October 31 – December 2, 1828 |
Image1: | Andrew Jackson.jpg |
Nominee1: | Andrew Jackson |
Party1: | Democratic Party (United States) |
Home State1: | Tennessee |
Running Mate1: | John C. Calhoun |
Electoral Vote1: | 5 |
Popular Vote1: | 16,736 |
Percentage1: | 89.89% |
Nominee2: | John Quincy Adams |
Party2: | National Republican Party (United States) |
Home State2: | Massachusetts |
Running Mate2: | Richard Rush |
Electoral Vote2: | 0 |
Popular Vote2: | 1,878 |
Percentage2: | 10.09% |
Map Size: | 250px |
President | |
Before Election: | John Quincy Adams |
Before Party: | Democratic-Republican Party |
After Election: | Andrew Jackson |
After Party: | Democratic Party (United States) |
The 1828 United States presidential election in Alabama took place between October 31 and December 2, 1828, as part of the 1828 United States presidential election. Voters chose five representatives, or electors, to the Electoral College, who voted for President and Vice President.
Alabama voted for the Democratic candidate, Andrew Jackson, over the National Republican candidate, John Quincy Adams. Jackson won Alabama by a margin of 79.80%.
1828 United States presidential election in Alabama[1] | |||||
---|---|---|---|---|---|
Party | Candidate | Votes | Percentage | Electoral votes | |
Democratic | Andrew Jackson | 16,736 | 89.89% | 5 | |
National Republican | John Quincy Adams (incumbent) | 1,878 | 10.09% | 0 | |
N/A | Other | 4 | 0.02% | 0 | |
Totals | 18,618 | 100.00% | 5 | ||