1828 United States presidential election in Alabama explained

See main article: 1828 United States presidential election.

Election Name:1828 United States presidential election in Alabama
Country:Alabama
Type:presidential
Ongoing:no
Previous Election:1824 United States presidential election in Alabama
Previous Year:1824
Next Election:1832 United States presidential election in Alabama
Next Year:1832
Election Date:October 31 – December 2, 1828
Image1:Andrew Jackson.jpg
Nominee1:Andrew Jackson
Party1:Democratic Party (United States)
Home State1:Tennessee
Running Mate1:John C. Calhoun
Electoral Vote1:5
Popular Vote1:16,736
Percentage1:89.89%
Nominee2:John Quincy Adams
Party2:National Republican Party (United States)
Home State2:Massachusetts
Running Mate2:Richard Rush
Electoral Vote2:0
Popular Vote2:1,878
Percentage2:10.09%
Map Size:250px
President
Before Election:John Quincy Adams
Before Party:Democratic-Republican Party
After Election:Andrew Jackson
After Party:Democratic Party (United States)

The 1828 United States presidential election in Alabama took place between October 31 and December 2, 1828, as part of the 1828 United States presidential election. Voters chose five representatives, or electors, to the Electoral College, who voted for President and Vice President.

Alabama voted for the Democratic candidate, Andrew Jackson, over the National Republican candidate, John Quincy Adams. Jackson won Alabama by a margin of 79.80%.

Results

1828 United States presidential election in Alabama[1]
PartyCandidateVotesPercentageElectoral votes
DemocraticAndrew Jackson16,73689.89%5
National RepublicanJohn Quincy Adams (incumbent)1,87810.09%0
N/AOther40.02%0
Totals18,618100.00%5

See also

Notes and References

  1. Web site: 1828 Presidential General Election Results - Alabama. U.S. Election Atlas. 28 February 2013.