See main article: 1824 United States presidential election.
| Election Name: | 1824 United States presidential election in Alabama |
| Country: | Alabama |
| Type: | presidential |
| Ongoing: | no |
| Previous Election: | 1820 United States presidential election in Alabama |
| Previous Year: | 1820 |
| Next Election: | 1828 United States presidential election in Alabama |
| Next Year: | 1828 |
| Election Date: | October 26 – December 2, 1824 |
| Image1: | Andrew Jackson.jpg |
| Nominee1: | Andrew Jackson |
| Party1: | Democratic-Republican Party |
| Home State1: | Tennessee |
| Running Mate1: | John C. Calhoun |
| Electoral Vote1: | 5 |
| Popular Vote1: | 9,429 |
| Percentage1: | 69.32% |
| Nominee2: | John Quincy Adams |
| Party2: | Democratic-Republican Party |
| Home State2: | Massachusetts |
| Running Mate2: | John C. Calhoun |
| Electoral Vote2: | 0 |
| Popular Vote2: | 2,422 |
| Percentage2: | 17.80% |
| Image3: | WilliamHCrawford.jpg |
| Nominee3: | William H. Crawford |
| Party3: | Democratic-Republican Party |
| Home State3: | Georgia |
| Running Mate3: | Nathaniel Macon |
| Electoral Vote3: | 0 |
| Popular Vote3: | 1,656 |
| Percentage3: | 12.17% |
| Map Size: | 250px |
| President | |
| Before Election: | James Monroe |
| Before Party: | Democratic-Republican Party |
| After Election: | John Quincy Adams |
| After Party: | Democratic-Republican Party |
The 1824 United States presidential election in Alabama took place between October 26 and December 2, 1824, as part of the 1824 presidential election. Voters chose five representatives, or electors, to the Electoral College, who voted for President and Vice President.
During this election, the Democratic-Republican Party was the only major national party, and four different candidates from this party sought the Presidency. Alabama voted for Andrew Jackson over John Quincy Adams, William H. Crawford and Henry Clay. Jackson won Alabama by a margin of 51.52%. This was the first time since achieving statehood in 1819 that Alabama backed the losing candidate in a presidential election.
| 1824 United States presidential election in Alabama[1] | |||||
|---|---|---|---|---|---|
| Party | Candidate | Votes | Percentage | Electoral votes | |
| Democratic-Republican | Andrew Jackson | 9,429 | 69.32% | 5 | |
| Democratic-Republican | John Quincy Adams | 2,422 | 17.80% | 0 | |
| Democratic-Republican | William H. Crawford | 1,656 | 12.17% | 0 | |
| Democratic-Republican | Henry Clay | 96 | 0.71% | 0 | |
| Totals | 13,423 | 100.00% | 5 | ||