1902 United States elections explained

Year:1902
Type:Midterm elections
Election Day:November 4
Incumbent President:Theodore Roosevelt (Republican)
Next Congress:58th
Senate Seats Contested:30 of 90 seats[1]
Senate Control:Republican hold
Senate Net Change:Democratic +4[2]
Senate Map Caption:Results of the elections:

House Seats Contested:All 386 voting seats
House Control:Republican hold
House Net Change:Democratic +25
Governor Seats Contested:27
Governor Net Change:None
Governor Map Caption:1902 gubernatorial elections results


The 1902 United States elections elected the 58th United States Congress, and occurred in the middle of Republican President Theodore Roosevelt's first term, during the Fourth Party System. Roosevelt had become president on September 14, 1901, upon the assassination of his predecessor, William McKinley. Republicans retained a majority in both chambers of Congress, while the Populist Party and Silver Republican Party disappeared from Congress.

Reapportionment added twenty nine seats to the House. Democrats picked up several seats in the newly enlarged House, while Republicans made lesser gains. Republicans continued to control the chamber with a slightly diminished majority.[3]

In the Senate, Republicans and Democrats each picked up one seat, while the Populist Party lost both its seats. Republicans maintained a commanding majority in the chamber.[4]

See also

Primary sources

Notes and References

  1. Not counting special elections.
  2. Congressional seat gain figures only reflect the results of the regularly-scheduled elections, and do not take special elections into account.
  3. Web site: Party Divisions of the House of Representatives. United States House of Representatives. 25 June 2014.
  4. Web site: Party Division in the Senate, 1789-Present. United States Senate. 25 June 2014.