1801 United States Senate special election in Pennsylvania explained

Election Name:1801 U.S. Senate special election in Pennsylvania
Type:presidential
Ongoing:no
Previous Election:1801 United States Senate election in Pennsylvania
Previous Year:Feb. 1801
Next Election:1806 United States Senate election in Pennsylvania
Next Year:1806
Election Date:December 17, 1801
Votes For Election:111 Members of the Pennsylvania legislature
Needed Votes:Majority of
Image1:File:GeoLogan.jpg
Nominee1:George Logan
Party1:Democratic-Republican Party
Electoral Vote1:68
Percentage1:61.26%
Nominee2:Joseph Hiester
Party2:Democratic-Republican Party
Electoral Vote2:30
Percentage2:27.03%
Senator
Before Election:Peter Muhlenberg
Before Party:Democratic-Republican Party (United States)
After Election:George Logan
After Party:Democratic-Republican Party (United States)

The 1801 United States Senate special election in Pennsylvania was held on December 17, 1801. George Logan was elected by the Pennsylvania General Assembly to the United States Senate.[1]

Background

The Democratic-Republican Peter Muhlenberg was elected to the United States Senate by the Pennsylvania General Assembly, consisting of the House of Representatives and the Senate, in February 1801. Sen. Muhlenberg resigned on June 30, 1801, after being appointed supervisor of revenue for Pennsylvania by President Thomas Jefferson.[2]

Results

Following the resignation of Sen. Peter Muhlenberg, the Pennsylvania General Assembly convened on December 17, 1801, to elect a new Senator to fill the vacancy. The results of the vote of both houses combined are as follows:

|-|-bgcolor="#EEEEEE"| colspan="3" align="right" | Totals| align="right" | 111| align="right" | 100.00%|}

External links

Notes and References

  1. Web site: U.S. Senate Election - 17 December 1801. Wilkes University. 28 September 2013.
  2. Web site: MUHLENBERG, Peter, (1746 - 1807). Biographical Directory of the United States Congress. 28 September 2013.