| Election Name: | 1988 United States Senate election in Wyoming |
| Country: | Wyoming |
| Type: | presidential |
| Ongoing: | no |
| Previous Election: | 1982 United States Senate election in Wyoming |
| Previous Year: | 1982 |
| Next Election: | 1994 United States Senate election in Wyoming |
| Next Year: | 1994 |
| Election Date: | November 8, 1988 |
| Image1: | File:malcolmwallop.JPG |
| Nominee1: | Malcolm Wallop |
| Party1: | Republican Party (United States) |
| Popular Vote1: | 91,143 |
| Percentage1: | 50.37% |
| Nominee2: | John Vinich |
| Party2: | Democratic Party (United States) |
| Popular Vote2: | 89,821 |
| Percentage2: | 49.63% |
| Map Size: | 250px |
| U.S. Senator | |
| Before Election: | Malcolm Wallop |
| Before Party: | Republican Party (United States) |
| After Election: | Malcolm Wallop |
| After Party: | Republican Party (United States) |
The 1988 United States Senate election in Wyoming was held on November 8, 1988. Incumbent Republican Senator Malcolm Wallop ran for re-election to a third term. He was opposed by Democratic State Senator John Vinich in the general election. Despite Wallop's past strong performances in 1976 and 1982, and the overwhelming Republican majority in Wyoming in the presidential election, Wallop faced a surprisingly competitive race. He ended up defeating Vinich by less than 1%, by a margin of just 1,322 votes. To date, this remains the strongest performance by a Democratic U.S. Senate nominee in Wyoming since 1970, the last time a Democrat won a Senate election in the state. This is also the closest U.S. Senate race in Wyoming history.