1986 United States Senate election in Florida explained

Election Name:1986 United States Senate election in Florida
Country:Florida
Type:presidential
Ongoing:no
Previous Election:1980 United States Senate election in Florida
Previous Year:1980
Next Election:1992 United States Senate election in Florida
Next Year:1992
Election Date:November 4, 1986
Image1:Portrait of Governor Bob Graham (cropped).jpg
Nominee1:Bob Graham
Party1:Democratic Party (United States)
Popular Vote1:1,877,543
Percentage1:54.74%
Nominee2:Paula Hawkins
Party2:Republican Party (United States)
Popular Vote2:1,552,376
Percentage2:45.26%
Map Size:300px
U.S. Senator
Before Election:Paula Hawkins
Before Party:Republican Party (United States)
After Election:Bob Graham
After Party:Democratic Party (United States)

The 1986 United States Senate election in Florida took place on November 4, 1986, alongside other elections to the United States Senate in other states as well as elections to the United States House of Representatives and various state and local elections. Incumbent Republican U.S. Senator Paula Hawkins decided to run for re-election to second term, but was defeated by Democrat Bob Graham, the popular incumbent Governor of Florida. To date, this was the last time an incumbent from Florida's Class 3 Senate seat lost re-election.[1]

Graham received 83% of the black vote.

Democratic primary

Candidates

Results

Republican primary

Candidates

Results

General election

Candidates

Results

See also

Works cited

Notes and References

  1. Web site: Statistics of the Congressional Election of November 4, 1986 . Clerk of the House of Representatives . 8.