1958 United States Senate election in Florida explained

Election Name:1958 United States Senate election in Florida
Country:Florida
Type:presidential
Ongoing:no
Previous Election:1952 United States Senate election in Florida
Previous Year:1952
Next Election:1964 United States Senate election in Florida
Next Year:1964
Election Date:November 4, 1958
Image1:Spessard Holland.JPG
Nominee1:Spessard Holland
Party1:Democratic Party (United States)
Popular Vote1:386,113
Percentage1:71.23%
Nominee2:Leland Hyzer
Party2:Republican Party (United States)
Popular Vote2:155,956
Percentage2:28.77%
Map Size:280px
U.S. Senator
Before Election:Spessard Holland
Before Party:Democratic Party (US)
After Election:Spessard Holland
After Party:Democratic Party (US)
Flag Year:1900

The 1958 United States Senate election in Florida was held on November 4, 1958.

After fending off a primary challenge from former senator Claude Pepper, the incumbent senator Spessard Holland was easily re-elected to a third term in office.

Democratic primary

Candidates

Campaign

The incumbent senator Holland, a firm conservative, was challenged by former senator Claude Pepper, who had been unseated in 1950. Holland had played a role in recruiting George A. Smathers to run against the liberal Pepper in that election. The two served as colleagues in the Senate from 1947 to 1951.[1]

Results

Republican primary

Candidates

Results

Hyzer was unopposed for the Republican nomination.

General election

Results

See also

Notes and References

  1. News: Egerton . John . November 29, 1981 . COURTLY CHAMPION OF AMERICA'S ELDERLY . The New York Times . August 15, 2019.