Uniformly convex space explained

In mathematics, uniformly convex spaces (or uniformly rotund spaces) are common examples of reflexive Banach spaces. The concept of uniform convexity was first introduced by James A. Clarkson in 1936.

Definition

A uniformly convex space is a normed vector space such that, for every

0<\varepsilon\leq2

there is some

\delta>0

such that for any two vectors with

\|x\|=1

and

\|y\|=1,

the condition

\|x-y\|\geq\varepsilon

implies that:

\left\|x+y
2

\right\|\leq1-\delta.

Intuitively, the center of a line segment inside the unit ball must lie deep inside the unit ball unless the segment is short.

Properties

X

is uniformly convex if and only if for every

0<\varepsilon\le2

there is some

\delta>0

so that, for any two vectors

x

and

y

in the closed unit ball (i.e.

\|x\|\le1

and

\|y\|\le1

) with

\|x-y\|\ge\varepsilon

, one has
\left\|{x+y
2
}\right\| \le 1-\delta (note that, given

\varepsilon

, the corresponding value of

\delta

could be smaller than the one provided by the original weaker definition).The "if" part is trivial. Conversely, assume now that

X

is uniformly convex and that

x,y

are as in the statement, for some fixed

0<\varepsilon\le2

. Let

\delta1\le1

be the value of

\delta

corresponding to
\varepsilon
3

in the definition of uniform convexity. We will show that
\left\|x+y
2

\right\|\le1-\delta

, with
\delta=min\left\{\varepsilon,
6
\delta1
3

\right\}

.

If

\|x\|\le1-2\delta

then
\left\|x+y\right\|\le
2
1(1-2\delta)+
2
1
2

=1-\delta

and the claim is proved. A similar argument applies for the case

\|y\|\le1-2\delta

, so we can assume that

1-2\delta<\|x\|,\|y\|\le1

. In this case, since
\delta\le1
3

, both vectors are nonzero, so we can let
x'=x
\|x\|

and
y'=y
\|y\|

. We have

\|x'-x\|=1-\|x\|\le2\delta

and similarly

\|y'-y\|\le2\delta

, so

x'

and

y'

belong to the unit sphere and have distance
\|x'-y'\|\ge\|x-y\|-4\delta\ge\varepsilon-4\varepsilon=
6
\varepsilon
3

. Hence, by our choice of

\delta1

, we have
\left\|x'+y'
2

\right\|\le1-\delta1

. It follows that
\left\|x+y\right\|\le\left\|
2
x'+y'\right\|+
2
\|x'-x\|+\|y'-y\|
2

\le1-\delta1+2\delta\le1-

\delta1
3

\le1-\delta

and the claim is proved.

\{fn\}

infty
n=1

is a sequence in a uniformly convex Banach space that converges weakly to

f

and satisfies

\|fn\|\to\|f\|,

then

fn

converges strongly to

f

, that is,

\|fn-f\|\to0

.

X

is uniformly convex if and only if its dual

X*

is uniformly smooth.

\|x+y\|<\|x\|+\|y\|

whenever

x,y

are linearly independent, while the uniform convexity requires this inequality to be true uniformly.

Examples

(1<p<infty)

are uniformly convex.

Linfty

is not uniformly convex.

See also

References

General references

Notes and References

  1. Book: Narici . Lawrence . Beckenstein . Edward . Topological Vector Spaces . 2011 . CRC Press . Boca Raton, FL . 978-1-58488-866-6 . 524, Example 16.2.3 . 2nd.