Tsirelson space explained

In mathematics, especially in functional analysis, the Tsirelson space is the first example of a Banach space in which neither an  p space nor a c0 space can be embedded. The Tsirelson space is reflexive.

It was introduced by B. S. Tsirelson in 1974. The same year, Figiel and Johnson published a related article where they used the notation T for the dual of Tsirelson's example. Today, the letter T is the standard notation[1] for the dual of the original example, while the original Tsirelson example is denoted by T*. In T* or in T, no subspace is isomorphic, as Banach space, to an  p space, 1 ≤ p < ∞, or to c0.

All classical Banach spaces known to, spaces of continuous functions, of differentiable functions or of integrable functions, and all the Banach spaces used in functional analysis for the next forty years, contain some  p or c0. Also, new attempts in the early '70s[2] to promote a geometric theory of Banach spaces led to ask [3] whether or not every infinite-dimensional Banach space has a subspace isomorphic to some  p or to c0. Moreover, it was shownby Baudier, Lancien, and Schlumprecht that p and c0 do not even coarsely embed into T*.

The radically new Tsirelson construction is at the root of several further developments in Banach space theory: the arbitrarily distortable space of Thomas Schlumprecht, on which depend Gowers' solution to Banach's hyperplane problem[4] and the Odell - Schlumprecht solution to the distortion problem. Also, several results of Argyros et al.[5] are based on ordinal refinements of the Tsirelson construction, culminating with the solution by Argyros - Haydon of the scalar plus compact problem.[6]

Tsirelson's construction

On the vector space ℓ of bounded scalar sequences, let Pn denote the linear operator which sets to zero all coordinates xj of x for which j ≤ n.

A finite sequence

\{xn\}

N
n=1
of vectors in ℓ is called block-disjoint if there are natural numbers

style\{an,bn\}

N
n=1
so that

a1\leqb1<a2\leqb2<\leqbN

, and so that

(xn)i=0

when

i<an

or

i>bn

, for each n from 1 to N. The unit ball &thinsp;B&thinsp; of ℓ is compact and metrizable for the topology of pointwise convergence (the product topology). The crucial step in the Tsirelson construction is to let K be the smallest pointwise closed subset of &thinsp;B&thinsp; satisfying the following two properties:[7]

a. For every integer &thinsp;j&thinsp; in N, the unit vector ej and all multiples

λej

, for |&lambda;| ≤ 1, belong to K.

b. For any integer N ≥ 1, if

style(x1,\ldots,xN)

is a block-disjoint sequence in K, then

style{{1\over2}PN(x1++xN)}

belongs to K.This set K satisfies the following stability property:

c. Together with every element x of K, the set K contains all vectors y in ℓ such that |y| ≤ |x| (for the pointwise comparison).It is then shown that K is actually a subset of c0, the Banach subspace of ℓ consisting of scalar sequences tending to zero at infinity. This is done by proving that

d: for every element x in K, there exists an integer n such that 2&thinsp;Pn(x) belongs to K,and iterating this fact. Since K is pointwise compact and contained in c0, it is weakly compact in c0. Let V be the closed convex hull of K in c0. It is also a weakly compact set in c0. It is shown that V satisfies b, c and d.

The Tsirelson space T* is the Banach space whose unit ball is V. The unit vector basis is an unconditional basis for T* and T* is reflexive. Therefore, T* does not contain an isomorphic copy of c0. The other  p spaces, 1 ≤ p < ∞, are ruled out by condition b.

Properties

The Tsirelson space is reflexive and finitely universal, which means that for some constant, the space contains -isomorphic copies of every finite-dimensional normed space, namely, for every finite-dimensional normed space, there exists a subspace of the Tsirelson space with multiplicative Banach - Mazur distance to less than . Actually, every finitely universal Banach space contains almost-isometric copies of every finite-dimensional normed space,[8] meaning that can be replaced by for every . Also, every infinite-dimensional subspace of is finitely universal. On the other hand, every infinite-dimensional subspace in the dual of contains almost isometric copies of

1
\scriptstyle{\ell
n}
, the -dimensional ℓ1-space, for all .

The Tsirelson space is distortable, but it is not known whether it is arbitrarily distortable.

The space is a minimal Banach space.[9] This means that every infinite-dimensional Banach subspace of contains a further subspace isomorphic to . Prior to the construction of, the only known examples of minimal spaces were  p and 0. The dual space is not minimal.[10]

The space is polynomially reflexive.

Derived spaces

The symmetric Tsirelson space S(T) is polynomially reflexive and it has the approximation property. As with T, it is reflexive and no  p space can be embedded into it.

Since it is symmetric, it can be defined even on an uncountable supporting set, giving an example of non-separable polynomially reflexive Banach space.

See also

References

External links

Notes and References

  1. see for example, p. 8;, p. 95; The Handbook of the Geometry of Banach Spaces, vol. 1, p. 276; vol. 2, p. 1060, 1649.
  2. see, .
  3. The question is formulated explicitly in,, on last page., p. 95, say that this question was "a long standing open problem going back to Banach's book", but the question does not appear in Banach's book. However, Banach compares the linear dimension of  p to that of other classical spaces, a somewhat similar question.
  4. The question is whether every infinite-dimensional Banach space is isomorphic to its hyperplanes. The negative solution is in Gowers, "A solution to Banach's hyperplane problem". Bull. London Math. Soc. 26 (1994), 523-530.
  5. for example, S. Argyros and V. Felouzis, "Interpolating Hereditarily Indecomposable Banach spaces", Journal Amer. Math. Soc., 13 (2000), 243–294; S. Argyros and A. Tolias, "Methods in the theory of hereditarily indecomposable Banach spaces", Mem. Amer. Math. Soc. 170 (2004), no. 806.
  6. S. Argyros and R. Haydon constructed a Banach space on which every bounded operator is a compact perturbation of a scalar multiple of the identity, in "A hereditarily indecomposable L-space that solves the scalar-plus-compact problem", Acta Mathematica (2011) 206: 1-54.
  7. conditions b, c, d here are conditions (3), (2) and (4) respectively in, and a is a modified form of condition (1) from the same article.
  8. this is because for every, and &epsilon;, there exists such that every -isomorph of ℓ contains a -isomorph of ℓn, by James' blocking technique (see Lemma 2.2 in Robert C. James "Uniformly Non-Square Banach Spaces", Annals of Mathematics, Vol. 80, 1964, pp. 542-550), and because every finite-dimensional normed space -embeds in ℓ when is large enough.
  9. see, p. 54.
  10. see, p. 56.