In algebraic geometry, the trisectrix of Maclaurin is a cubic plane curve notable for its trisectrix property, meaning it can be used to trisect an angle. It can be defined as locus of the point of intersection of two lines, each rotating at a uniform rate about separate points, so that the ratio of the rates of rotation is 1:3 and the lines initially coincide with the line between the two points. A generalization of this construction is called a sectrix of Maclaurin. The curve is named after Colin Maclaurin who investigated the curve in 1742.
Let two lines rotate about the points
P=(0,0)
P1=(a,0)
P
\theta
P1
3\theta
Q
Q
2\theta
{r\over\sin3\theta}={a\over\sin2\theta}
r=a
\sin3\theta | |
\sin2\theta |
={a\over2}
4\cos2\theta-1 | |
\cos\theta |
={a\over2}(4\cos\theta-\sec\theta).
In Cartesian coordinates the equation of this curve is
2x(x2+y2)=a(3x2-y2).
If the origin is moved to (a, 0) then a derivation similar to that given above shows that the equation of the curve in polar coordinates becomes
r=2a\cos{\theta\over3},
Given an angle
\phi
(a,0)
x
\phi
x
\phi/3
The curve has an x-intercept at
3a\over2
x={-{a\over2}}
(a,{\pm{1\over\sqrt{3}}a})
The trisectrix of Maclaurin can be defined from conic sections in three ways. Specifically:
2x=a(3x2-y2).
(x+a)2+y2=a2
and the line
x={a\over2}
y2=2a(x-\tfrac{3}{2}a).
In addition:
(a,0)