Tensor product of representations explained
In mathematics, the tensor product of representations is a tensor product of vector spaces underlying representations together with the factor-wise group action on the product. This construction, together with the Clebsch–Gordan procedure, can be used to generate additional irreducible representations if one already knows a few.
Definition
Group representations
If
are
linear representations of a group
, then their tensor product is the tensor product of
vector spaces
with the linear action of
uniquely determined by the condition that
g ⋅ (v1 ⊗ v2)=(g ⋅ v1) ⊗ (g ⋅ v2)
for all
and
. Although not every element of
is expressible in the form
, the universal property of the tensor product guarantees that this action is well-defined.
In the language of homomorphisms, if the actions of
on
and
are given by homomorphisms
\Pi1:G\to\operatorname{GL}(V1)
and
\Pi2:G\to\operatorname{GL}(V2)
, then the tensor product representation is given by the homomorphism
\Pi1 ⊗ \Pi2:G\to\operatorname{GL}(V1 ⊗ V2)
given by
\Pi1 ⊗ \Pi2(g)=\Pi1(g) ⊗ \Pi2(g)
,where
is the tensor product of linear maps.
[1]
is an
algebraic representation of
G; i.e., each element of
G acts as an algebra automorphism.
Lie algebra representations
If
and
are representations of a
Lie algebra
, then the tensor product of these representations is the map
\pi1 ⊗ \pi2:akg\to\operatorname{End}(V1 ⊗ V2)
given by
[2] \pi1 ⊗ \pi2(X)=\pi1(X) ⊗ I+I ⊗ \pi2(X)
, where
is the
identity endomorphism. This is called the Kronecker sum, defined in Matrix addition#Kronecker sum and Kronecker product#Properties.The motivation for the use of the Kronecker sum in this definition comes from the case in which
and
come from representations
and
of a
Lie group
. In that case, a simple computation shows that the Lie algebra representation associated to
is given by the preceding formula.
[3] Quantum groups
For quantum groups, the coproduct is no longer co-commutative. As a result, the natural permutation map
is no longer an isomorphism of modules. However, the permutation map remains an isomorphism of vector spaces.
Action on linear maps
If
and
are representations of a group
, let
\operatorname{Hom}(V1,V2)
denote the
space of all
linear maps from
to
. Then
\operatorname{Hom}(V1,V2)
can be given the structure of a representation by defining
for all
A\in\operatorname{Hom}(V,W)
. Now, there is a natural isomorphism
\operatorname{Hom}(V,W)\congV* ⊗ W
as vector spaces; this vector space
isomorphism is in fact an isomorphism of representations.
[4]
consists of
G-linear maps; i.e.,
\operatorname{Hom}G(V,W)=\operatorname{Hom}(V,W)G.
Let
denote the
endomorphism algebra of
V and let
A denote the subalgebra of
consisting of symmetric tensors. The
main theorem of invariant theory states that
A is
semisimple when the
characteristic of the base
field is zero.
Clebsch–Gordan theory
The general problem
The tensor product of two irreducible representations
of a group or Lie algebra is usually not irreducible. It is therefore of interest to attempt to decompose
into irreducible pieces. This decomposition problem is known as the Clebsch–Gordan problem.
The SU(2) case
The prototypical example of this problem is the case of the rotation group SO(3)—or its double cover, the special unitary group SU(2). The irreducible representations of SU(2) are described by a parameter
, whose possible values are
(The dimension of the representation is then
.) Let us take two parameters
and
with
. Then the tensor product representation
then decomposes as follows:
[5] V\ell ⊗ Vm\congV\ell+m ⊕ V\ell+m-1 ⊕ … ⊕ V\ell-m+1 ⊕ V\ell-m.
Consider, as an example, the tensor product of the four-dimensional representation
and the three-dimensional representation
. The tensor product representation
has dimension 12 and decomposes as
V3/2 ⊗ V1\congV5/2 ⊕ V3/2 ⊕ V1/2
,where the representations on the right-hand side have dimension 6, 4, and 2, respectively. We may summarize this result arithmetically as
.
The SU(3) case
See main article: Clebsch–Gordan coefficients for SU(3). In the case of the group SU(3), all the irreducible representations can be generated from the standard 3-dimensional representation and its dual, as follows. To generate the representation with label
, one takes the tensor product of
copies of the standard representation and
copies of the dual of the standard representation, and then takes the invariant subspace generated by the tensor product of the highest weight vectors.
[6] In contrast to the situation for SU(2), in the Clebsch–Gordan decomposition for SU(3), a given irreducible representation
may occur more than once in the decomposition of
.
Tensor power
As with vector spaces, one can define the th tensor power of a representation to be the vector space
with the action given above.
The symmetric and alternating square
Over a field of characteristic zero, the symmetric and alternating squares are subrepresentations of the second tensor power. They can be used to define the Frobenius–Schur indicator, which indicates whether a given irreducible character is real, complex, or quaternionic. They are examples of Schur functors.They are defined as follows.
Let be a vector space. Define an endomorphism of
as follows:
\begin{align}
T:V ⊗ V&\longrightarrowV ⊗ V\\
v ⊗ w&\longmapstow ⊗ v.
\end{align}
[7] It is an involution (its own inverse), and so is an automorphism of
.
Define two subsets of the second tensor power of,
These are the symmetric square of ,
, and the
alternating square of ,
, respectively. The symmetric and alternating squares are also known as the
symmetric part and
antisymmetric part of the tensor product.
Properties
The second tensor power of a linear representation of a group decomposes as the direct sum of the symmetric and alternating squares:
as representations. In particular, both are subrepresentations of the second tensor power. In the language of modules over the group ring, the symmetric and alternating squares are
-submodules of
.
, then the symmetric square has a basis
\{vi ⊗ vj+vj ⊗ vi\mid1\leqi\leqj\leqn\}
and the alternating square has a basis
\{vi ⊗ vj-vj ⊗ vi\mid1\leqi<j\leqn\}
. Accordingly,
\begin{align}
\dim\operatorname{Sym}2(V)&=
,\\
\dim\operatorname{Alt}2(V)&=
.
\end{align}
Let
be the
character of
. Then we can calculate the characters of the symmetric and alternating squares as follows: for all in,
\begin{align}
| 2(V)}(g) |
\chi | |
| \operatorname{Sym |
&=
(\chi(g)2+\chi(g2)),\\
| 2(V)}(g) |
\chi | |
| \operatorname{Alt |
&=
(\chi(g)2-\chi(g2)).
\end{align}
The symmetric and exterior powers
and
th exterior power
, which are
subspaces of the
th tensor power (see those pages for more detail on this construction). They are also subrepresentations, but higher tensor powers no longer decompose as their direct sum.
. Precisely, as an
-module
V ⊗ \simeqoplusλMλ ⊗ Sλ(V)
where
is an irreducible representation of the
symmetric group
corresponding to a partition
of
n (in decreasing order),
is the image of the
Young symmetrizer
.
The mapping
is a
functor called the
Schur functor. It generalizes the constructions of symmetric and exterior powers:
S(n)(V)=\operatorname{Sym}nV,S(1,(V)=\wedgenV.
In particular, as a G-module, the above simplifies to
where
. Moreover, the multiplicity
may be computed by the
Frobenius formula (or the
hook length formula). For example, take
. Then there are exactly three partitions:
and, as it turns out,
. Hence,
V ⊗ \simeq\operatorname{Sym}3Voplus\wedge3VoplusS(2,(V) ⊕ .
Tensor products involving Schur functors
Let
denote the
Schur functor defined according to a partition
. Then there is the following decomposition:
SλV ⊗ S\muV\simeqoplus\nu(S\nu
where the multiplicities
are given by the
Littlewood–Richardson rule.
Given finite-dimensional vector spaces V, W, the Schur functors Sλ give the decomposition
\operatorname{Sym}(W* ⊗ V)\simeqoplusλSλ(W*) ⊗ Sλ(V)
The left-hand side can be identified with the
ring of polynomial functions on Hom(
V, 
W ),
k[Hom(''V'', ''W'' )] =
k[''V''<sup> *</sup> ⊗ ''W'' ], and so the above also gives the decomposition of
k[Hom(''V'', ''W'' )].
Tensor products representations as representations of product groups
Let G, H be two groups and let
and
be representations of
G and
H, respectively. Then we can let the
direct product group
act on the tensor product space
by the formula
(g,h) ⋅ (v ⊗ w)=\pi(g)v ⊗ \rho(h)w.
Even if
, we can still perform this construction, so that the tensor product of two representations of
could, alternatively, be viewed as a representation of
rather than a representation of
. It is therefore important to clarify whether the tensor product of two representations of
is being viewed as a representation of
or as a representation of
.
In contrast to the Clebsch–Gordan problem discussed above, the tensor product of two irreducible representations of
is irreducible when viewed as a representation of the product group
.
See also
References
-
- Book: James, Gordon Douglas. Representations and characters of groups. 2001. Cambridge University Press. Liebeck, Martin W.. 978-0521003926. 2nd. Cambridge, UK. 52220683.
- Claudio Procesi (2007) Lie Groups: an approach through invariants and representation, Springer, .
- Book: Serre, Jean-Pierre. Linear Representations of Finite Groups. registration. Springer-Verlag. 1977. 978-0-387-90190-9. 2202385.
Notes and References
- Section 4.3.2
- Definition 4.19
- Proposition 4.18
- pp. 433–434
- Theorem C.1
- Proof of Proposition 6.17
- Precisely, we have
V x V\toV ⊗ V,(v,w)\mapstov ⊗ w
, which is bilinear and thus descends to the linear map