Tensor product of representations explained

In mathematics, the tensor product of representations is a tensor product of vector spaces underlying representations together with the factor-wise group action on the product. This construction, together with the Clebsch–Gordan procedure, can be used to generate additional irreducible representations if one already knows a few.

Definition

Group representations

If

V1,V2

are linear representations of a group

G

, then their tensor product is the tensor product of vector spaces

V1V2

with the linear action of

G

uniquely determined by the condition that

g(v1v2)=(gv1)(gv2)

for all

v1\inV1

and

v2\inV2

. Although not every element of

V1V2

is expressible in the form

v1 ⊗ v2

, the universal property of the tensor product guarantees that this action is well-defined.

In the language of homomorphisms, if the actions of

G

on

V1

and

V2

are given by homomorphisms

\Pi1:G\to\operatorname{GL}(V1)

and

\Pi2:G\to\operatorname{GL}(V2)

, then the tensor product representation is given by the homomorphism

\Pi1 ⊗ \Pi2:G\to\operatorname{GL}(V1V2)

given by

\Pi1 ⊗ \Pi2(g)=\Pi1(g)\Pi2(g)

,where

\Pi1(g)\Pi2(g)

is the tensor product of linear maps.[1]

T(V)

is an algebraic representation of G; i.e., each element of G acts as an algebra automorphism.

Lie algebra representations

If

(V1,\pi1)

and

(V2,\pi2)

are representations of a Lie algebra

akg

, then the tensor product of these representations is the map

\pi1 ⊗ \pi2:akg\to\operatorname{End}(V1V2)

given by[2]

\pi1 ⊗ \pi2(X)=\pi1(X)I+I\pi2(X)

, where

I

is the identity endomorphism. This is called the Kronecker sum, defined in Matrix addition#Kronecker sum and Kronecker product#Properties.The motivation for the use of the Kronecker sum in this definition comes from the case in which

\pi1

and

\pi2

come from representations

\Pi1

and

\Pi2

of a Lie group

G

. In that case, a simple computation shows that the Lie algebra representation associated to

\Pi1 ⊗ \Pi2

is given by the preceding formula.[3]

Quantum groups

For quantum groups, the coproduct is no longer co-commutative. As a result, the natural permutation map

VWWV

is no longer an isomorphism of modules. However, the permutation map remains an isomorphism of vector spaces.

Action on linear maps

If

(V1,\Pi1)

and

(V2,\Pi2)

are representations of a group

G

, let

\operatorname{Hom}(V1,V2)

denote the space of all linear maps from

V1

to

V2

. Then

\operatorname{Hom}(V1,V2)

can be given the structure of a representation by defining

gA=\Pi2(g)A\Pi

-1
1(g)
for all

A\in\operatorname{Hom}(V,W)

. Now, there is a natural isomorphism

\operatorname{Hom}(V,W)\congV*W

as vector spaces; this vector space isomorphism is in fact an isomorphism of representations.[4]

\operatorname{Hom}(V,W)G

consists of G-linear maps; i.e.,

\operatorname{Hom}G(V,W)=\operatorname{Hom}(V,W)G.

Let

E=\operatorname{End}(V)

denote the endomorphism algebra of V and let A denote the subalgebra of

E

consisting of symmetric tensors. The main theorem of invariant theory states that A is semisimple when the characteristic of the base field is zero.

Clebsch–Gordan theory

The general problem

The tensor product of two irreducible representations

V1,V2

of a group or Lie algebra is usually not irreducible. It is therefore of interest to attempt to decompose

V1 ⊗ V2

into irreducible pieces. This decomposition problem is known as the Clebsch–Gordan problem.

The SU(2) case

The prototypical example of this problem is the case of the rotation group SO(3)—or its double cover, the special unitary group SU(2). The irreducible representations of SU(2) are described by a parameter

\ell

, whose possible values are

\ell=0,1/2,1,3/2,\ldots.

(The dimension of the representation is then

2\ell+1

.) Let us take two parameters

\ell

and

m

with

\ell\geqm

. Then the tensor product representation

V\ellVm

then decomposes as follows:[5]

V\ellVm\congV\ell+mV\ell+m-1 ⊕ … ⊕ V\ell-m+1V\ell-m.

Consider, as an example, the tensor product of the four-dimensional representation

V3/2

and the three-dimensional representation

V1

. The tensor product representation

V3/2V1

has dimension 12 and decomposes as

V3/2V1\congV5/2V3/2V1/2

,where the representations on the right-hand side have dimension 6, 4, and 2, respectively. We may summarize this result arithmetically as

4 x 3=6+4+2

.

The SU(3) case

See main article: Clebsch–Gordan coefficients for SU(3). In the case of the group SU(3), all the irreducible representations can be generated from the standard 3-dimensional representation and its dual, as follows. To generate the representation with label

(m1,m2)

, one takes the tensor product of

m1

copies of the standard representation and

m2

copies of the dual of the standard representation, and then takes the invariant subspace generated by the tensor product of the highest weight vectors.[6]

In contrast to the situation for SU(2), in the Clebsch–Gordan decomposition for SU(3), a given irreducible representation

W

may occur more than once in the decomposition of

UV

.

Tensor power

As with vector spaces, one can define the th tensor power of a representation to be the vector space

V

with the action given above.

The symmetric and alternating square

Over a field of characteristic zero, the symmetric and alternating squares are subrepresentations of the second tensor power. They can be used to define the Frobenius–Schur indicator, which indicates whether a given irreducible character is real, complex, or quaternionic. They are examples of Schur functors.They are defined as follows.

Let be a vector space. Define an endomorphism of

VV

as follows:

\begin{align} T:VV&\longrightarrowVV\\ vw&\longmapstowv. \end{align}

[7]

It is an involution (its own inverse), and so is an automorphism of

VV

.

Define two subsets of the second tensor power of,

\begin \operatorname^2(V) &:= \ \\ \operatorname^2(V) &:= \\end

These are the symmetric square of ,

V\odotV

, and the alternating square of ,

V\wedgeV

, respectively. The symmetric and alternating squares are also known as the symmetric part and antisymmetric part of the tensor product.

Properties

The second tensor power of a linear representation of a group decomposes as the direct sum of the symmetric and alternating squares:

V^ = V \otimes V \cong \operatorname^2(V) \oplus \operatorname^2(V)

as representations. In particular, both are subrepresentations of the second tensor power. In the language of modules over the group ring, the symmetric and alternating squares are

C[G]

-submodules of

VV

.

\{v1,v2,\ldots,vn\}

, then the symmetric square has a basis

\{vivj+vjvi\mid1\leqi\leqj\leqn\}

and the alternating square has a basis

\{vivj-vjvi\mid1\leqi<j\leqn\}

. Accordingly,

\begin{align} \dim\operatorname{Sym}2(V)&=

\dimV(\dimV+1)
2

,\\ \dim\operatorname{Alt}2(V)&=

\dimV(\dimV-1)
2

. \end{align}

Let

\chi:G\toC

be the character of

V

. Then we can calculate the characters of the symmetric and alternating squares as follows: for all in,

\begin{align}

2(V)}(g)
\chi
\operatorname{Sym

&=

1
2

(\chi(g)2+\chi(g2)),\\

2(V)}(g)
\chi
\operatorname{Alt

&=

1
2

(\chi(g)2-\chi(g2)). \end{align}

The symmetric and exterior powers

\operatorname{Sym}n(V)

and th exterior power

Λn(V)

, which are subspaces of the th tensor power (see those pages for more detail on this construction). They are also subrepresentations, but higher tensor powers no longer decompose as their direct sum.

G=\operatorname{GL}(V)

. Precisely, as an

Sn x G

-module

V\simeqoplusλMλSλ(V)

where

Mλ

is an irreducible representation of the symmetric group

Sn

corresponding to a partition

λ

of n (in decreasing order),

Sλ(V)

is the image of the Young symmetrizer

cλ:V\toV

.

The mapping

V\mapstoSλ(V)

is a functor called the Schur functor. It generalizes the constructions of symmetric and exterior powers:

S(n)(V)=\operatorname{Sym}nV,S(1,(V)=\wedgenV.

In particular, as a G-module, the above simplifies to

V\simeqoplusλSλ

mλ
(V)
where

mλ=\dimMλ

. Moreover, the multiplicity

mλ

may be computed by the Frobenius formula (or the hook length formula). For example, take

n=3

. Then there are exactly three partitions:

3=3=2+1=1+1+1

and, as it turns out,

m(3)=m(1,=1,m(2,=2

. Hence,

V\simeq\operatorname{Sym}3Voplus\wedge3VoplusS(2,(V).

Tensor products involving Schur functors

Let

Sλ

denote the Schur functor defined according to a partition

λ

. Then there is the following decomposition:

SλVS\muV\simeqoplus\nu(S\nu

Nλ
V)
where the multiplicities

Nλ

are given by the Littlewood–Richardson rule.

Given finite-dimensional vector spaces V, W, the Schur functors Sλ give the decomposition

\operatorname{Sym}(W*V)\simeqoplusλSλ(W*)Sλ(V)

The left-hand side can be identified with the ring of polynomial functions on Hom(V,&thinsp;W&hairsp;), k[Hom(''V'',&thinsp;''W''&hairsp;)] = k[''V''<sup>&thinsp;*</sup>&thinsp;⊗&thinsp;''W''&hairsp;], and so the above also gives the decomposition of k[Hom(''V'',&thinsp;''W''&hairsp;)].

Tensor products representations as representations of product groups

Let G, H be two groups and let

(\pi,V)

and

(\rho,W)

be representations of G and H, respectively. Then we can let the direct product group

G x H

act on the tensor product space

VW

by the formula

(g,h)(vw)=\pi(g)v\rho(h)w.

Even if

G=H

, we can still perform this construction, so that the tensor product of two representations of

G

could, alternatively, be viewed as a representation of

G x G

rather than a representation of

G

. It is therefore important to clarify whether the tensor product of two representations of

G

is being viewed as a representation of

G

or as a representation of

G x G

.

In contrast to the Clebsch–Gordan problem discussed above, the tensor product of two irreducible representations of

G

is irreducible when viewed as a representation of the product group

G x G

.

See also

References

Notes and References

  1. Section 4.3.2
  2. Definition 4.19
  3. Proposition 4.18
  4. pp. 433–434
  5. Theorem C.1
  6. Proof of Proposition 6.17
  7. Precisely, we have

    V x V\toVV,(v,w)\mapstovw

    , which is bilinear and thus descends to the linear map

    VV\toVV.