In fluid dynamics, Taylor scraping flow is a type of two-dimensional corner flow occurring when one of the wall is sliding over the other with constant velocity, named after G. I. Taylor.[1] [2] [3]
Consider a plane wall located at
\theta=0
(r,\theta)
U
\alpha
x
r=0
U
r=0
Taylor noticed that the inertial terms are negligible as long as the region of interest is within
r\ll\nu/U
Re=Ur/\nu\ll1
U=10cm/s
r\ll0.4cm
\nabla4\psi=0, ur=
1 | |
r |
\partial\psi | |
\partial\theta |
, u\theta=-
\partial\psi | |
\partialr |
where
v=(ur,u\theta)
\psi
\begin{align} r>0, \theta=0:& ur=-U, u\theta=0\\ r>0, \theta=\alpha:& ur=0, u\theta=0 \end{align}
Attempting a separable solution of the form
\psi=Urf(\theta)
fiv+2f''+f=0
with boundary conditions
f(0)=0, f'(0)=-1, f(\alpha)=0, f'(\alpha)=0
The solution is[5]
f(\theta)=
1 | |
\alpha2-\sin2\alpha |
[\theta\sin\alpha\sin(\alpha-\theta)-\alpha(\alpha-\theta)\sin\theta]
Therefore, the velocity field is
\begin{align} ur&=
U | |
\alpha2-\sin2\alpha |
\{\sin\alpha[\sin(\alpha-\theta)-\theta\cos(\alpha-\theta)]+\alpha[\sin\theta-(\alpha-\theta)\cos\theta]\}\\ u\theta&=-
U | |
\alpha2-\sin2\alpha |
[\theta\sin\alpha\sin(\alpha-\theta)-\alpha(\alpha-\theta)\sin\theta] \end{align}
Pressure can be obtained through integration of the momentum equation
\nablap=\mu\nabla2v, p(r,infty)=pinfty
which gives,
p(r,\theta)-pinfty=
2\muU | |
r |
\alpha\sin\theta+\sin\alpha\sin(\alpha-\theta) | |
\alpha2-\sin2\alpha |
The tangential stress and the normal stress on the scraper due to pressure and viscous forces are
\sigmat=
2\muU | |
r |
\sin\alpha-\alpha\cos\alpha | |
\alpha2-\sin2\alpha |
, \sigman=
2\muU | |
r |
\alpha\sin\alpha | |
\alpha2-\sin2\alpha |
The same scraper stress if resolved according to Cartesian coordinates (parallel and perpendicular to the lower plate i.e.
\sigmax=-\sigmat\cos\alpha+\sigman\sin\alpha, \sigmay=\sigmat\sin\alpha+\sigman\cos\alpha
\sigmax=
2\muU | |
r |
\alpha-\sin\alpha\cos\alpha | |
\alpha2-\sin2\alpha |
, \sigmay=
2\muU | |
r |
\sin2\alpha | |
\alpha2-\sin2\alpha |
As noted earlier, all the stresses become infinite at
r=0
The stress in the direction parallel to the lower wall decreases as
\alpha
\sigmax=2\muU/r
\alpha=\pi
\sigmay
0<\alpha<\pi
\pi/2<\alpha<\pi
\sigmay
\sigman
\alpha
180\circ
\alpha
\sigmay/\sigmax
Since scraping applications are important for non-Newtonian fluid (for example, scraping paint, nail polish, cream, butter, honey, etc.,), it is essential to consider this case. The analysis was carried out by J. Riedler and Wilhelm Schneider in 1983 and they were able to obtain self-similar solutions for power-law fluids satisfying the relation for the apparent viscosity[6]
\mu=
m | \left( | ||||
|
1 | |
r |
\partial\psi | |
\partial\theta |
\right)\right]2+\left[
1 | |
r2 |
\partial2\psi | |
\partial\theta2 |
-r
\partial | \left( | |
\partialr |
1 | |
r |
\partial | |
\partialr |
\right)\right]2\right\}(n-1)/2
where
mz
n
\psi=Ur\left\{\left[1-
lJ1(\theta) | |
lJ1(\alpha) |
\right]\sin\theta+
lJ2(\theta) | |
lJ1(\alpha) |
\cos\theta\right\}
where
\begin{align} lJ1&=sgn(F)
\theta | |
\int | |
0 |
|F|1/n\cosxdx,\\ lJ2&=sgn(F)
\theta | |
\int | |
0 |
|F|1/n\sinxdx \end{align}
and
\begin{align} F=\sin(\sqrt{n(2-n)}x-C) ifn<2,\\ F=\sqrt{x-C} ifn=2,\\ F=\sinh(\sqrt{n(n-2)}x-C) ifn>2 \end{align}
where
C
lJ2(\alpha)=0
n=1