See also: Suchy Dwór, Lower Silesian Voivodeship.
| Suchy Dwór | |
| Settlement Type: | Village |
| Total Type: | |
| Subdivision Type: | Country |
| Subdivision Type1: | Voivodeship |
| Subdivision Name1: | Pomeranian |
| Subdivision Type2: | County |
| Subdivision Name2: | Puck |
| Subdivision Type3: | Gmina |
| Subdivision Name3: | Kosakowo |
| Coordinates: | 54.5756°N 18.4647°W |
| Pushpin Map: | Poland |
| Pushpin Label Position: | right |
| Population Total: | 888 |
Suchy Dwór is a village in the administrative district of Gmina Kosakowo, within Puck County, Pomeranian Voivodeship, in northern Poland.[1] It lies approximately 2km (01miles) south-west of Kosakowo, 150NaN0 south of Puck, and 260NaN0 north-west of the regional capital Gdańsk.
For details of the history of the region, see History of Pomerania.