In mathematics, the Strömberg wavelet is a certain orthonormal wavelet discovered by Jan-Olov Strömberg and presented in a paper published in 1983.[1] Even though the Haar wavelet was earlier known to be an orthonormal wavelet, Strömberg wavelet was the first smooth orthonormal wavelet to be discovered. The term wavelet had not been coined at the time of publishing the discovery of Strömberg wavelet and Strömberg's motivation was to find an orthonormal basis for the Hardy spaces.[1]
Let m be any non-negative integer. Let V be any discrete subset of the set R of real numbers. Then V splits R into non-overlapping intervals. For any r in V, let Ir denote the interval determined by V with r as the left endpoint. Let P(m)(V) denote the set of all functions f(t) over R satisfying the following conditions:
If A0 = ∪ ∪ and A1 = A0 ∪ then the Strömberg wavelet of order m is a function Sm(t) satisfying the following conditions:[1]
Sm(t)\inP(m)(A1).
\VertSm(t)\Vert=1
\intR\vertSm(t)\vert2dt=1.
Sm(t)
P(m)(A0)
\intRSm(t)f(t)dt=0
f(t)\inP(m)(A0).
The following are some of the properties of the set P(m)(V):
The following result establishes the Strömberg wavelet as an orthonormal wavelet.[1]
Let Sm be the Strömberg wavelet of order m. Then the following set
\left\{2j/2Sm(2jt-k):j,kintegers\right\}
In the special case of Strömberg wavelets of order 0, the following facts may be observed:
As already observed, the Strömberg wavelet S0(t) is completely determined by the set . Using the defining properties of the Strömbeg wavelet, exact expressions for elements of this set can be computed and they are given below.[2]
S0(k)=S0(1)(\sqrt{3}-2)k-1
k=1,2,3,\ldots
S0(\tfrac{1}{2})=-S0(1)\left(\sqrt{3}+\tfrac{1}{2}\right)
S0(0)=S0(1)(2\sqrt{3}-2)
S0(-\tfrac{k}{2})=S0(1)(2\sqrt{3}-2)(\sqrt{3}-2)k
k=1,2,3,\ldots
The Strömberg wavelet of order 0 has the following properties.[2]
S0(-k/2)=(10-6\sqrt{3})S0(k)
k=1,2,3,\ldots.