Stable polynomial explained

In the context of the characteristic polynomial of a differential equation or difference equation, a polynomial is said to be stable if either:

The first condition provides stability for continuous-time linear systems, and the second case relates to stabilityof discrete-time linear systems. A polynomial with the first property is called at times a Hurwitz polynomial and with the second property a Schur polynomial. Stable polynomials arise in control theory and in mathematical theoryof differential and difference equations. A linear, time-invariant system (see LTI system theory) is said to be BIBO stable if every bounded input produces bounded output. A linear system is BIBO stable if its characteristic polynomial is stable. The denominator is required to be Hurwitz stable if the system is in continuous-time and Schur stable if it is in discrete-time. In practice, stability is determined by applying any one of several stability criteria.

Properties

Q(z)=(z-1)dP\left({{z+1}\over{z-1}}\right)

z\mapsto{{z+1}\over{z-1}}

which maps the left half-plane to the open unit disc: P is Schur stable if and only if Q is Hurwitz stable and

P(1)0

. For higher degree polynomials the extra computation involved in this mapping can be avoided by testing the Schur stability by the Schur-Cohn test, the Jury test or the Bistritz test.

f(z)=a0+a1z+ … +anzn

with (real) coefficients such that

an>an-1>>a0>0,

is Schur stable.

Examples

4z3+3z2+2z+1

is Schur stable because it satisfies the sufficient condition;

z10

is Schur stable (because all its roots equal 0) but it does not satisfy the sufficient condition;

z2-z-2

is not Hurwitz stable (its roots are −1 and 2) because it violates the necessary condition;

z2+3z+2

is Hurwitz stable (its roots are −1 and −2).

z4+z3+z2+z+1

(with positive coefficients) is neither Hurwitz stable nor Schur stable. Its roots are the four primitive fifth roots of unity

zk=\cos\left({{2\pik}\over5}\right)+i\sin\left({{2\pik}\over5}\right),k=1,\ldots,4.

Note here that

\cos({{2\pi}/5})={{\sqrt{5}-1}\over4}>0.

It is a "boundary case" for Schur stability because its roots lie on the unit circle. The example also shows that the necessary (positivity) conditions stated above for Hurwitz stability are not sufficient.

Stable matrices

Just as stable polynomials are crucial for assessing the stability of systems described by polynomials, stability matrices play a vital role in evaluating the stability of systems represented by matrices.

Hurwitz matrix

See main article: Hurwitz matrix. A square matrix A is called a Hurwitz matrix if every eigenvalue of A has strictly negative real part.

Schur matrix

Schur matrices is an analogue of the Hurwitz matrices for discrete-time systems. A matrix A is a Schur (stable) matrix if its eigenvalues are located in the open unit disk in the complex plane.

See also

External links

Notes and References

  1. Garloff. Jürgen. Wagner. David G.. 1996. Hadamard Products of Stable Polynomials Are Stable. Journal of Mathematical Analysis and Applications. en. 202. 3. 797–809. 10.1006/jmaa.1996.0348. free.