λ
T
T-λI
Here,
I
By the closed graph theorem,
λ
T-λI:V\toV
V
The study of spectra and related properties is known as spectral theory, which has numerous applications, most notably the mathematical formulation of quantum mechanics.
The spectrum of an operator on a finite-dimensional vector space is precisely the set of eigenvalues. However an operator on an infinite-dimensional space may have additional elements in its spectrum, and may have no eigenvalues. For example, consider the right shift operator R on the Hilbert space ℓ2,
(x1,x2,...)\mapsto(0,x1,x2,...).
The notion of spectrum extends to unbounded (i.e. not necessarily bounded) operators. A complex number λ is said to be in the spectrum of an unbounded operator
T:X\toX
D(T)\subseteqX
(T-λI)-1:X\toD(T)
X.
(T-λI)-1
The space of bounded linear operators B(X) on a Banach space X is an example of a unital Banach algebra. Since the definition of the spectrum does not mention any properties of B(X) except those that any such algebra has, the notion of a spectrum may be generalised to this context by using the same definition verbatim.
Let
T
X
C
I
X
T
λ\inC
T-λI
Since
T-λI
λ
T-λI
The spectrum of a given operator
T
\sigma(T)
\rho(T)=C\setminus\sigma(T)
\rho(T)
T
If
λ
T
T-λI
(T-λI)-1
T-λI
λ
For example, consider the Hilbert space
\ell2(\Z)
v=(\ldots,v-2,v-1,v0,v1,v2,\ldots)
T
u=T(v)
ui=vi-1
i
T(v)=λv
vi
\vertλ\vert=1
\vertλ\vert ≠ 1
T-λI
|λ|=1
u
ui=1/(|i|+1)
\ell2(\Z)
v
\ell2(\Z)
(T-I)v=u
vi-1=ui+vi
i
The spectrum of a bounded operator T is always a closed, bounded subset of the complex plane.
If the spectrum were empty, then the resolvent function
R(λ)=(T-λI)-1, λ\in\Complex,
would be defined everywhere on the complex plane and bounded. But it can be shown that the resolvent function R is holomorphic on its domain. By the vector-valued version of Liouville's theorem, this function is constant, thus everywhere zero as it is zero at infinity. This would be a contradiction.
The boundedness of the spectrum follows from the Neumann series expansion in λ; the spectrum σ(T) is bounded by ||T||. A similar result shows the closedness of the spectrum.
The bound ||T|| on the spectrum can be refined somewhat. The spectral radius, r(T), of T is the radius of the smallest circle in the complex plane which is centered at the origin and contains the spectrum σ(T) inside of it, i.e.
r(T)=\sup\{|λ|:λ\in\sigma(T)\}.
The spectral radius formula says[2] that for any element
T
r(T)=\limn\left\|Tn\right\|1/n.
One can extend the definition of spectrum to unbounded operators on a Banach space X. These operators which are no longer elements in the Banach algebra B(X).
Let X be a Banach space and
T:D(T)\toX
D(T)\subseteqX
T
T-λI:D(T)\toX
has a bounded everywhere-defined inverse, i.e. if there exists a bounded operator
S:X → D(T)
such that
S(T-λI)=ID(T),(T-λI)S=IX.
A complex number λ is then in the spectrum if λ is not in the resolvent set.
For λ to be in the resolvent (i.e. not in the spectrum), just like in the bounded case,
T-λI
By the closed graph theorem, boundedness of
(T-λI)-1
T-λI
The spectrum of an unbounded operator is in general a closed, possibly empty, subset of the complex plane.If the operator T is not closed, then
\sigma(T)=\Complex
A bounded operator T on a Banach space is invertible, i.e. has a bounded inverse, if and only if T is bounded below, i.e.
\|Tx\|\geqc\|x\|,
c>0,
λ\in\sigma(T)
T-λI
T-λI
T-λI
λ\in\sigma(T)
T-λI
\sigmacp(T)
T-λI
\sigmares(T)
Note that the approximate point spectrum and residual spectrum are not necessarily disjoint[3] (however, the point spectrum and the residual spectrum are).
The following subsections provide more details on the three parts of σ(T) sketched above.
If an operator is not injective (so there is some nonzero x with T(x) = 0), then it is clearly not invertible. So if λ is an eigenvalue of T, one necessarily has λ ∈ σ(T). The set of eigenvalues of T is also called the point spectrum of T, denoted by σp(T). Some authors refer to the closure of the point spectrum as the pure point spectrum
\sigmapp(T)=\overline{\sigmap(T)}
\sigmapp(T):=\sigmap(T).
More generally, by the bounded inverse theorem, T is not invertible if it is not bounded below; that is, if there is no c > 0 such that ||Tx|| ≥ c||x|| for all . So the spectrum includes the set of approximate eigenvalues, which are those λ such that is not bounded below; equivalently, it is the set of λ for which there is a sequence of unit vectors x1, x2, ... for which
\limn\|Txn-λxn\|=0
The set of approximate eigenvalues is known as the approximate point spectrum, denoted by
\sigmaap(T)
It is easy to see that the eigenvalues lie in the approximate point spectrum.
For example, consider the right shift R on
l2(\Z)
R:ej\mapstoej+1, j\in\Z,
where
(ej)j\in\N
l2(\Z)
|λ|=1
1 | |
\sqrt{n |
one can see that ||xn|| = 1 for all n, but
\|Rxn-λxn\|=\sqrt{
2 | |
n |
Since R is a unitary operator, its spectrum lies on the unit circle. Therefore, the approximate point spectrum of R is its entire spectrum.
This conclusion is also true for a more general class of operators.A unitary operator is normal. By the spectral theorem, a bounded operator on a Hilbert space H is normal if and only if it is equivalent (after identification of H with an
L2
The discrete spectrum is defined as the set of normal eigenvalues or, equivalently, as the set of isolated points of the spectrum such that the corresponding Riesz projector is of finite rank. As such, the discrete spectrum is a strict subset of the point spectrum, i.e.,
\sigmad(T)\subset\sigmap(T).
The set of all λ for which
T-λI
\sigmac(T)
\sigmac(T)=\sigmaap(T)\setminus(\sigmar(T)\cup\sigmap(T))
For example,
A:l2(\N)\tol2(\N)
ej\mapstoej/j
j\in\N
Ran(A)\subsetneql2(\N)
cj\in\Complex
The set of
λ\in\Complex
T-λI
\sigmacp(T)
The set of
λ\in\Complex
T-λI
\sigmar(T)
\sigmar(T)=\sigmacp(T)\setminus\sigmap(T).
An operator may be injective, even bounded below, but still not invertible. The right shift on
l2(N)
R:l2(N)\tol2(N)
R:ej\mapstoej+1,j\in\N
e1\not\inRan(R)
Ran(R)
l2(N)
e1\notin\overline{Ran(R)}
The peripheral spectrum of an operator is defined as the set of points in its spectrum which have modulus equal to its spectral radius.[4]
There are five similar definitions of the essential spectrum of closed densely defined linear operator
A:X\toX
\sigmaess,1(A)\subset \sigmaess,2(A)\subset \sigmaess,3(A)\subset \sigmaess,4(A)\subset \sigmaess,5(A)\subset \sigma(A).
All these spectra
\sigmaess,k(A), 1\lek\le5
\sigmaess,1(A)
λ
A-λI
λ=0\in\sigmaess,1(A)
A:l2(\N)\tol2(\N)
A:ej\mapstoej/j,~j\in\N
l2(\N)
λ=0\in\sigmaess,1(N)
N:l2(\N)\tol2(\N)
N:v\mapsto0
v\inl2(\N)
\sigmaess,2(A)
λ
A-λI
(xj)j\in\N
\Vertxj\Vert=1
(xj)j\in\N
λ=0\in\sigmaess,2(B)
B:l2(\N)\tol2(\N)
B:ej\mapstoej/2
ej\mapsto0
λ=0\not\in\sigmaess,1(B)
\sigmaess,3(A)
λ
A-λI
λ=0\in\sigmaess,3(J)
J:l2(\N)\tol2(\N)
J:ej\mapstoe2j
λ=0\not\in\sigmaess,2(J)
\sigmaess,4(A)
λ
A-λI
B0(X)
λ=0\in\sigmaess,4(R)
R:l2(\N)\tol2(\N)
R:l2(\N)\tol2(\N)
R:ej\mapstoej+1
j\in\N
λ=0\not\in\sigmaess,3(R)
\sigmaess,5(A)
\sigmaess,1(A)
\Complex\setminus\sigmaess,1(A)
\Complex\setminus\sigma(A)
\sigma(A)\setminus\sigmad(A)
T:l2(\Z)\tol2(\Z)
T:ej\mapstoej-1
j\ne0
T:e0\mapsto0
\VertT\Vert=1
\sigma(T)\subset\overline{D1}
z\in\Complex
|z|=1
T-zI
\partialD1\subset\sigmaess,1(T)
z\in\Complex
|z|<1
T-zI
z\in\sigma(T)
z\not\in\sigmaess,k(T)
1\lek\le4
\sigmaess,k(T)=\partialD1
1\lek\le4
\Complex\setminus\sigmaess,1(T)
\{z\in\Complex:|z|>1\}
\{z\in\Complex:|z|<1\}
\{|z|<1\}
\sigmaess,5(T)=\sigmaess,1(T)\cup\{z\in\Complex:|z|<1\}=\{z\in\Complex:|z|\le1\}
H=-\Delta- | Z |
|x| |
Z>0
D(H)=H1(\R3)
\sigmad(H)
\sigmap(H)
\sigmacont(H)=[0,+infty)
\sigmaess(H)=[0,+infty)
Let X be a Banach space and
T:X\toX
D(T)\subsetX
T*:X*\toX*
\sigma(T*)=\overline{\sigma(T)}:=\{z\in\Complex:\bar{z}\in\sigma(T)\}.
We also get
\sigmap(T)\subset\overline{\sigmar(T*)\cup\sigmap(T*)}
T-λI
Ran(T*-\bar{λ}I)
Ran(T*-\bar{λ}I)
Furthermore, if X is reflexive, we have
\overline{\sigmar
*)}\subset\sigma | |
(T | |
p |
(T)
If T is a compact operator, or, more generally, an inessential operator, then it can be shown that the spectrum is countable, that zero is the only possible accumulation point, and that any nonzero λ in the spectrum is an eigenvalue.
A bounded operator
A:X\toX
\lVertAn\rVert1/n\to0
n\toinfty
\sigma(A)=\{0\}.
An example of such an operator is
A:l2(\N)\tol2(\N)
ej\mapstoej+1/2j
j\in\N
If X is a Hilbert space and T is a self-adjoint operator (or, more generally, a normal operator), then a remarkable result known as the spectral theorem gives an analogue of the diagonalisation theorem for normal finite-dimensional operators (Hermitian matrices, for example).
For self-adjoint operators, one can use spectral measures to define a decomposition of the spectrum into absolutely continuous, pure point, and singular parts.
The definitions of the resolvent and spectrum can be extended to any continuous linear operator
T
X
R
C
TC
\rho(T)
λ\inC
TC-λI
XC
\sigma(T)=C\setminus\rho(T)
The real spectrum of a continuous linear operator
T
X
\sigmaR(T)
λ\inR
T-λI
X
\sigma(T)\capR=\sigmaR(T)
Let B be a complex Banach algebra containing a unit e. Then we define the spectrum σ(x) (or more explicitly σB(x)) of an element x of B to be the set of those complex numbers λ for which λe − x is not invertible in B. This extends the definition for bounded linear operators B(X) on a Banach space X, since B(X) is a unital Banach algebra.