Soviet Union at the Hopman Cup explained

Type:Hopman
Soviet Union
First Year:1990
Years Played:2
Best:Quarterfinals (1990, 1991)
Player Wins:Andrei Chesnokov (1–3)
Singles Wins:Andrei Chesnokov (1–1)
Doubles Wins:Andrei Chesnokov (0–2)
Natalia Zvereva (0–2)
Best Doubles:Natalia Zvereva &<br/>Andrei Chesnokov (0–2)
Most Years:Natalia Zvereva (2)
Andrei Chesnokov (2)

The Soviet Union is a nation that competed at two consecutive Hopman Cup tournaments and first competed in the 2nd Hopman Cup in 1990. The Soviet Union never won a tie and as such never passed the quarterfinal stage of the tournament.

Since the dissolution of the Soviet Union at the end of 1991, four of the fifteen independent states formed from the former Soviet Union have competed in the Hopman Cup. These are: Kazakhstan, Russia, Ukraine and Uzbekistan. Additionally, the Commonwealth of Independent States also entered a team into the 1992 event.[1]

Players

This is a list of players who have played for the Soviet Union in the Hopman Cup.

NameTotal W–LSingles W–LDoubles W–LFirst year playedNo. of years played
1–3 1–1 0–2 2
0–4 0–2 0–2 2

Results

YearCompetitionLocationOpponentScoreResult
1990QuarterfinalsAustralia0–3Lost
1991QuarterfinalsBurswood Dome, Perth Yugoslavia1–2Lost

See also

CIS at the Hopman Cup
Kazakhstan at the Hopman Cup
Russia at the Hopman Cup
Ukraine at the Hopman Cup
Uzbekistan at the Hopman Cup

Notes and References

  1. Web site: Nations Records . www.hopmancup.com . 10 Oct 2011 . dead . https://web.archive.org/web/20110905233823/http://hopmancup.com/Results/Nations-Records . 2011-09-05 .