Singular integral explained

In mathematics, singular integrals are central to harmonic analysis and are intimately connected with the study of partial differential equations. Broadly speaking a singular integral is an integral operator

T(f)(x)=\intK(x,y)f(y)dy,

whose kernel function K : Rn×Rn → R is singular along the diagonal x = y. Specifically, the singularity is such that |K(xy)| is of size |x - y|-n asymptotically as |x - y| → 0. Since such integrals may not in general be absolutely integrable, a rigorous definition must define them as the limit of the integral over |y - x| > ε as ε → 0, but in practice this is a technicality. Usually further assumptions are required to obtain results such as their boundedness on Lp(Rn).

The Hilbert transform

See main article: Hilbert transform.

The archetypal singular integral operator is the Hilbert transform H. It is given by convolution against the kernel K(x) = 1/(πx) for x in R. More precisely,

H(f)(x)=

1
\pi

\lim\varepsilon\int|x-y|>\varepsilon

1
x-y

f(y)dy.

The most straightforward higher dimension analogues of these are the Riesz transforms, which replace K(x) = 1/x with

Ki(x)=

xi
|x|n+1

where i = 1, ..., n and

xi

is the i-th component of x in Rn. All of these operators are bounded on Lp and satisfy weak-type (1, 1) estimates.[1]

Singular integrals of convolution type

See main article: Singular integral operators of convolution type. A singular integral of convolution type is an operator T defined by convolution with a kernel K that is locally integrable on Rn\, in the sense that

Suppose that the kernel satisfies:

  1. The size condition on the Fourier transform of K

\hat{K}\inLinfty(Rn)

  1. The smoothness condition: for some C > 0,

\supy\int|x|>2|y||K(x-y)-K(x)|dx\leqC.

Then it can be shown that T is bounded on Lp(Rn) and satisfies a weak-type (1, 1) estimate.

Property 1. is needed to ensure that convolution with the tempered distribution p.v. K given by the principal value integral

\operatorname{p.v.}K[\phi]=

\lim
\epsilon\to0+

\int|x|>\epsilon\phi(x)K(x)dx

is a well-defined Fourier multiplier on L2. Neither of the properties 1. or 2. is necessarily easy to verify, and a variety of sufficient conditions exist. Typically in applications, one also has a cancellation condition
\int
R1<|x|<R2

K(x)dx=0,\forallR1,R2>0

which is quite easy to check. It is automatic, for instance, if K is an odd function. If, in addition, one assumes 2. and the following size condition

\supR>0\intR<|x|<2R|K(x)|dx\leqC,

then it can be shown that 1. follows.

The smoothness condition 2. is also often difficult to check in principle, the following sufficient condition of a kernel K can be used:

K\inC1(Rn\setminus\{0\})

|\nablaK(x)|\le

C
|x|n+1
Observe that these conditions are satisfied for the Hilbert and Riesz transforms, so this result is an extension of those result.

Singular integrals of non-convolution type

These are even more general operators. However, since our assumptions are so weak, it is not necessarily the case that these operators are bounded on Lp.

Calderón–Zygmund kernels

A function is said to be a CalderónZygmund kernel if it satisfies the following conditions for some constants C > 0 and δ > 0.

  1. |K(x,y)|\leq

    C
    |x-y|n

  2. |K(x,y)-K(x',y)|\leq

    C|x-x'|\delta
    l(|x-y|+|x'-y|r)n+\delta

    whenever|x-x'|\leq

    1
    2

    maxl(|x-y|,|x'-y|r)

  3. |K(x,y)-K(x,y')|\leq

    C|y-y'|\delta
    l(|x-y|+|x-y'|r)n+\delta

    whenever|y-y'|\leq

    1
    2

    maxl(|x-y'|,|x-y|r)

Singular integrals of non-convolution type

T is said to be a singular integral operator of non-convolution type associated to the Calderón - Zygmund kernel K if

\intg(x)T(f)(x)dx=\iintg(x)K(x,y)f(y)dydx,

whenever f and g are smooth and have disjoint support. Such operators need not be bounded on Lp

Calderón - Zygmund operators

A singular integral of non-convolution type T associated to a Calderón - Zygmund kernel K is called a Calderón - Zygmund operator when it is bounded on L2, that is, there is a C > 0 such that

\|T(f)\|
L2

\leq

C\|f\|
L2

,

for all smooth compactly supported ƒ.

It can be proved that such operators are, in fact, also bounded on all Lp with 1 < p < ∞.

The T(b) theorem

The T(b) theorem provides sufficient conditions for a singular integral operator to be a Calderón–Zygmund operator, that is for a singular integral operator associated to a Calderón–Zygmund kernel to be bounded on L2. In order to state the result we must first define some terms.

A normalised bump is a smooth function φ on Rn supported in a ball of radius 1 and centred at the origin such that |α φ(x)| ≤ 1, for all multi-indices |α| ≤ n + 2. Denote by τx(φ)(y) = φ(y − x) and φr(x) = rnφ(x/r) for all x in Rn and r > 0. An operator is said to be weakly bounded if there is a constant C such that

\left|\int

x(\varphi
Tl(\tau
r)r)(y)
x(\psi
\tau
r)(y)

dy\right|\leqCr-n

for all normalised bumps φ and ψ. A function is said to be accretive if there is a constant c > 0 such that Re(b)(x) ≥ c for all x in R. Denote by Mb the operator given by multiplication by a function b.

The T(b) theorem states that a singular integral operator T associated to a Calderón–Zygmund kernel is bounded on L2 if it satisfies all of the following three conditions for some bounded accretive functions b1 and b2:[2]

  1. M
    b2
    TM
    b1
    is weakly bounded;
  2. T(b1)

    is in BMO;
  3. t(b
    T
    2),
    is in BMO, where Tt is the transpose operator of T.

See also

Notes

  1. News: Stein . Elias . Harmonic Analysis . Princeton University Press. 1993 .
  2. News: David . Journé . Semmes . Opérateurs de Calderón - Zygmund, fonctions para-accrétives et interpolation . Revista Matemática Iberoamericana . 1 . 1 - 56. fr . 1985 .

References

External links